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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#100453#6128. Flippy Sequencemaomao90#AC ✓72ms8060kbC++171.8kb2023-04-26 13:20:142023-04-26 13:20:28

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-04-26 13:20:28]
  • 评测
  • 测评结果:AC
  • 用时:72ms
  • 内存:8060kb
  • [2023-04-26 13:20:14]
  • 提交

answer


// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h> 
using namespace std;

#define REP(i, s, e) for (int i = (s); i < (e); i++)
#define RREP(i, s, e) for (int i = (s); i >= (e); i--)
template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define SZ(_a) (int) _a.size()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

const int INF = 1000000005;
const ll LINF = 1000000000000000005ll;
const int MAXN = 1000005;

int T;
int n;
string s, t;
bool psm[MAXN];

int main() {
#ifndef DEBUG
    ios::sync_with_stdio(0), cin.tie(0);
#endif
    cin >> T;
    while (T--) {
        cin >> n;
        cin >> s;
        cin >> t;
        s = "0" + s + "0";
        t = "0" + t + "0";
        int cnt = 0;
        REP (i, 1, n + 2) {
            psm[i] = (s[i] != t[i]) ^ (s[i - 1] != t[i - 1]);
            cnt += psm[i];
        }
        assert(cnt % 2 == 0);
        if (cnt > 4) {
            cout << 0 << '\n';
            continue;
        }
        if (cnt == 4) {
            cout << 6 << '\n';
            continue;
        }
        if (cnt == 0) {
            cout << (ll) n * (n + 1) / 2 << '\n';
            continue;
        }
        if (n == 1) {
            cout << 0 << '\n';
            continue;
        }
        cout << (n - 1) * 2 << '\n';
    }
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 2ms
memory: 3352kb

input:

3
1
1
0
2
00
11
5
01010
00111

output:

0
2
6

result:

ok 3 number(s): "0 2 6"

Test #2:

score: 0
Accepted
time: 72ms
memory: 8060kb

input:

126648
1
0
0
1
1
0
2
01
01
2
01
11
2
10
11
2
11
00
3
011
011
3
010
110
3
011
001
3
111
001
3
001
000
3
101
000
3
011
000
3
111
000
4
1111
1111
4
1110
0110
4
0010
0110
4
1011
0111
4
1001
1011
4
0100
1110
4
0000
0110
4
0111
1001
4
1001
1000
4
1011
0010
4
0001
0100
4
1000
0101
4
0100
0111
4
1101
0110
4...

output:

1
0
3
2
2
2
6
4
4
4
4
6
4
4
10
6
6
6
6
6
6
6
6
6
6
6
6
6
6
6
15
8
8
8
8
6
8
8
8
6
6
6
8
6
8
8
8
6
6
6
6
0
6
6
8
6
6
6
8
6
8
8
21
10
10
10
10
6
10
10
10
6
6
6
10
6
10
10
10
6
6
6
6
0
6
6
10
6
6
6
10
6
10
10
10
6
6
6
6
0
6
6
6
0
0
0
6
0
6
6
10
6
6
6
6
0
6
6
10
6
6
6
10
6
10
10
28
12
12
12
12
6
12
12
1...

result:

ok 126648 numbers