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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#795905 | #7103. Red Black Tree | ender_shayan | AC ✓ | 969ms | 27708kb | C++17 | 3.7kb | 2024-12-01 03:58:27 | 2024-12-01 03:58:28 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
//using namespace __gnu_pbds;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii ;
typedef pair<ll, ll> pll ;
typedef vector<pii> vii ;
typedef vector<int> veci ;
typedef vector<pll> vll ;
typedef vector<ll> vecll;
// find_by_order order_of_key
//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
#define F first
#define S second
#define pb push_back
#define endl '\n'
#define Mp make_pair
#define all(x) x.begin(), x.end()
#define debug(x) cerr << #x << " = " << x << endl
#define set_dec(x) cout << fixed << setprecision(x);
#define fast_io ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file_io freopen("in.txt" , "r" , stdin) ; freopen("out.txt" , "w" , stdout);
#define lb lower_bound
#define ub upper_bound
#define for1(n) for(int i=1;i<=n;i++)
#define for0(n) for(int i=0;i<n;i++)
#define forn(n) for(int i=n;i>0;i--)
#define pq priority_queue <pii, vector<pii>, greater<pii>>
ll mod = 1e9+7 ;// 998244353 ;// 1e9+9;
ll inf=1e18;
const int N=1e5+10,L=18;
int A[N],B[N],is[N],n,m,k,q,par[N][L],h[N],st[N],en[N],t;
vector<pii>g[N];
ll hh[N],rd[N];
void dfs1(int v,ll ww=0){
if(is[v])ww=0;
rd[v]=ww;
st[v]=++t;
for(auto [u,w]:g[v])if(u!=par[v][0]){
par[u][0]=v;
h[u]=h[v]+1;
hh[u]=hh[v]+w;
dfs1(u,ww+w);
}
en[v]=++t;
}
int LCA(int v1,int v2){
if(h[v1]<h[v2])swap(v1,v2);
int x=h[v1]-h[v2];
for(int j=0;j<L;j++)if(x>>j&1)v1=par[v1][j];
if(v1==v2)return v1;
for(int j=L-1;j>=0;j--)if(par[v1][j]!=par[v2][j]){
v1=par[v1][j];
v2=par[v2][j];
}
return par[v1][0];
}
int main(){
fast_io
int T;cin>>T;
while(T--){
cin>>n>>k>>q;
while(k--){
int x;cin>>x;
is[x]=1;
}
for1(n-1){
int u,v,w;cin>>u>>v>>w;
g[u].pb({v,w});
g[v].pb({u,w});
}
dfs1(1);
for(int j=1;j<L;j++)for1(n)par[i][j]=par[par[i][j-1]][j-1];
while(q--){
cin>>k;
vector<pii>vec;
vector<pii>vec2;
vector<pii> vec3;
pll MAX={0,0};
ll ans=0,tmp=0,ans3=0;
for1(k){
int v;cin>>v;
vec2.pb({st[v],v});
vec3.pb({en[v],v});
MAX=max(MAX,{rd[v],v});
ans=max(ans,rd[v]);
}
sort(all(vec2));sort(all(vec3));
int v=MAX.S;
for(auto[t,vv]:vec2){
int v2=LCA(v,vv);
ans3=max(ans3,min(rd[vv],hh[vv]-hh[v2]));
vec.pb({h[v2],v2});
}
sort(all(vec));
int l=0,r=k-1;
for(auto [t,vv]:vec){
while(vec2[l].F<st[vv]){
tmp=max(tmp,rd[vec2[l].S]);
l++;
}
while(vec3[r].F>en[vv]){
tmp=max(tmp,rd[vec3[r].S]);
r--;
}
ll ans2=max(tmp,hh[v]-hh[vv]);
ans=min(ans,ans2);
}
ans=max(ans,ans3);
cout<<ans<<endl;
}
t=0;
for1(n){g[i].clear();rd[i]=h[i]=hh[i]=is[i]=0;}
}
}
这程序好像有点Bug,我给组数据试试?
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 7612kb
input:
2 12 2 4 1 9 1 2 1 2 3 4 3 4 3 3 5 2 2 6 2 6 7 1 6 8 2 2 9 5 9 10 2 9 11 3 1 12 10 3 3 7 8 4 4 5 7 8 4 7 8 10 11 3 4 5 12 3 2 3 1 2 1 2 1 1 3 1 1 1 2 1 2 3 1 2 3
output:
4 5 3 8 0 0 0
result:
ok 7 lines
Test #2:
score: 0
Accepted
time: 969ms
memory: 27708kb
input:
522 26 1 3 1 1 4 276455 18 6 49344056 18 25 58172365 19 9 12014251 2 1 15079181 17 1 50011746 8 9 2413085 23 24 23767115 22 2 26151339 26 21 50183935 17 14 16892041 9 26 53389093 1 20 62299200 24 18 56114328 11 2 50160143 6 26 14430542 16 7 32574577 3 16 59227555 3 15 8795685 4 12 5801074 5 20 57457...
output:
148616264 148616264 0 319801028 319801028 255904892 317070839 1265145897 1265145897 1072765445 667742619 455103436 285643094 285643094 285643094 317919339 0 785245841 691421476 605409472 479058444 371688030 303203698 493383271 919185207 910180170 919185207 121535083 181713164 181713164 181713164 181...
result:
ok 577632 lines
Extra Test:
score: 0
Extra Test Passed