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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#770239 | #8049. Equal Sums | Lu_xZ | TL | 0ms | 3576kb | C++20 | 1.0kb | 2024-11-21 21:13:24 | 2024-11-21 21:13:24 |
Judging History
answer
#include<bits/stdc++.h>
#define eb emplace_back
#define ep emplace
using namespace std;
using ll = long long;
constexpr int N = 505, mod = 998244353;
int n, m, f[N][N][N << 1];
struct {int l, r;} a[N], b[N];
int main() {
cin.tie(0)->sync_with_stdio(0);
cin >> n >> m;
for(int i = 0; i < n; ++ i) cin >> a[i].l >> a[i].r;
for(int i = 0; i < m; ++ i) cin >> b[i].l >> b[i].r;
f[0][0][500] = 1;
for(int i = 0; i <= n; ++ i) {
for(int j = 0; j <= m; ++ j) {
if(i < n) {
for(int k = 0; k <= 500; ++ k) {
if(!f[i][j][k]) continue;
for(int x = a[i].l; x <= a[i].r; ++ x) {
f[i + 1][j][k + x] = (f[i + 1][j][k + x] + f[i][j][k]) % mod;
}
}
}
if(j < m) {
for(int k = 501; k <= 1000; ++ k) {
if(!f[i][j][k]) continue;
for(int x = b[j].l; x <= b[j].r; ++ x) {
f[i][j + 1][k - x] = (f[i][j + 1][k - x] + f[i][j][k]) % mod;
}
}
}
}
}
for(int i = 1; i <= n; ++ i) {
for(int j = 1; j <= m; ++ j) cout << f[i][j][500] << " \n"[j == m];
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3576kb
input:
2 3 1 2 2 3 1 4 2 2 1 3
output:
2 0 0 3 4 4
result:
ok 6 numbers
Test #2:
score: -100
Time Limit Exceeded
input:
500 500 19 458 1 480 7 485 50 461 12 476 15 461 48 466 40 453 46 467 9 458 27 478 26 472 46 459 29 490 6 500 17 487 48 484 28 472 28 459 25 480 4 491 29 481 36 460 2 491 44 499 22 473 20 458 4 483 27 471 2 496 11 461 43 450 2 478 37 466 15 459 42 482 7 451 19 455 2 453 47 475 48 450 1 474 46 471 9 4...