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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#770239#8049. Equal SumsLu_xZTL 0ms3576kbC++201.0kb2024-11-21 21:13:242024-11-21 21:13:24

Judging History

你现在查看的是最新测评结果

  • [2024-11-21 21:13:24]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:3576kb
  • [2024-11-21 21:13:24]
  • 提交

answer

#include<bits/stdc++.h>
#define eb emplace_back
#define ep emplace
using namespace std;

using ll = long long;
constexpr int N = 505, mod = 998244353;

int n, m, f[N][N][N << 1];
struct {int l, r;} a[N], b[N];


int main() {
	cin.tie(0)->sync_with_stdio(0);
	cin >> n >> m;
	for(int i = 0; i < n; ++ i) cin >> a[i].l >> a[i].r;
	for(int i = 0; i < m; ++ i) cin >> b[i].l >> b[i].r;
	f[0][0][500] = 1;
	for(int i = 0; i <= n; ++ i) {
		for(int j = 0; j <= m; ++ j) {
			if(i < n) {
				for(int k = 0; k <= 500; ++ k) {
					if(!f[i][j][k]) continue;
					for(int x = a[i].l; x <= a[i].r; ++ x) {
						f[i + 1][j][k + x] = (f[i + 1][j][k + x] + f[i][j][k]) % mod;
					}
				}
			}
			if(j < m) {
				for(int k = 501; k <= 1000; ++ k) {
					if(!f[i][j][k]) continue;
					for(int x = b[j].l; x <= b[j].r; ++ x) {
						f[i][j + 1][k - x] = (f[i][j + 1][k - x] + f[i][j][k]) % mod;
					}
				}
			} 
		}
	}
	for(int i = 1; i <= n; ++ i) {
		for(int j = 1; j <= m; ++ j) cout << f[i][j][500] << " \n"[j == m];
	}
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3576kb

input:

2 3
1 2
2 3
1 4
2 2
1 3

output:

2 0 0
3 4 4

result:

ok 6 numbers

Test #2:

score: -100
Time Limit Exceeded

input:

500 500
19 458
1 480
7 485
50 461
12 476
15 461
48 466
40 453
46 467
9 458
27 478
26 472
46 459
29 490
6 500
17 487
48 484
28 472
28 459
25 480
4 491
29 481
36 460
2 491
44 499
22 473
20 458
4 483
27 471
2 496
11 461
43 450
2 478
37 466
15 459
42 482
7 451
19 455
2 453
47 475
48 450
1 474
46 471
9 4...

output:


result: