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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#84567 | #4511. Wonderland Chase | Booksnow | 0 | 1677ms | 22668kb | C++14 | 2.2kb | 2023-03-06 15:55:50 | 2023-03-06 15:55:53 |
Judging History
answer
#include <bits/stdc++.h>
#define st first
#define nd second
#define db double
#define re register
#define pb push_back
#define mk make_pair
//#define int long long
#define ldb long double
#define pii pair<int, int>
#define ull unsigned long long
#define mst(a, b) memset(a, b, sizeof(a))
using namespace std;
const int N = 1e5 + 10;
inline int read()
{
int s = 0, w = 1;
char ch = getchar();
while(ch < '0' || ch > '9') { if(ch == '-') w *= -1; ch = getchar(); }
while(ch >= '0' && ch <= '9') s = s * 10 + ch - '0', ch = getchar();
return s * w;
}
int T, n, m, A, Q, ans;
int st, ed, q[N], dir[N], dis[2][N];
bool vis[N], chk[N]; //是否是安全点
vector<int> G[N];
inline void BFS(int s, int op)
{
for(re int i = 1; i <= n; i++) dis[op][i] = -1;
dis[op][s] = 0, st = 1, ed = 0, q[++ed] = s;
while(st <= ed){
int u = q[st]; st++;
for(re int to : G[u])
if(dis[op][to] == -1) dis[op][to] = dis[op][u] + 1, q[++ed] = to;
}
}
inline void DFS(int u)
{
chk[u] = true;
if(G[u].size() == 1) ans = max(ans, dis[1][u]); //找到一个叶子然后不动
for(re int to : G[u])
if(to != Q && !chk[to] && !vis[to]) DFS(to);
}
inline void Sol(int Cas)
{
n = read(), m = read(), A = read(), Q = read();
if(Cas == 11) cout << n << " " << m << " " << A << " " << Q << "\n";
for(re int i = 1; i <= n; i++) G[i].clear(), vis[i] = true, chk[i] = false, dir[i] = 0;
for(re int i = 1, x, y; i <= m; i++){
x = read(), y = read(), G[x].pb(y), G[y].pb(x), dir[x]++, dir[y]++;
if(Cas == 11) cout << x << " " << y << "\n";
}
st = 1, ed = 0;
for(re int i = 1; i <= n; i++) if(dir[i] == 1) q[++ed] = i;
while(st <= ed){
int u = q[st];
st++, vis[u] = false;
for(re int to : G[u]){
if(!vis[to]) continue;
dir[to] -= 1;
if(dir[to] == 1) q[++ed] = to;
}
}
BFS(A, 0), BFS(Q, 1);
if(dis[0][Q] == -1) { printf("Case #%d: SAFE\n", Cas); return; } //不在一个联通块
for(re int i = 1; i <= n; i++)
if(vis[i] && dis[0][i] < dis[1][i]) { printf("Case #%d: SAFE\n", Cas); return; }
ans = 0, DFS(A);
//printf("Case #%d: %d\n", Cas, 2 * ans);
}
signed main()
{
T = read();
for(re int Cas = 1; Cas <= T; Cas++) Sol(Cas);
return 0;
}
Details
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Test #1:
score: 0
Wrong Answer
time: 4ms
memory: 7404kb
input:
100 2 1 1 2 1 2 3 3 1 2 1 3 1 2 2 3 6 6 5 1 1 4 5 6 3 4 3 6 2 3 1 2 6 6 2 4 4 5 1 4 2 3 2 5 1 6 5 6 6 6 2 3 1 3 3 4 2 6 2 5 4 5 1 5 6 5 5 3 2 5 3 4 1 2 3 6 4 6 6 5 1 6 1 4 1 2 5 6 3 5 2 4 30 29 11 5 9 21 25 28 14 20 13 30 21 28 5 18 5 23 8 22 10 30 4 8 7 24 16 26 13 26 12 18 22 23 11 16 3 11 2 17 1 ...
output:
Case #2: SAFE Case #5: SAFE Case #6: SAFE Case #7: SAFE Case #8: SAFE Case #9: SAFE 5 4 5 2 1 4 4 5 2 4 1 3 Case #13: SAFE Case #26: SAFE Case #27: SAFE Case #28: SAFE Case #29: SAFE Case #30: SAFE Case #31: SAFE Case #32: SAFE Case #33: SAFE Case #34: SAFE Case #44: SAFE Case #45: SAFE Case #46: SA...
result:
wrong answer 1st lines differ - expected: 'Case #1: 2', found: 'Case #2: SAFE'
Test #2:
score: 0
Wrong Answer
time: 1677ms
memory: 22668kb
input:
100 100000 99999 32832 52005 67463 96972 10280 86580 12146 44520 41541 86634 46936 64223 22701 46291 9093 80967 52512 77386 51062 58931 2092 55026 2096 2384 85102 92986 39914 66949 33370 68952 41576 58836 27668 33997 5843 30705 44415 57721 15188 28706 23340 55082 20335 90872 16029 80328 4656 74633 8...
output:
Case #1: SAFE Case #2: SAFE Case #6: SAFE 50000 49999 36869 38739 20677 35326 7453 47835 12061 48322 20700 29334 26539 48467 6269 44227 1753 10855 3165 13308 3427 49492 25531 48343 20155 28436 313 16576 16574 34982 12841 14125 28758 41758 26362 45007 1827 46165 40661 40720 10612 31732 29888 30489 41...
result:
wrong answer 3rd lines differ - expected: 'Case #3: 8', found: 'Case #6: SAFE'