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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#760447#7618. Pattern SearchinksamuraiRE 0ms0kbC++231.8kb2024-11-18 16:58:552024-11-18 16:58:56

Judging History

你现在查看的是最新测评结果

  • [2024-11-18 16:58:56]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:0kb
  • [2024-11-18 16:58:55]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define rng(i,c,n) for(int i=c;i<n;i++)
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define all(a) a.begin(),a.end()
#define vec(...) vector<__VA_ARGS__>
typedef long long ll;
typedef vector<int> vi;
typedef pair<int,int> pii;
void print(){cout<<'\n';}
template<class h,class...t>
void print(const h&v,const t&...u){cout<<v<<' ',print(u...);}

const int SI=26;

vi get(string s){
	vi cnt(SI);
	rep(i,sz(s)) cnt[s[i]-'a']+=1;
	return cnt;
}

void slv(){
	string s,t;
	cin>>s>>t;
	int n=sz(s),m=sz(t);
	vi cnts=get(s),cntt=get(t);
	rep(i,SI){
		if(cnts[i]<cntt[i]){
			print(0);
			return;
		}
	}
	vi can(m+1,1);
	vec(vi) qs(m+1,vi(SI));
	rng(pat,1,m+1){
		int k=m/pat;
		int lo=0,hi=0;
		rep(i,SI){
			if(!cntt[i]) continue;
			// x * k >= cntt[i] - x * k
			int c=cntt[i];
			int x=(c+2*k-1)/(2*k);
			int y=c/k;
			if(y<c-y*k) can[pat]=0;
			assert(x*k>=cntt[i]-x*k);
			lo+=x;
			hi+=y;
			qs[pat][i]=x;
		}
		if(!(lo<=pat and pat<=hi)) can[pat]=0;
	}
	auto af=[&](int x){
		rng(pat,1,m+1){
			if(!can[pat]) continue;
			int pok=1;
			rep(i,SI){
				if(!cntt[i]) continue;
				// (cnts[i] - cntt[i]) / p >= x
				// (cnts[i] - cntt[i]) / x >= p
				int p=(cnts[i]-cntt[i])/x;
				while((cnts[i]-cntt[i])/p<x) p+=1;
				if(!(qs[pat][i]<=p)){
					pok=0;
					break;
				}
			}
			if(pok) return 1;
		}
		return 0;
	};
	// print(af(1));
	int l=1,r=n;
	int opt=0;
	while(l<=r){
		int _m=(l+r)/2;
		if(af(_m)) opt=_m,l=_m+1;
		else r=_m-1;
	}
	opt+=1;
	print(opt);
}

signed main(){
	ios::sync_with_stdio(0),cin.tie(0);
	int t;
	cin>>t;
	rep(cs,t){
		slv();
	}
}

详细

Test #1:

score: 0
Runtime Error

input:

2
bajkaaall aal
abca cba

output:


result: