QOJ.ac
QOJ
ID | 提交记录ID | 题目 | Hacker | Owner | 结果 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|
#540 | #312339 | #7754. Rolling For Days | Yansuan_HCl | 275307894a | Failed. | 2024-02-19 19:19:08 | 2024-02-19 19:19:09 |
详细
Extra Test:
Accepted
time: 0ms
memory: 8152kb
input:
4 2 2 2 0 1
output:
2
result:
ok answer is '2'
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#312339 | #7754. Rolling For Days | 275307894a | AC ✓ | 67ms | 76624kb | C++14 | 2.5kb | 2024-01-23 20:21:58 | 2024-01-23 20:21:58 |
answer
#include<bits/stdc++.h>
#define Gc() getchar()
#define Me(x,y) memset(x,y,sizeof(x))
#define Mc(x,y) memcpy(x,y,sizeof(x))
#define d(x,y) ((m)*(x-1)+(y))
#define R(n) (rnd()%(n)+1)
#define Pc(x) putchar(x)
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define eb emplace_back
using namespace std;using ll=long long;using db=double;using lb=long db;using ui=unsigned;using ull=unsigned long long;using pii=pair<int,int>;
const int N=(1<<12)+5,M=1000+5,K=1000+5,mod=998244353,Mod=mod-1;const db eps=1e-9;const int INF=1e9+7;mt19937 rnd(263082);
#define Tp template<typename T>
#define Ts template<typename T,typename... Ar>
namespace Debug{
Tp void _debug(char* f,T t){cerr<<f<<'='<<t<<endl;}
Ts void _debug(char* f,T x,Ar... y){while(*f!=',') cerr<<*f++;cerr<<'='<<x<<",";_debug(f+1,y...);}
#define gdb(...) _debug((char*)#__VA_ARGS__,__VA_ARGS__)
}using namespace Debug;
int n,m,k,sa[N],sb[N],A[N],B[N];ll frc[N],frv[N],inv[N],C[N][N];
ll dp[N][N][2],g[N][2];
ll mpow(ll x,int y=mod-2){ll ans=1;while(y) y&1&&(ans=ans*x%mod),y>>=1,x=x*x%mod;return ans;}
void Solve(){
int i,j,h;scanf("%d%d",&n,&m);k=(1<<m);
for(i=0;i<m;i++) scanf("%d",&A[i]);
for(i=0;i<m;i++) scanf("%d",&B[i]);
for(i=1;i<k;i++) sa[i]=sa[i^(i&-i)]+A[__lg(i&-i)];
for(i=1;i<k;i++) sb[i]=sb[i^(i&-i)]+B[__lg(i&-i)];
inv[1]=1;for(i=2;i<=n;i++) inv[i]=(mod-inv[mod%i])*(mod/i)%mod;
for(frc[0]=frv[0]=i=1;i<=n;i++) frc[i]=frc[i-1]*i%mod,frv[i]=frv[i-1]*inv[i]%mod;
for(i=0;i<=n;i++) for(C[i][0]=j=1;j<=i;j++) C[i][j]=(C[i-1][j]+C[i-1][j-1])%mod;
int goal=0;for(i=0;i<m;i++) if(!B[i]) goal|=1<<i;
dp[goal][0][0]=1;
for(i=0;i<k;i++){
Mc(g,dp[i]);
for(h=1;h<=sb[k-1]-sb[i];h++){
g[h][0]=(g[h][0]+g[h-1][0]*inv[sa[k-1]-sa[i]-(h-1)])%mod;
g[h][1]=(g[h][1]+(g[h-1][1]+g[h-1][0]*inv[sa[k-1]-sa[i]-(h-1)]%mod*(sa[k-1]-sb[i]-(h-1))%mod)*inv[sa[k-1]-sa[i]-(h-1)])%mod;
}
for(h=0;h<=sb[k-1]-sb[i];h++) g[h][0]=(g[h][0]+mod-dp[i][h][0])%mod,g[h][1]=(g[h][1]+mod-dp[i][h][1])%mod;
for(j=0;j<m;j++)if(~i>>j&1){
for(h=B[j];h<=sb[k-1]-sb[i];h++){
ll w=C[h-1][B[j]-1]*C[A[j]][B[j]]%mod*frc[B[j]]%mod;
dp[i|(1<<j)][h-B[j]][0]=(dp[i|(1<<j)][h-B[j]][0]+g[h][0]*w)%mod;
dp[i|(1<<j)][h-B[j]][1]=(dp[i|(1<<j)][h-B[j]][1]+g[h][1]*w)%mod;
}
}
}
gdb(dp[k-1][0][1],dp[k-1][0][0]);
printf("%lld\n",dp[k-1][0][1]*mpow(dp[k-1][0][0])%mod);
}
int main(){
int t=1;
// scanf("%d",&t);
while(t--) Solve();
cerr<<clock()*1.0/CLOCKS_PER_SEC<<'\n';
}