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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#83597 | #1872. Game | woxiangbaile# | AC ✓ | 502ms | 12468kb | C++14 | 5.8kb | 2023-03-02 17:32:49 | 2023-03-02 17:32:53 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define rep(i, d, u) for(int i = d; i <= u; ++i)
#define dep(i, u, d) for(int i = u; i >= d; --i)
#define cep(n) while(n--)
#define gep(i, a) for(int i = firs[a]; i; i = neig[i])
int ured() {
int re = 0;
char ch;
do {
ch = getchar();
} while('9' < ch || ch < '0');
do {
re = re * 10 + (ch ^ '0');
} while('0' <= (ch = getchar()) && ch <= '9');
return re;
}
void uwit(int da) {
int ch[21], cn = 0;
do {
ch[++cn] = da - da / 10 * 10;
} while(da /= 10);
do {
putchar('0' ^ ch[cn]);
} while(--cn);
}
const int _maxn = 100011, _zinf = 1000000001;
struct dats {
int po, ln, ma, mi, va, ls, rs, lz;
} tree[_maxn * 151];
void push(int at) {
if(tree[at] . lz) {
if(tree[at] . ls) {
tree[tree[at] . ls] . lz += tree[at] . lz;
}
if(tree[at] . rs) {
tree[tree[at] . rs] . lz += tree[at] . lz;
}
tree[at] . ln += tree[at] . lz, tree[at] . mi += tree[at] . lz, tree[at] . lz = 0;
}
}
void upda(int at) {
tree[at] . mi = tree[at] . ln, tree[at] . ma = tree[at] . po;
if(tree[at] . ls) {
push(tree[at] . ls);
if(tree[tree[at] . ls] . mi < tree[at] . mi) {
tree[at] . mi = tree[tree[at] . ls] . mi, tree[at] . ma = tree[tree[at] . ls] . ma;
}
}
if(tree[at] . rs) {
push(tree[at] . rs);
if(tree[tree[at] . rs] . mi < tree[at] . mi) {
tree[at] . mi = tree[tree[at] . rs] . mi, tree[at] . ma = tree[tree[at] . rs] . ma;
}
}
}
void merg(int le, int ri, int &at) {
if(!le || !ri) {
at = le + ri;
return;
}
if(tree[le] . va < tree[ri] . va) {
at = le, push(le), merg(tree[le] . rs, ri, tree[at] . rs);
} else {
at = ri, push(ri), merg(le, tree[ri] . ls, tree[at] . ls);
}
upda(at);
}
void spil(int &le, int &ri, int at, int po) {
if(!at) {
le = ri = 0;
return;
}
push(at);
if(tree[at] . po < po) {
le = at, spil(tree[le] . rs, ri, tree[at] . rs, po), upda(le);
} else {
ri = at, spil(le, tree[ri] . ls, tree[at] . ls, po), upda(ri);
}
}
int lens;
int finl(int at, int po) {
if(!at) {
return -_zinf;
}
push(at);
if(tree[at] . po <= po && po <= tree[at] . po + tree[at] . ln - 1) {
lens += tree[at] . ln;
return tree[at] . po;
} else if(po < tree[at] . po) {
return finl(tree[at] . ls, po);
} else {
return finl(tree[at] . rs, po);
}
}
int finr(int at, int po) {
if(!at) {
return -_zinf;
}
push(at);
if(tree[at] . po - tree[at] . ln + 1 <= po && po <= tree[at] . po) {
lens += tree[at] . ln;
return tree[at] . po;
} else if(po < tree[at] . po) {
return finr(tree[at] . ls, po);
} else {
return finr(tree[at] . rs, po);
}
}
mt19937 tran(1);
int lrot, rrot, latp, matp, ratp, cnts, latc, ratc;
void insp(int &at, int po, int ln = 1) {
++cnts, tree[cnts] . po = tree[cnts] . ma = po, tree[cnts] . mi = tree[cnts] . ln = ln;
tree[cnts] . ls = tree[cnts] . rs = tree[cnts] . lz = 0, tree[cnts] . va = tran();
spil(latp, ratp, at, po), merg(latp, cnts, latp), merg(latp, ratp, at);
}
void mant();
void eras(int &at, int po, int da = -_zinf, bool st = 0) {
spil(latc, at, at, po), spil(at, ratc, at, po + 1);
if(da != -_zinf) {
if(st) {
insp(latc, tree[at] . po, da - tree[at] . po), insp(ratc, da + 1, tree[at] . po + tree[at] . ln - da - 1);
} else {
insp(latc, da - 1, da - tree[at] . po + tree[at] . ln - 1), insp(ratc, tree[at] . po, tree[at] . po - da);
}
}
merg(latc, ratc, at);
if(da != -_zinf) {
mant();
}
}
void mant() {
int la, ra, ln;
while(lrot) {
push(lrot);
if(tree[lrot] . mi) {
break;
} else {
lens = 0, la = finr(rrot, tree[lrot] . ma - 1), ra = finr(rrot, tree[lrot] . ma);
eras(rrot, la), eras(rrot, ra), insp(rrot, ra, lens), eras(lrot, tree[lrot] . ma);
}
}
while(rrot) {
push(rrot);
if(tree[rrot] . mi) {
break;
} else {
lens = 0, la = finl(lrot, tree[rrot] . ma), ra = finl(lrot, tree[rrot] . ma + 1);
eras(lrot, la), eras(lrot, ra), insp(lrot, la, lens), eras(rrot, tree[rrot] . ma);
}
}
}
int atti, atpo;
void inse(int po, bool da) {
int re;
if(atti & 1 ^ da) {
if((re = finr(rrot, po)) != -_zinf) {
insp(lrot, po), eras(rrot, re, po, 0);
}
} else {
if((re = finl(lrot, po)) != -_zinf) {
insp(rrot, po), eras(lrot, re, po, 1);
}
}
}
int t, n, q, l[_maxn], r[_maxn], z[_maxn], aran[_maxn], a[_maxn], b[_maxn], bran[_maxn], frti;
bool rans[_maxn];
int main() {
t = ured();
cep(t) {
n = ured(), q = ured();
rep(i, 1, n) {
l[aran[i] = i] = ured(), r[i] = ured(), z[i] = ured();
}
rep(i, 1, q) {
a[bran[i] = i] = ured(), b[i] = ured();
}
sort(aran + 1, aran + n + 1, [](int le, int ri) {
return r[le] - l[le] < r[ri] - l[ri];
}), sort(bran + 1, bran + q + 1, [](int le, int ri) {
return b[le] - a[le] < b[ri] - a[ri];
}), atti = -1, atpo = lrot = rrot = cnts = 0, insp(rrot, _zinf + 10, _zinf << 1);
rep(i, 1, q) {
while(atti < b[bran[i]] - a[bran[i]]) {
push(lrot), push(rrot), frti = atti;
if(tree[lrot] . mi + (((atti & 1) << 1) - 1) && tree[rrot] . mi + (((atti & 1 ^ 1) << 1) - 1)) {
atti = min(b[bran[i]] - a[bran[i]], atpo == n ? _zinf : r[aran[atpo + 1]] - l[aran[atpo + 1]]);
} else {
++atti;
}
if((frti ^ atti) & 1) {
if(atti & 1) {
if(lrot) {
--tree[lrot] . lz;
}
if(rrot) {
++tree[rrot] . lz;
}
} else {
if(lrot) {
++tree[lrot] . lz;
}
if(rrot) {
--tree[rrot] . lz;
}
}
}
mant();
while(atpo + 1 <= n && r[aran[atpo + 1]] - l[aran[atpo + 1]] == atti) {
++atpo, inse(l[aran[atpo]] + r[aran[atpo]] >> 1, z[aran[atpo]]);
}
}
rans[bran[i]] = (finl(lrot, a[bran[i]] + b[bran[i]] >> 1) != -_zinf) ^ (atti & 1);
}
rep(i, 1, q) {
putchar('0' ^ rans[i]);
}
putchar('\n');
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 2ms
memory: 3404kb
input:
1 5 10 1 2 0 3 3 1 3 4 1 2 4 1 1 3 0 1 2 1 3 1 4 1 5 2 3 2 4 2 5 3 4 3 5 4 5
output:
0010111101
result:
ok single line: '0010111101'
Test #2:
score: 0
Accepted
time: 502ms
memory: 12468kb
input:
1004 100000 100000 500000000 500000000 1 500000000 500000002 1 500000000 500000004 1 500000000 500000006 0 500000000 500000008 1 500000000 500000010 0 500000000 500000012 0 500000000 500000014 1 500000000 500000016 0 500000000 500000018 1 500000000 500000020 0 500000000 500000022 1 500000000 5000000...
output:
000001100000000111001010000111001111110010000101100101101000101010101010000100100100101010011011110110001100000000100101000000000000000101000000000010100110110101000001000111110000100010110000100111110101101010011000000100000000001001011011101000100000011000111111100010001111010001000010001110001110...
result:
ok 1004 lines