QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#91180#5102. Dungeon Crawler_skb_WA 1ms5668kbC++174.2kb2023-03-27 16:42:392023-03-27 16:42:42

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-03-27 16:42:42]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:5668kb
  • [2023-03-27 16:42:39]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;

using i64 = long long;
using u64 = unsigned long long;

struct debug {
#define contPrint { *this << "["; \
        int f = 0; for(auto it : x) { *this << (f?", ":""); *this << it; f = 1;} \
        *this << "]"; return *this;}
 
    ~debug(){cerr << endl;}
    template<class c> debug& operator<<(c x) {cerr << x; return *this;}
    template<class c, class d>
    debug& operator<<(pair<c, d> x) {*this << "(" << x.first << ", " << x.second << ")"; 
        return *this;}
    template<class c> debug& operator<<(vector<c> x) contPrint;
#undef contPrint
};

#define dbg(x) "[" << #x << ": " << x << "]  "
#define Wa() cerr << "[LINE: " << __LINE__ << "] -> "; debug() << 
#define FASTIO ios_base::sync_with_stdio(false); cin.tie(NULL);

const int N = 2002;
vector<pair<int, int>> G[N];
int max_path[N][N];
i64 max_path_cost[N][N][2];
int edge_cost[N][N];
int P[N][N];

i64 dfs(int cur, int root, int p)
{
    i64 mx = 0;
    i64 mx2 = 0;
    i64 which = -1;
    P[root][cur] = p;

    for(auto it : G[cur]) {
        if(it.first != p) {
            i64 x = dfs(it.first, root, cur) + it.second;
            if(x > mx) {
                mx2 = mx;
                mx = x;
                which = it.first;
            } else if(x == mx) {
                mx2 = mx;
            }
        }
    }
    max_path[root][cur] = which;
    max_path_cost[root][cur][0] = mx;
    max_path_cost[root][cur][1] = mx2;
    return mx;
}

int main() 
{
    int n, q;
    scanf("%d %d", &n, &q);

    i64 tot_cost = 0;

    for(int i = 1; i < n; i++) {
        int u, v, w;
        scanf("%d %d %d", &u, &v, &w);
        G[u].push_back({v, w});
        G[v].push_back({u, w});
        edge_cost[u][v] = w;
        edge_cost[v][u] = w;
        tot_cost += w + w;
    }

    for(int i = 1; i <= n; i++) dfs(i, i, 0);

    int stk[N];
    int idx = 0;

    int vis[N];
    memset(vis, 0, sizeof vis);

    // Wa() dbg(tot_cost);

    while(q--) {
        int root, key, trap;
        scanf("%d %d %d", &root, &key, &trap);

        int cur = key;
        while(cur != root) {
            stk[idx++] = cur;
            vis[cur] = 1;
            cur = P[root][cur];
        }
        stk[idx++] = cur;
        vis[cur] = 1;

        if(vis[trap]) {
            puts("impossible");
        } else {
            int lca = trap;
            while(!vis[lca]) {
                lca = P[root][lca];
            }

            i64 tot = 0;
            cur = key;
            while(cur != lca) {
                tot += edge_cost[cur][P[root][cur]];
                cur = P[root][cur];
            }

            i64 lca_to_root_cost = 0;
            cur = lca;
            while(cur != root) {
                lca_to_root_cost += edge_cost[cur][P[root][cur]];
                cur = P[root][cur];
            }

            i64 ans = 1e18;
            cur = key;
            int prv = cur;
            bool lca_found = false;

            if(cur == lca) {
                lca_found = true;
            }

            while(cur != root) {
                if(max_path[root][cur] != prv) {
                    ans = min(ans, tot_cost + tot - max_path_cost[root][cur][0] - lca_to_root_cost);
                } else {
                    ans = min(ans, tot_cost + tot - max_path_cost[root][cur][1] - lca_to_root_cost);
                }

                prv = cur;
                cur = P[root][cur];

                if(!lca_found) {
                    tot -= edge_cost[prv][cur];
                } else {
                    lca_to_root_cost -= edge_cost[prv][cur];
                }

                if(cur == lca) {
                    lca_found = true;
                }
            }
            if(max_path[root][cur] != prv) {
                ans = min(ans, tot_cost + tot - max_path_cost[root][cur][0] - lca_to_root_cost);
            } else {
                ans = min(ans, tot_cost + tot - max_path_cost[root][cur][1] - lca_to_root_cost);
            }
            // Wa() dbg(lca_to_root_cost);
            assert(lca_to_root_cost == 0);

            printf("%lld\n", ans);

        }

        while(idx > 0) {
            vis[stk[--idx]] = 0;
        }
    }
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 4000kb

input:

22 5
1 2 7
2 3 5
3 4 8
3 6 6
3 7 3
2 5 6
5 8 2
8 9 11
2 10 16
1 11 12
11 12 4
11 13 9
1 14 25
14 15 4
15 16 5
15 17 6
15 18 1
15 19 8
14 20 7
20 21 9
20 22 17
1 19 9
1 9 19
1 8 9
1 9 8
2 22 11

output:

316
293
293
impossible
314

result:

ok 5 lines

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 5668kb

input:

100 100
1 2 289384
2 3 930887
2 4 692778
4 5 636916
4 6 747794
4 7 238336
4 8 885387
8 9 760493
8 10 516650
8 11 641422
8 12 202363
8 13 490028
8 14 368691
8 15 520060
8 16 897764
16 17 513927
16 18 180541
16 19 383427
16 20 89173
16 21 455737
16 22 5212
16 23 595369
16 24 702568
16 25 956430
16 26 ...

output:

103526917
103484292
107245246
104379596
104405611
104775512
105434682
105291604
103838430
105371370
104677980
104175650
105894571
104509242
103971939
105376499
105223283
104153426
105082245
105413188
104130613
104800548
107845726
104138329
103769253
105456754
104044745
104385328
107353400
105460460
...

result:

wrong answer 3rd lines differ - expected: '106288816', found: '107245246'