QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#99995 | #4398. Luxury cruise ship | 3360550356 | AC ✓ | 2ms | 3972kb | C++14 | 807b | 2023-04-24 12:19:46 | 2023-04-24 12:19:50 |
Judging History
answer
#include<bits/stdc++.h>
#define int long long
#define PII pair<int,int>
#define X first
#define Y second
const int INF=0x3f3f3f3f3f3f3f3f;
const int N=7*31*366;
const int M=7*31*365;
using namespace std;
int f[N];
void fun(){
memset(f,0x3f,sizeof(f));
f[0]=0;
int a[3]={7,31,365};
//完全背包
for(int i=0;i<3;i++){
for(int j=a[i];j<=M;j++){
f[j]=min(f[j],f[j-a[i]]+1);
}
}
}
//考虑用背包来做
void solve(){
int n;
cin>>n;
if(n<=M){
if(f[n]<INF)cout<<f[n]<<endl;
else cout<<"-1"<<endl;
}else{
int x=n-M;
int ans=(x+364)/365;
int y=n-365*ans;
ans+=f[y];
if(ans<INF)cout<<ans<<endl;
else cout<<"-1"<<endl;
}
}
signed main(){
int T;
T=1;
fun();
cin>>T;
while(T--){
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 2ms
memory: 3972kb
input:
1000 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101...
output:
-1 -1 -1 -1 -1 -1 1 -1 -1 -1 -1 -1 -1 2 -1 -1 -1 -1 -1 -1 3 -1 -1 -1 -1 -1 -1 4 -1 -1 1 -1 -1 -1 5 -1 -1 2 -1 -1 -1 6 -1 -1 3 -1 -1 -1 7 -1 -1 4 -1 -1 -1 8 -1 -1 5 -1 -1 2 9 -1 -1 6 -1 -1 3 10 -1 -1 7 -1 -1 4 11 -1 -1 8 -1 -1 5 12 -1 -1 9 -1 -1 6 13 -1 3 10 -1 -1 7 14 -1 4 11 -1 -1 8 15 -1 5 12 -1 -...
result:
ok 1000 lines