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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#95488#5111. Take On MememarcoskWA 2ms3968kbC++142.7kb2023-04-10 00:03:442023-04-10 00:03:47

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-04-10 00:03:47]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3968kb
  • [2023-04-10 00:03:44]
  • 提交

answer

#include <bits/stdc++.h>
#define fst first
#define snd second
#define fore(i,a,b) for(int i=a,ThxDem=b;i<ThxDem;++i)
#define pb push_back
#define ALL(s) s.begin(),s.end()
#define FIN ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0)
#define SZ(s) int(s.size())
using namespace std;
typedef long long ll;
typedef pair<int,int> ii;

struct pt{
	ll x,y;
	pt(){}
	pt(ll x, ll y):x(x),y(y){}
	ll norm2(){return *this**this;}
	pt operator +(pt p){return pt(x+p.x,y+p.y);}
	pt operator -(pt p){return pt(x-p.x,y-p.y);}
	pt operator *(ll k){return pt(x*k,y*k);}
	pt operator /(ll k){return pt(x/k,y/k);}
	ll operator *(pt p){return x*p.x+y*p.y;}
	ll operator %(pt p){return x*p.y-y*p.x;}
	bool left(pt p, pt q){return (q-p)%(*this-p)>=0;}
	bool operator <(pt p){return x<p.x||(x==p.x&&y<p.y);}
};

typedef vector<pt> poly;
 
vector<pt> chull(vector<pt> p){
	if(SZ(p)<3)return p;
	vector<pt> r;
	sort(ALL(p));
	fore(i,0,p.size()){
		while(r.size()>=2&&r.back().left(r[r.size()-2],p[i]))r.pop_back();
		r.pb(p[i]);
	}
	r.pop_back();
	int k=r.size();
	for(int i=p.size()-1;i>=0;--i){
		while(r.size()>=k+2&&r.back().left(r[r.size()-2],p[i]))r.pop_back();
		r.pb(p[i]);
	}
	r.pop_back();
	return r;
}
 
poly add(poly p, poly q){
	if(!SZ(p)) return q;
	if(!SZ(q)) return p;
	
	if(SZ(p)==1){
		for(auto &x:q) x=(x+p[0]);
		return q;
	}
	
	if(SZ(q)==1){
		for(auto &x:p) x=(x+q[0]);
		return p;
	}
	
	int n=SZ(p),m=SZ(q),x=0,y=0;
	fore(i,0,n) if(p[i]<p[x]) x=i;
	fore(i,0,m) if(q[i]<q[y]) y=i;
	poly ans={p[x]+q[y]};
	fore(it,1,n+m){
		pt a=p[(x+1)%n]+q[y];
		pt b=p[x]+q[(y+1)%m];
		if(b.left(ans.back(),a)) ans.pb(b), y=(y+1)%m;
		else ans.pb(a), x=(x+1)%n;
	}
	
	return chull(ans);
}

poly mul(poly p, ll k){
	for(auto &x:p) x=x*k;
	return p;
}

const int MAXN=10010;
poly wh[MAXN];
vector<int> g[MAXN];

void dfs(int pos){
	if(!SZ(g[pos])) return;
	
	for(auto x:g[pos]) dfs(x);
	
	vector<poly> lef,rig;
	
	poly now;
	fore(i,0,SZ(g[pos])){
		lef.pb(now);
		reverse(ALL(wh[g[pos][i]]));
		now=add(now,mul(wh[g[pos][i]],-1));
		reverse(ALL(wh[g[pos][i]]));
	}
	
	now.clear();
	for(int i=SZ(g[pos])-1;i>=0;i--){
		rig.pb(now);
		reverse(ALL(wh[g[pos][i]]));
		now=add(now,mul(wh[g[pos][i]],-1));
		reverse(ALL(wh[g[pos][i]]));
	}
	reverse(ALL(rig));
	
	poly all;
	fore(i,0,SZ(g[pos])){
		now=add(wh[g[pos][i]], add(lef[i],rig[i]));
		for(auto p:now) all.pb(p);
	}
	
	wh[pos]=chull(all);
}

int main(){FIN;
	int n; cin>>n;
	fore(i,0,n){
		int k; cin>>k;
		if(k==0){
			int x,y; cin>>x>>y;
			wh[i].pb(pt(x,y));
		}
		else{
			fore(j,0,k){
				int x; cin>>x; x--;
				g[i].pb(x);
			}
		}
	}
	
	dfs(0);
	
	ll ans=0;
	for(auto p:wh[0]) ans=max(ans, p.norm2());
	cout<<ans<<"\n";
}

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 3928kb

input:

5
4 2 3 4 5
0 2 -2
0 1 3
0 4 -6
0 -18 5

output:

725

result:

ok single line: '725'

Test #2:

score: 0
Accepted
time: 2ms
memory: 3924kb

input:

5
2 2 3
2 4 5
0 1 5
0 -4 -6
0 -1 7

output:

340

result:

ok single line: '340'

Test #3:

score: -100
Wrong Answer
time: 2ms
memory: 3968kb

input:

18
3 4 3 2
2 5 6
3 7 9 8
3 10 11 12
0 4 -1
0 18 49
0 -2 10
2 13 14
0 -5 6
0 5 8
4 15 16 17 18
0 17 3
0 3 -9
0 -7 -1
0 14 -33
0 -23 11
0 11 14
0 2 19

output:

16981

result:

wrong answer 1st lines differ - expected: '26269', found: '16981'