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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#100843 | #5115. Clone Ranran | lgvc# | AC ✓ | 31ms | 4400kb | C++23 | 1.6kb | 2023-04-28 12:41:33 | 2023-04-28 12:41:37 |
Judging History
answer
//这回只花了114514min就打完了。
//真好。记得多手造几组。
#include <bits/stdc++.h>
#define int long long
#define pai 3.141592653589793238462643383279502884197169399375105820
#define MOD 1000000007
#define eps 0.00000001
inline int min(int a,int b) {return a<b?a:b;}
inline int max(int a,int b) {return a>b?a:b;}
#define ULL unsigned long long
#define LL long long
#define INF 0x3f3f3f3f
#define INF_LL 0x3f3f3f3f3f3f3f3f
static char buf[1000000],*paa=buf,*pd=buf;
static char buf2[1000000],*pp=buf2;
#define getchar() paa==pd&&(pd=(paa=buf)+fread(buf,1,1000000,stdin),paa==pd)?EOF:*paa++
inline void pc(char ch){
if(pp-buf2==1000000) fwrite(buf2,1,1000000,stdout),pp=buf2;
*pp++=ch;
}
inline void pcc(){
fwrite(buf2,1,pp-buf2,stdout);
pp=buf2;
}
inline int read(void) {
int w=1;
register int x(0);register char c(getchar());
while(c<'0'||c>'9') {if(c=='-') w=-1;c=getchar();}
while(c>='0'&&c<='9') x=(x<<1)+(x<<3)+(c^48),c=getchar();
return w*x;
}
void write(int x) {
if(x<0) pc('-'),x=-x;
static int sta[20];
int top=0;
do {
sta[top++]=x%10,x/=10;
} while(x);
while(top) pc(sta[--top]+48);
}
void we(int x) {
write(x);
pc('\n');
}
inline bool cmp_xi(int a,int b) {return a<b;}
inline bool cmp_da(int a,int b) {return a>b;}
signed main(void) {
//freopen("m.in","r",stdin);
//freopen("m.out","w",stdout);
int T=read();
while(T--) {
int A=read(),B=read(),C=read(),ans=INF_LL;
for(int i=0;i<=30;i++) {
ans=std::min(ans,i*A+(C+(1<<i)-1)/(1<<i)*B);
}
printf("%lld\n",ans);
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 2ms
memory: 3424kb
input:
5 1 1 1 2 3 3 9 9 9 3 26 47 1064 822 1048576
output:
1 7 45 44 21860
result:
ok 5 number(s): "1 7 45 44 21860"
Test #2:
score: 0
Accepted
time: 31ms
memory: 4400kb
input:
99500 1000000000 1000000000 1000000000 1000000000 1000000000 999999999 1000000000 1000000000 999999998 1000000000 1000000000 999999997 1000000000 1000000000 999999996 1000000000 1000000000 999999995 1000000000 1000000000 999999994 1000000000 1000000000 999999993 1000000000 1000000000 999999992 10000...
output:
31000000000 31000000000 31000000000 31000000000 31000000000 31000000000 31000000000 31000000000 31000000000 31000000000 30999999998 30999999998 30999999998 30999999998 30999999998 30999999998 30999999998 30999999998 30999999998 30999999998 30999999996 30999999996 30999999996 30999999996 30999999996 ...
result:
ok 99500 numbers