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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#103364 | #5010. Squaring the Triangle | joesmitty | WA | 0ms | 3328kb | C++20 | 4.5kb | 2023-05-05 14:35:27 | 2023-05-05 14:35:29 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef unsigned int uint;
typedef vector<int> vi;
typedef vector< vector <int> > vvi;
typedef pair<int, int> pii;
typedef pair < pair < int, int >, int > piii;
typedef pair < pair <int, int > , pair <int, int> > piiii;
typedef pair<ll, ll> pll;
typedef vector<bool> vb;
typedef vector<char> vc;
typedef vector<string> vs;
#define FOR(i,a,b) for(int i = a; i < b; i ++)
#define RFOR(i,a,b) for(int i = a-1; i >= b; i --)
#define all(a) a.begin(), a.end()
#define endl '\n';
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define ff first
#define ss second
template <typename T>
void pr(vector<T> &v) {
FOR(i, 0, sz(v)) cout << v[i] << " ";
cout << endl;
}
template <typename T>
void pr(vector<vector<T> > &v) {
FOR(i, 0, sz(v)) { pr(v[i]); }
}
template <typename T>
void re(T &x) {
cin >> x;
}
template <typename T>
void re(vector<T> &a) {
FOR(i, 0, sz(a)) re(a[i]);
}
template <class Arg, class... Args>
void re(Arg &first, Args &... rest) {
re(first);
re(rest...);
}
template <typename T>
void pr(T x) {
cout << x << endl;
}
template <class Arg, class... Args>
void pr(const Arg &first, const Args &... rest) {
cout << first << " ";
pr(rest...);
cout << endl;
}
void ps() { cout << endl; }
template<class T, class... Ts>
void ps(const T& t, const Ts&... ts) {
cout << t; if (sizeof...(ts)) cout << " "; ps(ts...);
}
const ll MOD = 1000000007;
#define inf 1e18;
#define INF INT_MAX;
long double PI = 4*atan(1);
long double eps = 1e-12;
template<int MOD, int RT> struct mint {
static const int mod = MOD;
static constexpr mint rt() { return RT; } // primitive root for FFT
int v; explicit operator int() const { return v; } // explicit -> don't silently convert to int
mint():v(0) {}
mint(ll _v) { v = int((-MOD < _v && _v < MOD) ? _v : _v % MOD);
if (v < 0) v += MOD; }
bool operator==(const mint& o) const {
return v == o.v; }
friend bool operator!=(const mint& a, const mint& b) {
return !(a == b); }
friend bool operator<(const mint& a, const mint& b) {
return a.v < b.v; }
// friend void re(mint& a) { ll x; re(x); a = mint(x); }
// friend str ts(mint a) { return ts(a.v); }
mint& operator+=(const mint& o) {
if ((v += o.v) >= MOD) v -= MOD;
return *this; }
mint& operator-=(const mint& o) {
if ((v -= o.v) < 0) v += MOD;
return *this; }
mint& operator*=(const mint& o) {
v = int((ll)v*o.v%MOD); return *this; }
mint& operator/=(const mint& o) { return (*this) *= inv(o); }
friend mint mpow(mint a, ll p) {
mint ans = 1; //assert(p >= 0);
for (; p; p /= 2, a *= a) if (p&1) ans *= a;
return ans; }
friend mint inv(const mint& a) { //assert(a.v != 0);
return mpow(a,MOD-2); }
mint operator-() const { return mint(-v); }
mint& operator++() { return *this += 1; }
mint& operator--() { return *this -= 1; }
friend mint operator+(mint a, const mint& b) { return a += b; }
friend mint operator-(mint a, const mint& b) { return a -= b; }
friend mint operator*(mint a, const mint& b) { return a *= b; }
friend mint operator/(mint a, const mint& b) { return a /= b; }
};
using mi = mint<MOD,5>; // 5 is primitive root for both common mods
mi choose(mi a, mi b) {
mi ans = 1;
FOR(i,0,b) ans *= (a-i);
FOR(i,1,b+1) {
mi im = i;
ans *= inv(im);
}
return ans;
}
void solve() {
ll n,p,q; cin >> n >> p >> q;
mi pmi = p;
mi qmi = q;
mi pp = pmi * inv(qmi);
mi pp3 = pp * pp * pp;
mi pp5 = pp3 * pp * pp;
mi pp6 = pp5 * pp;
mi ans = 0;
ans += pp3 * choose(n,3);
ans += pp5 * choose(n,2) * (n-2) * (n-3);
ans += pp5 * n * choose(n-1, 2) * choose(n-3,2);
ans += pp6 * choose(n, 3) * choose(n-3, 3);
cout << ans.v << endl;
}
int main() {
//auto start = chrono::high_resolution_clock::now();
ios_base::sync_with_stdio(0);cin.tie(0);
// ofstream cout("pieaters.out");
// ifstream cin("pieaters.in");
#ifdef DEBUG
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
int T; cin >> T;
FOR(tcase,0,T) {
solve();
}
// auto stop = chrono::high_resolution_clock::now();
// auto duration = chrono::duration_cast<chrono::microseconds>(stop - start);
// cout << duration.count() << endl;
//cin.close();
//cout.close();
}
详细
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3328kb
input:
2 3 50 100 7 8 9
output:
125000001 469637008
result:
wrong answer 2nd lines differ - expected: '655855196', found: '469637008'