QOJ.ac
QOJ
| ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
|---|---|---|---|---|---|---|---|---|---|
| #95440 | #6309. Aqre | George_Plover | WA | 61ms | 8164kb | Python3 | 708b | 2023-04-09 18:00:39 | 2023-04-09 18:00:42 |
Judging History
answer
a = [[1, 1, 1, 0], [1, 0, 1, 1], [1, 1, 0, 1], [0, 1, 1, 1]]
b = [[1, 1, 1], [1, 0, 1], [1, 1, 1], [0, 1, 0]]
T = int(input())
for _ in range(T):
n, m = [int(x) for x in input().split()]
flag = False
if n < m:
n, m = m, n
flag = True
ans = [[1] * m for _ in range(n)]
if n >= 4:
for i in range(n):
for j in range(m):
ans[i][j] = b[i % 4][j % 4] if m == 3 else a[(i + 1) % 4 if n % 4 == m % 4 == 1 else i % 4][j % 4]
print(sum([sum(_) for _ in ans]))
if flag:
n, m = m, n
for i in range(n):
for j in range(m):
print(ans[j][i] if flag else ans[i][j], end='')
print()
Details
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Test #1:
score: 100
Accepted
time: 12ms
memory: 8088kb
input:
3 2 2 3 4 3 8
output:
4 11 11 9 1110 1011 1110 18 11101110 10111011 11101110
result:
ok ok (3 test cases)
Test #2:
score: -100
Wrong Answer
time: 61ms
memory: 8164kb
input:
361 2 2 2 3 2 4 2 5 2 6 2 7 2 8 2 9 2 10 2 11 2 12 2 13 2 14 2 15 2 16 2 17 2 18 2 19 2 20 3 2 3 3 3 4 3 5 3 6 3 7 3 8 3 9 3 10 3 11 3 12 3 13 3 14 3 15 3 16 3 17 3 18 3 19 3 20 4 2 4 3 4 4 4 5 4 6 4 7 4 8 4 9 4 10 4 11 4 12 4 13 4 14 4 15 4 16 4 17 4 18 4 19 4 20 5 2 5 3 5 4 5 5 5 6 5 7 5 8 5 9 5 1...
output:
4 11 11 6 111 111 6 1110 1011 8 11101 10111 9 111011 101110 11 1110111 1011101 12 11101110 10111011 14 111011101 101110111 15 1110111011 1011101110 17 11101110111 10111011101 18 111011101110 101110111011 20 1110111011101 1011101110111 21 11101110111011 10111011101110 23 111011101110111 1011101110111...
result:
wrong answer ans finds a larger answer (test case 81)