QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#102257#6376. LaLa and LampCrysfly#WA 2ms3560kbC++172.5kb2023-05-02 19:34:442023-05-02 19:34:46

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-05-02 19:34:46]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3560kb
  • [2023-05-02 19:34:44]
  • 提交

answer

#include<bits/stdc++.h>
#define For(i,a,b) for(int i=(a);i<=(b);++i)
#define Rep(i,a,b) for(int i=(a);i>=(b);--i)
using namespace std;
inline int read()
{
	char c=getchar();int x=0;bool f=0;
	for(;!isdigit(c);c=getchar())f^=!(c^45);
	for(;isdigit(c);c=getchar())x=(x<<1)+(x<<3)+(c^48);
	if(f)x=-x;return x;
}

#define mod 998244353
struct modint{
	int x;
	modint(int o=0){x=o;}
	modint &operator = (int o){return x=o,*this;}
	modint &operator +=(modint o){return x=x+o.x>=mod?x+o.x-mod:x+o.x,*this;}
	modint &operator -=(modint o){return x=x-o.x<0?x-o.x+mod:x-o.x,*this;}
	modint &operator *=(modint o){return x=1ll*x*o.x%mod,*this;}
	modint &operator ^=(int b){
		modint a=*this,c=1;
		for(;b;b>>=1,a*=a)if(b&1)c*=a;
		return x=c.x,*this;
	}
	modint &operator /=(modint o){return *this *=o^=mod-2;}
	friend modint operator +(modint a,modint b){return a+=b;}
	friend modint operator -(modint a,modint b){return a-=b;}
	friend modint operator *(modint a,modint b){return a*=b;}
	friend modint operator /(modint a,modint b){return a/=b;}
	friend modint operator ^(modint a,int b){return a^=b;}
	friend bool operator ==(modint a,int b){return a.x==b;}
	friend bool operator !=(modint a,int b){return a.x!=b;}
	bool operator ! () {return !x;}
	modint operator - () {return x?mod-x:0;}
	bool operator <(const modint&b)const{return x<b.x;}
};
inline modint qpow(modint x,int y){return x^y;}

vector<modint> fac,ifac,iv;
inline void initC(int n)
{
	if(iv.empty())fac=ifac=iv=vector<modint>(2,1);
	int m=iv.size(); ++n;
	if(m>=n)return;
	iv.resize(n),fac.resize(n),ifac.resize(n);
	For(i,m,n-1){
		iv[i]=iv[mod%i]*(mod-mod/i);
		fac[i]=fac[i-1]*i,ifac[i]=ifac[i-1]*iv[i];
	}
}
inline modint C(int n,int m){
	if(m<0||n<m)return 0;
	return initC(n),fac[n]*ifac[m]*ifac[n-m];
}
inline modint sign(int n){return (n&1)?(mod-1):(1);}

#define fi first
#define se second
#define pb push_back
#define mkp make_pair
typedef pair<int,int>pii;
typedef vector<int>vi;

#define maxn 500005
#define inf 0x3f3f3f3f

int n;
string s[2005];

int a[maxn],b[maxn],c[maxn];

signed main()
{
	n=read();
	For(i,0,n-1)cin>>s[i];
	int qwq=0;
	For(x,0,1)For(y,0,1)For(z,0,1){
		c[0]=x;
		For(i,1,n-1) c[i]=c[i-1]^(s[i][0]&1)^(s[i][1]&1)^y^z;
		b[0]=y,b[1]=z;
		For(i,0,n-1) a[i]=b[0]^c[i]^(s[i][0]&1);
		For(i,2,n-1) b[i]=a[n-1]^c[n-i-1]^(s[n-1][i]&1);
		bool ok=1;
		For(i,0,n-1) For(j,0,i-1) if((s[i][j]&1)!=(a[i]^b[j]^c[i-j])) ok=0;
		if(ok)qwq=1;
	} 
	if(qwq)puts("Yes");
	else puts("No");
	return 0;
}
/*
6
0
00
000
0110
00100
000000
*/

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3344kb

input:

6
0
00
000
0110
00100
000000

output:

Yes

result:

ok answer is YES

Test #2:

score: 0
Accepted
time: 2ms
memory: 3560kb

input:

2
0
11

output:

Yes

result:

ok answer is YES

Test #3:

score: 0
Accepted
time: 1ms
memory: 3408kb

input:

3
1
10
011

output:

Yes

result:

ok answer is YES

Test #4:

score: -100
Wrong Answer
time: 1ms
memory: 3516kb

input:

4
1
11
101
0101

output:

Yes

result:

wrong answer expected NO, found YES