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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#84555#4511. Wonderland ChaseBooksnow0 1735ms22564kbC++142.1kb2023-03-06 15:51:542023-03-06 15:51:55

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-03-06 15:51:55]
  • 评测
  • 测评结果:0
  • 用时:1735ms
  • 内存:22564kb
  • [2023-03-06 15:51:54]
  • 提交

answer

#include <bits/stdc++.h>
#define st first
#define nd second
#define db double
#define re register
#define pb push_back
#define mk make_pair
//#define int long long
#define ldb long double
#define pii pair<int, int>
#define ull unsigned long long 
#define mst(a, b) memset(a, b, sizeof(a))
using namespace std;
const int N = 1e5 + 10;
inline int read()
{
	
  int s = 0, w = 1;
  char ch = getchar();
  while(ch < '0' || ch > '9') { if(ch == '-') w *= -1; ch = getchar(); }
  while(ch >= '0' && ch <= '9') s = s * 10 + ch - '0', ch = getchar();
  return s * w;
}
int T, n, m, A, Q, ans;
int st, ed, q[N], dir[N], dis[2][N];
bool vis[N], chk[N]; //是否是安全点 
vector<int> G[N];
inline void BFS(int s, int op)
{
	for(re int i = 1; i <= n; i++) dis[op][i] = -1;
	dis[op][s] = 0, st = 1, ed = 0, q[++ed] = s;
	while(st <= ed){
		int u = q[st]; st++;
		for(re int to : G[u])
			if(dis[op][to] == -1) dis[op][to] = dis[op][u] + 1, q[++ed] = to;
	}
}
inline void DFS(int u)
{
	chk[u] = true;
	if(G[u].size() == 1) ans = max(ans, dis[1][u]); //找到一个叶子然后不动 
	for(re int to : G[u])
		if(to != Q && !chk[to] && !vis[to]) DFS(to); 
}
inline void Sol(int Cas)
{
	n = read(), m = read(), A = read(), Q = read();
	for(re int i = 1; i <= n; i++) G[i].clear(), vis[i] = true, chk[i] = false, dir[i] = 0; 
	for(re int i = 1, x, y; i <= m; i++)
		x = read(), y = read(), G[x].pb(y), G[y].pb(x), dir[x]++, dir[y]++;
	st = 1, ed = 0;
	for(re int i = 1; i <= n; i++) if(dir[i] == 1) q[++ed] = i;
	while(st <= ed){
		int u = q[st];
		st++, vis[u] = false;
		for(re int to : G[u]){
			if(!vis[to]) continue;
			dir[to] -= 1;
			if(dir[to] == 1) q[++ed] = to;
		}
	}
	BFS(A, 0), BFS(Q, 1);
	if(dis[0][Q] == -1) { printf("Case #%d: SAFE\n", Cas); return; } //不在一个联通块 
	for(re int i = 1; i <= n; i++)
		if(vis[i] && dis[0][i] < dis[1][i]) { printf("Case #%d: SAFE\n", Cas); return; }
	ans = 0, DFS(A);
	printf("Case #%d: %d\n", Cas, 2 * ans);
}
signed main()
{
	T = read();
	for(re int Cas = 1; Cas <= T; Cas++) Sol(Cas);
	return 0;
}

Details

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Test #1:

score: 0
Wrong Answer
time: 3ms
memory: 5832kb

input:

100
2 1 1 2
1 2
3 3 1 2
1 3
1 2
2 3
6 6 5 1
1 4
5 6
3 4
3 6
2 3
1 2
6 6 2 4
4 5
1 4
2 3
2 5
1 6
5 6
6 6 2 3
1 3
3 4
2 6
2 5
4 5
1 5
6 5 5 3
2 5
3 4
1 2
3 6
4 6
6 5 1 6
1 4
1 2
5 6
3 5
2 4
30 29 11 5
9 21
25 28
14 20
13 30
21 28
5 18
5 23
8 22
10 30
4 8
7 24
16 26
13 26
12 18
22 23
11 16
3 11
2 17
1 ...

output:

Case #1: 2
Case #2: SAFE
Case #3: 8
Case #4: 6
Case #5: SAFE
Case #6: SAFE
Case #7: SAFE
Case #8: SAFE
Case #9: SAFE
Case #10: 8
Case #11: 6
Case #12: 2
Case #13: SAFE
Case #14: 2
Case #15: 10
Case #16: 10
Case #17: 6
Case #18: 2
Case #19: 28
Case #20: 28
Case #21: 18
Case #22: 2
Case #23: 58
Case #...

result:

wrong answer 11th lines differ - expected: 'Case #11: 4', found: 'Case #11: 6'

Test #2:

score: 0
Wrong Answer
time: 1735ms
memory: 22564kb

input:

100
100000 99999 32832 52005
67463 96972
10280 86580
12146 44520
41541 86634
46936 64223
22701 46291
9093 80967
52512 77386
51062 58931
2092 55026
2096 2384
85102 92986
39914 66949
33370 68952
41576 58836
27668 33997
5843 30705
44415 57721
15188 28706
23340 55082
20335 90872
16029 80328
4656 74633
8...

output:

Case #1: SAFE
Case #2: SAFE
Case #3: 8
Case #4: 6
Case #5: 2
Case #6: SAFE
Case #7: 2
Case #8: 39998
Case #9: 39998
Case #10: 19192
Case #11: 2
Case #12: 99998
Case #13: 99998
Case #14: 16776
Case #15: 2
Case #16: 199998
Case #17: 199998
Case #18: 141806
Case #19: SAFE
Case #20: SAFE
Case #21: SAFE
...

result:

wrong answer 4th lines differ - expected: 'Case #4: 4', found: 'Case #4: 6'