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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#100701#6329. Colorful GraphSolitaryDream#TL 7719ms7752kbC++204.8kb2023-04-27 17:31:532023-04-27 17:31:54

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-04-27 17:31:54]
  • 评测
  • 测评结果:TL
  • 用时:7719ms
  • 内存:7752kb
  • [2023-04-27 17:31:53]
  • 提交

answer


#include <bits/stdc++.h>
using namespace std;
typedef pair<int, int> pii;
namespace Flow {
    const int N = 14010;
    const int M = N * 10;
    vector<int> H[N];
    int ans[N];
    int nn;
    int h[N], gap[N], in[N];
    int tot = 1, a[M], ne[M], c[M], tmpc[M], fi[N];
    void Add(int x, int y, int z) {
        a[++tot] = y; ne[tot] = fi[x]; fi[x] = tot; c[tot] = tmpc[tot] = z; 
        a[++tot] = x; ne[tot] = fi[y]; fi[y] = tot; c[tot] = tmpc[tot] = 0;
    }
    int cur[N], de[N];
    inline bool Bfs(int s, int t) {
        static queue<int> q;
        for (int i = 1; i <= t; ++i) de[i] = 0;
        de[s] = 1; q.push(s);
        while (!q.empty()) {
            int u = q.front(); q.pop();
            for (int i = fi[u]; i; i = ne[i]) if (c[i] && !de[a[i]]) {
                de[a[i]] = de[u] + 1;
                q.push(a[i]);
            }
        }
        return de[t];
    }
    inline int Dfs(int x, int flow, int t) {
        if (x == t) return flow;
        int tmp, sm = 0;
        for (int &i = cur[x]; i; i = ne[i]) if (c[i] && de[x] + 1 == de[a[i]] && (tmp = Dfs(a[i], min(flow, c[i]), t))) {
            c[i] -= tmp; c[i ^ 1] += tmp;
            flow -= tmp; sm += tmp;
            if (!flow) return sm;
        }
        return sm;
    }
    inline bool Check(int lim, int sm, int ip, int SS, int TT) {
        for (int i = 2; i <= tot; ++i) c[i] = tmpc[i];
        c[ip] = lim;
        int maxflow = 0;
        while (Bfs(SS, TT)) {
            memcpy(cur + 1, fi + 1, TT * sizeof *cur);
            maxflow += Dfs(SS, nn, TT);
        }
        return sm == maxflow;
    }
    list<int> vec[N];
    inline void Split(list<int> &a, list<int> &b, int num) {
        auto it = a.end();
        while (num--) --it;
        b.insert(b.end(), it, a.end());
        a.erase(it, a.end());
    }
    inline void Solve() {
        int S = nn * 2 + 1, T = S + 1, SS = T + 1, TT = SS + 1;
        for (int i = 1; i <= nn; ++i) {
            int j = i + nn;
            in[i] -= 1; in[j] += 1;
            Add(i, j, nn);
            Add(S, i, nn);
            Add(j, T, nn);
            for (auto ni : H[i]) Add(j, ni, nn);
        }
        int sm = 0;
        for (int i = 1; i <= TT; ++i) if (in[i] > 0) sm += in[i], Add(SS, i, in[i]); else Add(i, TT, -in[i]);
        Add(T, S, 0);
        int ip = tot - 1;
        int lim = 0;
        for (int l = 1, r = nn; l <= r; ) {
            int mid = (l + r) >> 1;
            if (Check(mid, sm, ip, SS, TT)) lim = mid, r = mid - 1; else l = mid + 1;
        }
        Check(lim, sm, ip, SS, TT);
        // printf("lim = %d\n", lim);
        for (int i = 1; i <= lim; ++i) vec[S].push_back(i);
        // puts("here");
        for (int i = fi[S]; i; i = ne[i]) if (a[i] <= nn && c[i ^ 1]) {
            // printf("%d -> %d  %d\n", S, a[i], c[i ^ 1]);
            Split(vec[S], vec[a[i]], c[i ^ 1]);
        }
        for (int x = nn; x; --x) {
            // printf("%d %d\n", x, (int)vec[x].size());
            ans[x] = vec[x].front();
            for (int i = fi[x + nn]; i; i = ne[i]) if (a[i] <= nn) {
                // printf("%d -> %d  %d\n", x, a[i], c[i ^ 1]);
                Split(vec[x], vec[a[i]], c[i ^ 1]);
            }
        }
        // puts("fin");
    }
};
const int N = 7010;
int n, m;
vector<int> g[N], h[N];
int fa[N];
int col[N], colnum, dfn[N], low[N], dclk;
int deg[N], ins[N];
stack<int> sta;
inline void Tarjan(int x) {
    sta.push(x); ins[x] = 1;
    dfn[x] = low[x] = ++dclk;
    for (auto y : g[x]) 
        if (!dfn[y]) Tarjan(y), low[x] = min(low[x], low[y]);
        else if (ins[y]) low[x] = min(low[x], dfn[y]);
    if (low[x] == dfn[x]) {
        col[x] = ++colnum;
        while (sta.top() != x) {
            col[sta.top()] = colnum;
            ins[sta.top()] = 0;
            sta.pop();
        }
        ins[x] = 0;
        sta.pop();
    }
}
int main() {
    scanf("%d%d", &n, &m);
    // srand(time(0));
    // n = 7000; m = 7000;
    for (int i = 1, x, y; i <= m; ++i) {
        scanf("%d%d", &x, &y);
        // if (i <= 3500) {
        //     x = i, y = i + 1;
        // } else {
        //     x = 3501, y = i;
        // }
        g[x].push_back(y);
    }
    for (int i = 1; i <= n; ++i) if (!dfn[i]) {
        Tarjan(i);
    }
    for (int x = 1; x <= n; ++x)
        for (auto y : g[x]) if (col[x] != col[y]) {
            Flow::H[col[x]].push_back(col[y]);
            ++deg[col[y]];
        }
    for (int i = 1; i <= colnum; ++i) {
        using Flow::H;
        sort(H[i].begin(), H[i].end());
        H[i].erase(unique(H[i].begin(), H[i].end()), H[i].end());
    }
    Flow::nn = colnum;
    Flow::Solve();
    for (int i = 1; i <= n; ++i) printf("%d%c", Flow::ans[col[i]], " \n"[i == n]);
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 3ms
memory: 6564kb

input:

5 5
1 4
2 3
1 3
2 5
5 1

output:

2 2 2 1 2

result:

ok AC

Test #2:

score: 0
Accepted
time: 2ms
memory: 6352kb

input:

5 7
1 2
2 1
4 3
5 1
5 4
4 1
4 5

output:

1 1 2 2 2

result:

ok AC

Test #3:

score: 0
Accepted
time: 1ms
memory: 6016kb

input:

8 6
6 1
3 4
3 6
2 3
4 1
6 4

output:

1 1 1 1 2 1 3 4

result:

ok AC

Test #4:

score: 0
Accepted
time: 7719ms
memory: 7752kb

input:

7000 6999
4365 4296
2980 3141
6820 4995
4781 24
2416 5844
2940 2675
3293 2163
3853 5356
262 6706
1985 1497
5241 3803
353 1624
5838 4708
5452 3019
2029 6161
3849 4219
1095 1453
4268 4567
1184 1857
2911 3977
1662 2751
6353 6496
2002 6628
1407 4623
425 1331
4445 4277
1259 3165
4994 1044
2756 5788
5496 ...

output:

1 591 1653 628 368 2 3 668 152 703 409 1378 4 1594 21 5 858 6 448 1302 1055 1518 1616 1340 1231 7 8 755 1410 9 219 1096 10 11 909 909 1626 12 1640 13 946 101 14 513 15 18 16 691 17 18 111 19 355 1396 1684 1191 901 20 1211 21 13 1187 267 546 153 22 1694 1197 544 23 24 288 25 862 26 1510 1128 1675 114...

result:

ok AC

Test #5:

score: -100
Time Limit Exceeded

input:

7000 6999
4832 1603
5984 6985
5355 3687
6007 2170
5984 3486
3267 2189
538 2123
4343 4553
5855 6168
5984 257
4239 2304
5984 2063
3298 1869
5984 6353
5984 2018
5984 5387
5984 3382
3164 3978
2690 2816
4810 2638
5984 3773
5984 1634
5984 2786
5984 3671
5984 5140
2943 5721
5984 414
1105 4060
3093 796
5984...

output:


result: