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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#808645 | #8551. DFS Order 5 | ucup-team2179 | WA | 44ms | 3840kb | C++20 | 3.3kb | 2024-12-10 23:00:31 | 2024-12-10 23:00:31 |
Judging History
answer
#include<bits/stdc++.h>
#define int long long
#define pb push_back
#define pii pair<int, int>
using namespace std;
struct ollca{
vector<vector<int> > adj;
vector<int>L;
vector<int>dfn;
vector<int>siz;
vector<int>fa;
int cnt=0,n;
vector<vector<int> >mylist;
void dfs(int u,int f){
cnt++;
dfn[cnt]=u;
L[u]=cnt;
siz[u]++;
for(auto p:adj[u]){
if(p==f)continue;
fa[p]=u;
dfs(p,u);
cnt++;
dfn[cnt]=u;
siz[u]+=siz[p];
}
}
int op(int l,int r){
if(L[l]<L[r])return l;
return r;
};
ollca(){}
ollca(vector<vector<int> > a,int root){
adj=a;
n=a.size()-1;
L.resize(n+1);
fa.resize(n+1);
siz.resize(n+1);
dfn.resize(n*2);
dfs(root,0);
mylist=vector<vector<int>>(2*n+1,vector<int>(__lg(2*n-1)+1));
for(int i=1;i<=2*n-1;i++)
mylist[i][0]=dfn[i];
for(int j=1;j<=__lg(2*n-1);j++)
for(int i=1;i<=2*n-1-(1<<j)+1;i++)
mylist[i][j]=op(mylist[i][j-1],mylist[i+(1<<j-1)][j-1]);
}
int lca(int l,int r){
l=L[l];
r=L[r];
if(l>r)swap(l,r);
int len=__lg(r-l+1);
return op(mylist[l][len],mylist[r-(1<<len)+1][len]);
}
}tr;
int LCA(int u, int v) {
return tr.lca(u, v);
}
struct stable {
vector<vector<int>> mylist;
int n;
int (*op) (int a, int b);
stable(vector<int>&a, int(*f)(int, int)) {
op = f;
n = a.size() - 1;
mylist = vector<vector<int>> (n + 1, vector<int>(__lg(n) + 1));
for (int i = 1; i <= n; i++) mylist[i][0] = a[i];
for (int j = 1; j <= __lg(n); j++)
for (int i = 1; i <= n - (1 << j) + 1; i++)
mylist[i][j] = op(mylist[i][j - 1], mylist[i + (1 << j - 1)][j - 1]);
}
int q(int l, int r) {
assert(l >= 1 && r <= n && l <= r);
int len = __lg(r - l + 1);
return op(mylist[l][len], mylist[r - (1 << len) + 1][len]);
}
};
void solve() {
int n, q; cin >> n >> q;
vector<vector<int> > a(n+1);
for (int i = 1; i < n; i++) {
int u, v; cin >> u >> v;
a[u].push_back(v);
a[v].push_back(u);
}
tr=ollca(a,1);
while (q--) {
int k; cin >> k;
set<int> s;
vector<int> arr(k + 1);
for (int i = 1; i <= k; i++) cin >> arr[i], s.insert(arr[i]);
if (s.size() != k) {
cout << "No\n";
continue;
}
s.clear();
stable st(arr, LCA);
int flag = 1;
for (int i = 1; i < k && flag; i++)
flag &= (LCA(arr[i], arr[i + 1]) == tr.fa[arr[i + 1]]);
for (int i = 1; i <= k && flag; i++) {
flag &= (arr[i] == st.q(i, min(k, i + tr.siz[arr[i]] - 1)));
}
for (int i = 1; i <= k && flag; i++) {
if(s.lower_bound(tr.L[arr[i]])!=s.end()&&*s.lower_bound(tr.L[arr[i]])<=tr.L[arr[i]]+tr.siz[arr[i]]-1)flag=0;
s.insert(tr.L[arr[i]]);
}
if (flag) cout << "Yes\n";
else cout << "No\n";
}
}
signed main() {
ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int t = 1;
// cin >> t;
while (t--) solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3600kb
input:
6 7 1 2 1 3 2 4 3 5 2 6 2 4 1 2 4 2 2 4 3 2 4 4 2 4 5 2 4 6 6 1 2 6 4 3 5
output:
No No Yes No No Yes Yes
result:
ok 7 tokens
Test #2:
score: -100
Wrong Answer
time: 44ms
memory: 3840kb
input:
10 100000 7 2 1 7 7 10 8 6 8 7 1 3 4 5 9 5 5 8 8 8 9 7 2 8 1 6 1 4 8 3 5 2 6 7 10 3 9 9 1 1 1 8 10 3 2 9 3 8 7 3 7 5 6 2 8 5 9 1 6 3 4 6 2 1 3 5 8 9 2 4 9 1 3 2 1 5 5 8 5 1 7 9 10 5 2 9 2 6 4 10 6 3 8 3 4 5 8 2 8 4 9 4 10 1 2 4 3 3 6 3 1 3 6 1 1 6 8 3 1 3 7 3 2 3 9 1 5 4 3 7 8 10 9 4 2 3 10 2 5 4 3 ...
output:
No No No Yes No No No No Yes No No No No No No Yes No No No No No No No No No No No No No No No Yes No No No No No No Yes No No No No No Yes Yes No No No No No No No No No No No No No No No No No No No No No No No No Yes No No Yes Yes No No No No Yes No No No No No No No No No No No No No No No No N...
result:
wrong answer 3780th words differ - expected: 'No', found: 'Yes'