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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#102584#5661. Multi-LaddersJoler#AC ✓3ms3484kbC++143.7kb2023-05-03 14:51:232023-05-03 14:51:27

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-03 14:51:27]
  • 评测
  • 测评结果:AC
  • 用时:3ms
  • 内存:3484kb
  • [2023-05-03 14:51:23]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#ifdef LOCAL
template<class t,class u>ostream& operator<<(ostream& os,const pair<t,u>& p){return os<<"("<<p.first<<","<<p.second<<")";}
#endif
template<class t>ostream& operator<<(ostream& os,const vector<t>& v){if(v.size())os<<v[0];for(int i=1; i<v.size(); i++)os<<' '<<v[i]; return os;}


template<class T>
T power(T a, ll b) {
    T res = 1;
    for (; b; b /= 2, a *= a) {
        if (b % 2) {
            res *= a;
        }
    }
    return res;
}

template<int P>
struct MInt {
    int x;
    MInt() : x{} {}
    MInt(ll x) : x{norm(x % P)} {}

    int norm(int x) {
        if (x < 0) {
            x += P;
        }
        if (x >= P) {
            x -= P;
        }
        return x;
    }
    int val() const {
        return x;
    }
    MInt operator-() const {
        MInt res;
        res.x = norm(P - x);
        return res;
    }
    MInt inv() const {
        assert(x != 0);
        return power(*this, P - 2);
    }
    MInt &operator*=(const MInt &rhs) {
        x = 1LL * x * rhs.x % P;
        return *this;
    }
    MInt &operator+=(const MInt &rhs) {
        x = norm(x + rhs.x);
        return *this;
    }
    MInt &operator-=(const MInt &rhs) {
        x = norm(x - rhs.x);
        return *this;
    }
    MInt &operator/=(const MInt &rhs) {
        return *this *= rhs.inv();
    }
    friend MInt operator*(const MInt &lhs, const MInt &rhs) {
        MInt res = lhs;
        res *= rhs;
        return res;
    }
    friend MInt operator+(const MInt &lhs, const MInt &rhs) {
        MInt res = lhs;
        res += rhs;
        return res;
    }
    friend MInt operator-(const MInt &lhs, const MInt &rhs) {
        MInt res = lhs;
        res -= rhs;
        return res;
    }
    friend MInt operator/(const MInt &lhs, const MInt &rhs) {
        MInt res = lhs;
        res /= rhs;
        return res;
    }
    friend std::istream &operator>>(std::istream &is, MInt &a) {
        ll v;
        is >> v;
        a = MInt(v);
        return is;
    }
    friend std::ostream &operator<<(std::ostream &os, const MInt &a) {
        return os << a.val();
    }
};

constexpr int P = 1000000007;
using Z = MInt<P>;

#define ll Z
const int inf = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f3f3f;
ll n, m, t, k, a, b, c, d, cnt, mark, an, oT_To, x, y, z;
ll ans;

array<array<ll, 2>, 2> A = {array<ll, 2>{0, 1}};
struct jz {
    array<array<ll, 2>, 2> a{};
};
jz operator*(const jz& ja, const jz& jb) {
    array<array<ll, 2>, 2> res{};
    for (int i : {0, 1}) for (int j : {0, 1}) for (int l : {0, 1})
        res[i][j] += ja.a[i][l] * jb.a[l][j];
    return {res};
}

jz ksm (jz a, ll b) {
    jz res{array<ll, 2>{1, 0}, array<ll, 2>{0, 1}};
    while (b.x) {
        if (b.x & 1) res = res * a;
        a = a * a;
        b.x >>= 1;
    }
    return res;
}

struct Solver {
	void solve() {
        cin >> n >> m >> k;
        A[1][0] = k - 1;
        A[1][1] = k - 2;
        if (k.x <= 1) return cout << "0\n", void();
//        if (k == 2) {
//            if (m == 3) cout << "0\n";
//            else cout << 2 << '\n';
//            return;
//        }
        
        auto p = ksm({A}, m-1);
        ll y = p.a[1][0];
//        cout << "x: " << x << '\n';
//        cout << "y: " << y << '\n';
        ll ans = (y * k) * power(((k-1)*(k-1)-k+2), (n.x-1ll)*m.x);
        cout << ans << '\n';
	}
};
#undef int
int main () {
    ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);
    oT_To = 1;
    cin >> oT_To;
    while (oT_To.x--) {
    	Solver solver;
        solver.solve();
    }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 3232kb

input:

1
2 3 3

output:

162

result:

ok single line: '162'

Test #2:

score: 0
Accepted
time: 3ms
memory: 3484kb

input:

20
2 3 3
1 3 3
10 3 0
10 3 2
1 21 2
1 22 0
2000 15000 2000
12000 30000 200000
1000000000 3 3
2 1000000000 3
2 3 100000000
1000000000 1000000000 10
1000000000 3 100000000
2 1000000000 100000000
1 1000000000 10
1 1000000000 100000000
1 1000 100000000
1000000000 1000000000 0
1000000000 1000000000 1
100...

output:

162
6
0
0
0
0
349400141
243010659
52489881
53690844
176686901
218103365
558243892
991895211
693053429
883715672
80402569
0
0
311752813

result:

ok 20 lines