QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#76569#4884. Battleship: New RulesLG_MonkeyTL 0ms0kbC++142.4kb2023-02-10 20:33:172023-02-10 20:33:19

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-02-10 20:33:19]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:0kb
  • [2023-02-10 20:33:17]
  • 提交

answer

/*NE Write and AFO here*/
#include<bits/stdc++.h>
using namespace std;
#define int long long
#define pb push_back
#define pii pair<int, int>
#define mp make_pair
int n, a[1010][1010]; 
pii dfs(int x1, int y1, int X2, int Y2) {
	int x2 = X2 - 1, y2 = Y2 - 1; 
	int cnt = (x2 - x1 + 2) * (y2 - y1 + 2);
	for (int i = y1 - 1; i <= y2 + 1; ) {
		if (a[x2 + 1][i] != 1) continue;
		int j = i;
		while (j <= y2 && a[x2 + 1][j + 1] == 1) j++;
		if (i == y1 - 1 && j == y2 + 1) cnt -= y2 - y1 + 2;
		else if (i == y1 - 1 || j == y2 + 1) cnt -= j - i + 1;
		else cnt -= j - i + 2;
		i = j + 1;
	} 
	for (int i = y1 - 1; i <= y2 + 1; ) {
		if (a[x1 - 1][i] != 1) continue;
		int j = i;
		while (j <= y2 && a[x1 - 1][j + 1] == 1) j++;
		if (i == y1 - 1 && j == y2 + 1) cnt -= y2 - y1 + 2;
		else if (i == y1 - 1 || j == y2 + 1) cnt -= j - i + 1;
		else cnt -= j - i + 2;
		i = j + 1;
	} 
	for (int i = x1 - 1; i <= x2 + 1; ) {
		if (a[i][y1 - 1] != 1) continue;
		int j = i;
		while (j <= x2 && a[j + 1][y1 - 1] == 1) j++;
		if (i == x1 - 1 && j == x2 + 1) cnt -= x2 - x1 + 2;
		else if (i == x1 - 1 || j == x2 + 1) cnt -= j - i + 1;
		else cnt -= j - i + 2;
		i = j + 1;
	} 
	for (int i = x1 - 1; i <= x2 + 1; ) {
		if (a[i][y2 + 1] != 1) continue;
		int j = i;
		while (j <= x2 && a[j + 1][y2 + 1] == 1) j++;
		if (i == x1 - 1 && j == x2 + 1) cnt -= x2 - x1 + 2;
		else if (i == x1 - 1 || j == x2 + 1) cnt -= j - i + 1;
		else cnt -= j - i + 2;
		i = j + 1;
	} 
	if (cnt % 2 == 0) return mp(-1, -1);
	if (x1 == X2 && y1 && Y2) return mp(x1, y1);
	if (x2 - x1 > y2 - y1) {
		int mid = (x1 + x2) >> 1;
		for (int j = y1; j <= y2; j++) {
			if (a[mid][j] == -1) {
				int x; cin >> x; a[mid][j] = x;
			}
		}
		pii la = dfs(x1, y1, mid, Y2), ra = dfs(mid + 1, y1, X2, Y2);
		if (la.first == -1) return ra; else return la;
	} else {
		int mid = (y1 + y2) >> 1;
		for (int j = x1; j <= x2; j++) {
			if (a[j][mid] == -1) {
				int x; cin >> x; a[j][mid] = x;
			}
		}
		pii la = dfs(x1, y1, X2, mid), ra = dfs(x1, mid + 1, X2, Y2);
		if (la.first == -1) return ra; else return la;
	}
}
signed main() {
	int T;
	cin >> T;
	while (T--) {
		cin >> n;
		if (n & 1) {
			cout << "! -1 -1" << endl; int x; cin >> x; continue;
		}
		memset(a, -1, sizeof a);
		pii ans = dfs(1, 1, n + 1, n + 1);
		cout << "! " << ans.first << " " << ans.second << endl; int x; cin >> x;
	}
}

详细

Test #1:

score: 0
Time Limit Exceeded

input:

2
3
1
4

output:

! -1 -1

result: