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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#102290 | #6380. LaLa and Divination Magic | Crysfly# | WA | 2ms | 3400kb | C++17 | 3.1kb | 2023-05-02 21:19:14 | 2023-05-02 21:19:15 |
Judging History
answer
#include<bits/stdc++.h>
#define For(i,a,b) for(int i=(a);i<=(b);++i)
#define Rep(i,a,b) for(int i=(a);i>=(b);--i)
using namespace std;
inline int read()
{
char c=getchar();int x=0;bool f=0;
for(;!isdigit(c);c=getchar())f^=!(c^45);
for(;isdigit(c);c=getchar())x=(x<<1)+(x<<3)+(c^48);
if(f)x=-x;return x;
}
#define mod 998244353
struct modint{
int x;
modint(int o=0){x=o;}
modint &operator = (int o){return x=o,*this;}
modint &operator +=(modint o){return x=x+o.x>=mod?x+o.x-mod:x+o.x,*this;}
modint &operator -=(modint o){return x=x-o.x<0?x-o.x+mod:x-o.x,*this;}
modint &operator *=(modint o){return x=1ll*x*o.x%mod,*this;}
modint &operator ^=(int b){
modint a=*this,c=1;
for(;b;b>>=1,a*=a)if(b&1)c*=a;
return x=c.x,*this;
}
modint &operator /=(modint o){return *this *=o^=mod-2;}
friend modint operator +(modint a,modint b){return a+=b;}
friend modint operator -(modint a,modint b){return a-=b;}
friend modint operator *(modint a,modint b){return a*=b;}
friend modint operator /(modint a,modint b){return a/=b;}
friend modint operator ^(modint a,int b){return a^=b;}
friend bool operator ==(modint a,int b){return a.x==b;}
friend bool operator !=(modint a,int b){return a.x!=b;}
bool operator ! () {return !x;}
modint operator - () {return x?mod-x:0;}
bool operator <(const modint&b)const{return x<b.x;}
};
inline modint qpow(modint x,int y){return x^y;}
vector<modint> fac,ifac,iv;
inline void initC(int n)
{
if(iv.empty())fac=ifac=iv=vector<modint>(2,1);
int m=iv.size(); ++n;
if(m>=n)return;
iv.resize(n),fac.resize(n),ifac.resize(n);
For(i,m,n-1){
iv[i]=iv[mod%i]*(mod-mod/i);
fac[i]=fac[i-1]*i,ifac[i]=ifac[i-1]*iv[i];
}
}
inline modint C(int n,int m){
if(m<0||n<m)return 0;
return initC(n),fac[n]*ifac[m]*ifac[n-m];
}
inline modint sign(int n){return (n&1)?(mod-1):(1);}
#define fi first
#define se second
#define pb push_back
#define mkp make_pair
typedef pair<int,int>pii;
typedef vector<int>vi;
#define maxn 2000005
#define inf 0x3f3f3f3f
#define bint bitset<2005>
int n,m;
vector<vi>res;
bint a[2005],tmp;
bitset<4005>e[4005];
int cnt;
void dfs(bitset<4005>S,int u){
if((S&(S<<m)).count())return;
if(u==m+1){
if((++cnt)>n)puts("-1"),exit(0);
return;
}
if(!S[u]) dfs(S|e[u],u+1);
if(!S[u+m]) dfs(S|e[u+m],u+1);
}
int rd(){
char ch;
while(!isdigit(ch=getchar()));
return ch&1;
}
signed main()
{
n=read(),m=read();
For(i,1,n)
For(j,1,m)a[j][i]=rd();
For(i,1,m*2)e[i][i]=1;
For(u,1,m)
For(v,u,m){
For(i,0,1)
For(j,0,1){
if(u==v && i!=j) continue;
tmp=(i?a[u]:(~a[u]))&(j?a[v]:(~a[v]));
// cout<<"i,j "<<u<<" "<<v<<" "<<i<<" "<<j<<endl;
// For(_,1,n)cout<<tmp[_];puts("");
if(tmp._Find_next(0)<=n) continue;
// puts("QAQ");
res.pb({u-1,v-1,i+1+j*2});
e[u+m*(!i)][v+m*j]=1;
e[v+m*(!j)][u+m*i]=1;
}
}
bitset<4005>tmp;
tmp.reset();
dfs(tmp,1);
if(cnt!=n)puts("-1"),exit(0);
cout<<res.size()<<"\n";
for(auto it:res){
for(int x:it)cout<<x<<" ";
cout<<"\n";
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3400kb
input:
2 1 1 0
output:
0
result:
ok Kout = 0, Kans = 0
Test #2:
score: -100
Wrong Answer
time: 2ms
memory: 3356kb
input:
3 3 101 011 111
output:
-1
result:
wrong answer Jury has a solution while the participant doesn't, Kans = 6