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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#758257#8136. Rebellious EdgeraspaTL 4ms31852kbC++172.4kb2024-11-17 17:12:302024-11-17 17:12:40

Judging History

你现在查看的是最新测评结果

  • [2024-11-17 17:12:40]
  • 评测
  • 测评结果:TL
  • 用时:4ms
  • 内存:31852kb
  • [2024-11-17 17:12:30]
  • 提交

answer


#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;


//#pragma GCC optimize("O3,unroll-loops")
#define migmig     		ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define pb          		push_back
#define F           		first
#define S           		second
#define SZ(x)       		ll((x).size())
#define all(x)      		(x).begin(), (x).end()
#define cl          		clear
#define endl        		'\n'
#define deb(x)    			cerr << #x << " = " << x << '\n'
#define dokme(x)			{cout << x << endl; return;}
#define wtf					cout << "[ahaaaaaaaaaaaaaaaa]" << endl;


const int MAXN = 1e6 + 10;
const int MOD = 1e9 + 7; //998244353
const ll INF = 1e18;
const int inf = 1e9 + 90;
const int maxLG = 20;
const int SQ = 350;

int n, m, dist[MAXN];
vector<pll> G[MAXN];
bool mark[MAXN];
set<pii> se;
int MST = 0;
int cnt = 0;

void add(int v) {
	for (auto [u, w] : G[v]) {
		if (!mark[u]) {
	      se.erase({dist[u], u});
	      se.insert({(dist[u] = w), u});
    	}
	}
}


void prim() {
	dist[1] = 0;
	add(1);
	se.insert({0, 1});
	for (int i = 1; i <= n; i++) {
		if (se.empty()) {
			return;
		}
		auto tmp = *(se.begin());
		int v = tmp.S;
		MST += tmp.F;
		cnt++;
		se.erase(tmp);
		add(v);
		mark[v] = 1;
	}
}

void reset() {
	memset(dist, 63, sizeof dist);
	for (int i = 1; i <= n; i++)
			G[i].cl();
	memset(dist, 63, sizeof dist);
	se.cl();
	memset(mark, false, sizeof mark);
	MST = 0;
}

int main() {
	migmig;
	int T;
	cin >> T;
	while (T--) {
		cin >> n >> m;
		reset();
		int b, tmp;
		vector<pair<pll, int>> edg;
		for (int i = 1; i <= m; i++) {
			int v, u, w;
			cin >> v >> u >> w;
			if (v > u) {
				b = u;
				tmp = w;
			}
			edg.pb({{v, u}, w});
		}
		
		
		for (auto x : edg) {
			int v = x.F.F, u = x.F.S, w = x.S;
			if (v != b && u != b)
				G[v].pb({u, w});
		}
		prim();
//		deb(cnt);
		int res1 = MST + tmp;
		if (cnt > n) {
			res1 = inf;
		}
		
		
		MST = 0;
		reset();
		int c;
		for (auto x : edg) {
			int v = x.F.F, u = x.F.S, w = x.S;
			if (v < u)
				G[v].pb({u, w});
		}
		cnt = 0;
		prim();
		int res2 = MST;
//		deb(cnt);
		if (cnt > n) {
			res2 = inf;
		}
		cout << min(res1, res2) << endl;
		reset();
		
//		deb(res1 << ' ' << res2);
	}
}

/*
5 6
1 2 4
1 3 2
2 3 0
3 4 1
4 5 1
5 2 1
*/

詳細信息

Test #1:

score: 100
Accepted
time: 4ms
memory: 31852kb

input:

3
5 6
1 2 4
1 3 2
2 3 0
3 4 1
4 5 1
5 2 1
4 4
1 2 4
1 3 6
1 4 8
4 2 1000000
3 3
1 2 100
2 1 10
2 3 1000

output:

5
18
1100

result:

ok 3 number(s): "5 18 1100"

Test #2:

score: -100
Time Limit Exceeded

input:

50000
4 5
2 4 998973548
2 3 501271695
4 1 778395982
1 4 32454891
1 2 757288934
4 5
1 4 720856669
2 3 665098951
3 4 407461517
2 1 866914401
1 2 457859826
4 5
1 2 75288664
1 4 624893594
3 2 458973866
2 4 769074655
2 3 834773751
4 5
2 3 237060634
2 4 297307882
3 4 200383586
1 2 42856502
3 1 16574713
4 ...

output:

778395982
1000000090
1000000090
480300722
1000000090
1000000090
-1727961723
858095911
1000000090
793861088
635606317
1000000090
612891589
1000000090
622081756
1000000090
1000000090
93634961
960978736
984886788
1000000090
1000000090
1000000090
1000000090
1000000090
977157479
1000000090
654475526
1000...

result: