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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#94959 | #4432. Jungle Trail | whatever# | AC ✓ | 128ms | 38916kb | C++23 | 1.6kb | 2023-04-08 14:42:38 | 2023-04-08 14:42:41 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
using i64 = long long;
constexpr int N = 2010;
int n, m, vis[N][N], pre[N][N];
string str[N];
void solve() {
cin >> n >> m;
for(int i = 1; i <= n; i ++) {
cin >> str[i];
str[i] = "#" + str[i];
}
for(int i = 1; i <= n; i ++) {
for(int j = 1; j <= m; j ++) {
vis[i][j] = 0;
}
}
vis[1][1] = 1;
for(int i = 1; i <= n; i ++) {
for(int j = 1; j <= m; j ++) {
if(str[i][j] == '#') {
vis[i][j] = 0;
}
if(vis[i][j]) {
vis[i + 1][j] = 1;
pre[i + 1][j] = 0;
vis[i][j + 1] = 1;
pre[i][j + 1] = 1;
}
}
}
if(vis[n][m]){
cout << "TAK\n";
string s(n, 'N'), t(m, 'N'), p;
auto row = [&] (int x) {
s[x - 1] = 'T';
for(int i = 1; i <= m; i ++) {
if(str[x][i] == '@') str[x][i] = 'O';
else if(str[x][i] == 'O') str[x][i] = '@';
}
};
auto col = [&] (int x) {
t[x - 1] = 'T';
for(int i = 1; i <= n; i ++) {
if(str[i][x] == '@') str[i][x] = 'O';
else if(str[i][x] == 'O') str[i][x] = '@';
}
};
function<void(int, int)> dfs = [&] (int x, int y) {
if(x == 1 && y == 1) {
if(str[x][y] == '@') row(1);
return ;
}
if(pre[x][y]) {
dfs(x, y - 1);
p += "P";
if(str[x][y] == '@') col(y);
}
else {
dfs(x - 1, y);
p += "D";
if(str[x][y] == '@') row(x);
}
};
dfs(n, m);
cout << s << '\n' << t << '\n' << p << '\n';
} else {
cout << "NIE\n";
}
}
int main() {
//freopen("in.txt", "r", stdin);
ios::sync_with_stdio(false), cin.tie(0);
int T;
for(cin >> T; T; T --) {
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 128ms
memory: 38916kb
input:
486 4 5 ..#.. @@O@@ ##@#O ..@.@ 2 2 OO OO 2 2 @@ @@ 2 2 @@ #@ 2 2 @O #@ 2 2 @@ OO 2 2 O# @O 2 2 @# #@ 2 2 @. .@ 2 2 @# .O 2 2 OO .O 10 10 @O@O#O@@@# OO#@#@@#OO #@#@#O##O@ OO##@@O#@O O##@@#@O#@ OO@OO@@@O@ @O#@#@O#@O @OOOOO@##. O@OOO##O@@ OO@@OOOO#@ 10 10 @@#OOO#O@@ #@@OO@@.O@ #.O@@O#@@O OO@@#O@#O@ .#...
output:
TAK NTNN NNTNT DPPDDPP TAK NN NN DP TAK TT NN DP TAK TT NN PD TAK TN NT PD TAK TN NN DP TAK NT NT DP NIE TAK TN NT DP TAK TN NN DP TAK NN NN DP NIE TAK TTNNTTTTNT NNTTNNTTNN PDDDPPDDDDPPDDPPPP TAK NTTTNTNNNN NTTTNTNTTN DDDDDPDDDPPPPPDPPP TAK NNNTNTTTNT NNTTTTTNNT DDDPPDPDDDDDPPPPPP TAK NNNTNNNTNT NN...
result:
ok ac (486 test cases)
Extra Test:
score: 0
Extra Test Passed