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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#103485 | #5668. Cell Nuclei Detection | cardinal_city# | AC ✓ | 1982ms | 15020kb | C++17 | 3.4kb | 2023-05-06 05:03:20 | 2023-05-06 05:03:41 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef vector<int> vi;
typedef pair<int, int> pii;
#define all(x) (x).begin(), (x).end()
#define sz(x) (int)x.size();
#define rep(i,j,k) for (int i = j; i < (k); i++)
#define in(mp, v) (mp.find(v) != mp.end())
#define smx(a, b) a = max(a, b)
#define smn(a, b) a = min(a, b)
#define pb push_back
#define endl '\n'
const ll MOD = 1e9 + 7;
const ld EPS = 1e-9;
bool dfs(int a, int L, vector<vi> &g, vi& btoa, vi& A, vi &B) {
if(A[a] != L) return 0;
A[a] = -1;
for(int b : g[a]) {
if(B[b] == L+1) {
B[b] = 0;
if(btoa[b] == -1 || dfs(btoa[b], L+1, g, btoa, A,B)) {
return btoa[b] = a, 1;
}
}
}
return 0;
}
int hopcroftKarp(vector<vi> &g, vi& btoa) {
int res = 0;
vi A(g.size()), B(btoa.size()), cur, next;
for(;;) {
fill(all(A), 0);
fill(all(B), 0);
cur.clear();
for (int a : btoa) if(a != -1) A[a] = -1;
for(int a = 0; a < g.size(); a++) {
if(A[a] == 0) cur.pb(a);
}
for(int lay = 1;; lay++) {
bool islast = 0;
next.clear();
for(int a : cur) for(int b : g[a]) {
if(btoa[b] == -1) {
B[b] = lay;
islast = 1;
} else if(btoa[b] != a && !B[b]) {
B[b] = lay;
next.pb(btoa[b]);
}
}
if(islast) break;
if(next.empty()) return res;
for (int a : next) A[a] = lay;
cur.swap(next);
}
for(int a = 0; a < g.size(); a++) {
res += dfs(a, 0, g, btoa, A, B);
}
}
}
struct rect {
int x1, y1, x2, y2, id;
};
rect inter(rect a, rect b) {
return {max(a.x1, b.x1), max(a.y1, b.y1), min(a.x2, b.x2), min(a.y2, b.y2)};
}
int area(rect a) {
if(a.y2 <= a.y1 || a.x2 <= a.x1) return 0;
return (a.y2 - a.y1) * (a.x2 - a.x1);
}
void print(rect a) {
cout << a.x1 << " " << a.y1 << " " << a.x2 << " " << a.y2 << endl;
}
void solve() {
int n,m; cin >> n >> m;
map<pii, vector<rect>> gt;
for(int i = 0; i < n; i++) {
rect a;
cin >> a.x1 >> a.y1 >> a.x2 >> a.y2;
a.id = i;
gt[{a.x1, a.y1}].pb(a);
}
vi btoa(n, -1);
vector<vi> g(m);
for(int i = 0; i < m; i++) {
rect a;
cin >> a.x1 >> a.y1 >> a.x2 >> a.y2;
for(int x = max(0, a.x1 - 3); x < a.x2; x++) {
for(int y = max(0, a.y1 - 3); y < a.y2; y++) {
if(gt.count({x,y}) == 0) continue;
for(auto b : gt[{x,y}]) {
// cout << area(inter(a,b)) << " " << area(b) << endl;
// print(inter(a,b));
if(area(inter(a,b)) * 2 >= area(b)) {
g[i].pb(b.id);
}
}
}
}
}
// for(int i = 0; i < m; i++) {
// cout << i << ": ";
// for(auto x : g[i]) cout << x << " ";
// cout << endl;
// }
cout << hopcroftKarp(g, btoa) << endl;
}
int main() {
cin.tie(0)->sync_with_stdio(0);
int t; cin >> t;
for(int tcase = 0; tcase < t; tcase++) {
solve();
}
}
详细
Test #1:
score: 100
Accepted
time: 2ms
memory: 3352kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 2ms
memory: 3356kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #3:
score: 0
Accepted
time: 1171ms
memory: 15020kb
input:
5 50000 50000 0 0 4 4 4 0 8 4 8 0 12 4 12 0 16 4 16 0 20 4 20 0 24 4 24 0 28 4 28 0 32 4 32 0 36 4 36 0 40 4 40 0 44 4 44 0 48 4 48 0 52 4 52 0 56 4 56 0 60 4 60 0 64 4 64 0 68 4 68 0 72 4 72 0 76 4 76 0 80 4 80 0 84 4 84 0 88 4 88 0 92 4 92 0 96 4 96 0 100 4 100 0 104 4 104 0 108 4 108 0 112 4 112 ...
output:
50000 50000 0 50000 3150
result:
ok 5 lines
Test #4:
score: 0
Accepted
time: 753ms
memory: 14628kb
input:
5 50000 50000 0 0 1 1 1 0 2 1 2 0 3 1 3 0 4 1 4 0 5 1 5 0 6 1 6 0 7 1 7 0 8 1 8 0 9 1 9 0 10 1 10 0 11 1 11 0 12 1 12 0 13 1 13 0 14 1 14 0 15 1 15 0 16 1 16 0 17 1 17 0 18 1 18 0 19 1 19 0 20 1 20 0 21 1 21 0 22 1 22 0 23 1 23 0 24 1 24 0 25 1 25 0 26 1 26 0 27 1 27 0 28 1 28 0 29 1 29 0 30 1 30 0 ...
output:
50000 25050 12500 16000 8000
result:
ok 5 lines
Test #5:
score: 0
Accepted
time: 499ms
memory: 11464kb
input:
5 50000 50000 0 0 2 4 4 0 7 1 8 0 10 1 12 0 15 3 16 0 19 1 20 0 22 2 24 0 26 4 28 0 30 4 32 0 36 3 36 0 40 1 40 0 44 1 44 0 47 2 48 0 49 3 52 0 54 1 56 0 59 4 60 0 64 3 64 0 68 3 68 0 70 1 72 0 76 4 76 0 80 3 80 0 84 4 84 0 87 2 88 0 90 1 92 0 94 4 96 0 98 1 100 0 104 1 104 0 107 2 108 0 110 4 112 0...
output:
10594 10779 10618 10381 10779
result:
ok 5 lines
Test #6:
score: 0
Accepted
time: 1982ms
memory: 14988kb
input:
5 50000 50000 0 0 4 4 1 0 5 4 2 0 6 4 3 0 7 4 4 0 8 4 5 0 9 4 6 0 10 4 7 0 11 4 8 0 12 4 9 0 13 4 10 0 14 4 11 0 15 4 12 0 16 4 13 0 17 4 14 0 18 4 15 0 19 4 16 0 20 4 17 0 21 4 18 0 22 4 19 0 23 4 20 0 24 4 21 0 25 4 22 0 26 4 23 0 27 4 24 0 28 4 25 0 29 4 26 0 30 4 27 0 31 4 28 0 32 4 29 0 33 4 30...
output:
50000 50000 50000 50000 49600
result:
ok 5 lines
Test #7:
score: 0
Accepted
time: 2ms
memory: 3504kb
input:
1 4 4 1 1 3 3 2 1 4 3 1 2 3 4 2 2 4 4 2 1 4 3 3 2 5 4 1 2 3 4 2 3 4 5
output:
3
result:
ok single line: '3'