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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#790488#906. 强连通分量XY_ElevenWA 1ms3796kbC++204.5kb2024-11-28 12:35:032024-11-28 12:35:04

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你现在查看的是最新测评结果

  • [2024-11-28 12:35:04]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3796kb
  • [2024-11-28 12:35:03]
  • 提交

answer

#include <bits/stdc++.h>
// #include <windows.h>
#include <bits/extc++.h>
using namespace __gnu_pbds;
using namespace std;
//#pragma GCC optimize(3)
#define DB long double
#define LL long long
#define ULL unsigned long long
#define in128 __int128
#define cint const int
#define cLL const LL
#define For(z,e1,e2) for(int z=(e1);z<=(e2);z++)
#define Rof(z,e1,e2) for(int z=(e2);z>=(e1);z--)
#define For_(z,e1,e2) for(int z=(e1);z<(e2);z++)
#define Rof_(z,e1,e2) for(int z=(e2);z>(e1);z--)
#define inint(e) scanf("%d",&e)
#define inll(e) scanf("%lld",&e)
#define inpr(e1,e2) scanf("%d%d",&e1,&e2)
#define in3(e1,e2,e3) scanf("%d%d%d",&e1,&e2,&e3)
#define outint(e) printf("%d\n",e)
#define outint_(e) printf("%d%c",e," \n"[i==n])
#define outint2_(e,e1,e2) printf("%d%c",e," \n"[(e1)==(e2)])
#define outll(e) printf("%lld\n",e)
#define outll_(e) printf("%lld%c",e," \n"[i==n])
#define outll2_(e,e1,e2) printf("%lld%c",e," \n"[(e1)==(e2)])
#define exc(e) if(e) continue
#define stop(e) if(e) break
#define ret(e) if(e) return
#define ll(e) (1ll*(e))
#define pb push_back
#define ft first
#define sc second
#define pii pair<int,int> 
#define pli pair<long long,int> 
#define vct vector 
#define clean(e) while(!e.empty()) e.pop()
#define all(ev) ev.begin(),ev.end()
#define sz(ev) ((int)ev.size())
#define debug(x) printf("%s=%d\n",#x,x)
#define x0 __xx00__
#define y1 __yy11__
#define ffo fflush(stdout)
cLL mod=998244353,G=404;
// cLL mod[2]={1686688681ll,1666888681ll},base[2]={166686661ll,188868881ll};
template <typename Type> void get_min(Type &w1,const Type w2) { if(w2<w1) w1=w2; } template <typename Type> void get_max(Type &w1,const Type w2) { if(w2>w1) w1=w2; }
template <typename Type> Type up_div(Type w1,Type w2) { return (w1/w2+(w1%w2?1:0)); }
template <typename Type> Type gcd(Type X_,Type Y_) { Type R_=X_%Y_; while(R_) { X_=Y_; Y_=R_; R_=X_%Y_; } return Y_; } template <typename Type> Type lcm(Type X_,Type Y_) { return (X_/gcd(X_,Y_)*Y_); }
template <typename Type> Type md(Type w1,const Type w2=mod) { w1%=w2; if(w1<0) w1+=w2; return w1; } template <typename Type> Type md_(Type w1,const Type w2=mod) { w1%=w2; if(w1<=0) w1+=w2; return w1; }
void ex_gcd(LL &X_,LL &Y_,LL A_,LL B_) { if(!B_) { X_=1ll; Y_=0ll; return ; } ex_gcd(Y_,X_,B_,A_%B_); X_=md(X_,B_); Y_=(1ll-X_*A_)/B_; } LL inv(LL A_,LL B_=mod) { LL X_=0ll,Y_=0ll; ex_gcd(X_,Y_,A_,B_); return X_; }
template <typename Type> void add(Type &w1,const Type w2,const Type M_=mod) { w1=md(w1+w2,M_); } void mul(LL &w1,cLL w2,cLL M_=mod) { w1=md(w1*md(w2,M_),M_); } template <typename Type> Type pw(Type X_,Type Y_,Type M_=mod) { Type S_=1; while(Y_) { if(Y_&1) mul(S_,X_,M_); Y_>>=1; mul(X_,X_,M_); } return S_; }
template <typename Type> Type bk(vector <Type> &V_) { auto T_=V_.back(); V_.pop_back(); return T_; } template <typename Type> Type tp(stack <Type> &V_) { auto T_=V_.top(); V_.pop(); return T_; } template <typename Type> Type frt(queue <Type> &V_) { auto T_=V_.front(); V_.pop(); return T_; }
template <typename Type> Type bg(set <Type> &V_) { auto T_=*V_.begin(); V_.erase(V_.begin()); return T_; } template <typename Type> Type bk(set <Type> &V_) { auto T_=*prev(V_.end()); V_.erase(*prev(V_.end())); return T_; }
mt19937 gen(43); int rd() { return abs((int)gen()); }
int rnd(int l,int r) { return rd()%(r-l+1)+l; }
void main_init()
{
    
}
cint N=5.01e5;
int n,m;
vct <int> v[N];
int dfn[N],low[N],id;
bool ins[N]; stack <int> st;
vct <vct<int> > scc;
void dfs(int p)
{
    dfn[p]=low[p]=++id;
    st.push(p),ins[p]=true;
    for(auto i:v[p])
    {
        if(!dfn[i])
        {
            dfs(i);
            get_min(low[p],low[i]);
        }
        else if(ins[i])
            get_min(low[p],dfn[i]);
    }
    ret(low[p]!=dfn[p]);
    scc.pb({});
    while(true)
    {
        int t=st.top();
        st.pop(),ins[t]=false;
        scc.back().pb(t);
        stop(t==p);
    }
}
void main_solve()
{
    inpr(n,m);
    while(m--)
    {
        int x,y; inpr(x,y); x++,y++;
        v[x].pb(y);
    }
    id=0;
    For(i,1,n) if(!dfn[i])
        dfs(i);
    outint(sz(scc));
    for(auto &i:scc)
    {
        printf("%d",sz(i));
        for(auto p:i) printf(" %d",p-1);
        printf("\n");
    }
}
int main()
{
    // ios::sync_with_stdio(0); cin.tie(0);
    // freopen("in.txt","r",stdin);
    // freopen("out.txt","w",stdout);
    // srand(time(NULL));
    main_init();
    // int _; inint(_); For(__,1,_) // T>1 ?
        // printf("\n------------\n\n"),
        main_solve();
    return 0;
}
/*

*/

Details

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Test #1:

score: 0
Wrong Answer
time: 1ms
memory: 3796kb

input:

6 7
1 4
5 2
3 0
5 5
4 1
0 3
4 2

output:

4
2 3 0
1 2
2 4 1
1 5

result:

wrong answer 5 is later than 2, but there is an edge (5, 2)