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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#73666#2616. Attack Orderxlwang#WA 2ms3500kbC++142.1kb2023-01-27 15:21:102023-01-27 15:21:14

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-01-27 15:21:14]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3500kb
  • [2023-01-27 15:21:10]
  • 提交

answer

#include<bits/stdc++.h>
#define int long long
#define fr(i,j,k) for(register int i=j;i<=k;++i)
#define rf(i,j,k) for(register int i=j;i>=k;--i)
#define foredge(i,j) for(register int i=head[j];i;i=e[i].nxt)
#define randfind(l,r) (rand()%((r)-(l)+1)+(l))
#define pb push_back
#define Times printf("Time:%.3lf\n",clock()/CLOCKS_PER_SEC)
using namespace std;
inline int read(){
	int x=0;
	bool f=0;
	char c=getchar();
	while(!isdigit(c)) f|=(c=='-'),c=getchar();
	while(isdigit(c)) x=(x<<3)+(x<<1)+(c^48),c=getchar();
	return f?-x:x;
}
inline void write(int x){
    if(x<0){putchar('-');x=-x;}
    if(x>9)write(x/10);
    putchar(x%10+'0');
}
inline void writeln(int x){write(x); puts("");}
inline void writepl(int x){write(x); putchar(' ');}
//inline void init(){
//	int t=read();
//	while(t--) work();
//}
const int Maxn=1e2+10;
int a[Maxn],b[Maxn];
int n;
int vis[Maxn];
struct node{
    int val;
    int id;
}e[Maxn];
int sum[Maxn];
inline bool cmp(node a,node b){return a.val<b.val;}
inline bool check(int x){
    memset(vis,0,sizeof(vis));memset(sum,0,sizeof(sum));
    vis[n]=1;
    int l=1;
    fr(i,1,n){
        if(i==x){sum[i]=a[i]+b[n];continue;}
        while(vis[e[l].id]) ++l;
        int flag=0;
        fr(j,l,n){
            // writepl(i),writepl(j),writepl(e[j].id);
            // puts("");
            if(vis[e[j].id]) continue;
            if(e[j].id==i) continue;
            // puts("**");
            if(e[j].val+a[i]>=sum[i-1]){
                flag=1;vis[e[j].id]=1;
                break;
            }
        }
        if(!flag) return false;
    }
    return true;
}
inline void work(){
    n=read();
    fr(i,1,n) a[i]=read(),b[i]=read();
    fr(i,1,n) e[i].id=i,e[i].val=b[i];
    sort(e+1,e+n+1,cmp);
    // fr(i,1,n) writepl(e[i].val),writeln(e[i].id);
    fr(i,1,n-1) if(check(i)){
        puts("Yes");
        return;
    }
    puts("No");
}
inline void init(){
    int t=read();
    while(t--) work();
}
signed main(){
	// freopen("input.in","r",stdin);
	// freopen("output.out","w",stdout);
    init();
    // printf("\nTIME:%.3lf",(double)clock()/CLOCKS_PER_SEC);
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3412kb

input:

3
2
15 25
10 5
3
7 0
7 3
10 0
3
10 10
20 20
30 30

output:

Yes
Yes
No

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: -100
Wrong Answer
time: 2ms
memory: 3500kb

input:

1000
4
0 1
0 2
2 2
0 0
4
2 2
1 1
1 1
0 0
4
2 1
1 2
1 0
2 1
3
2 1
1 0
1 1
4
2 0
2 2
1 2
1 2
3
1 0
3 0
0 3
4
1 1
1 0
1 2
1 2
2
1 2
3 1
4
1 2
1 0
2 0
0 2
2
3 3
0 2
4
2 0
1 0
2 1
0 1
3
1 1
1 0
0 3
4
1 1
2 1
0 2
1 1
4
1 2
2 2
1 0
2 1
4
0 0
1 0
0 1
0 1
3
0 1
2 3
0 0
3
3 1
3 2
1 1
4
1 0
0 0
1 1
2 1
4
2 1
1...

output:

Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
No
Yes...

result:

wrong answer expected NO, found YES [1st token]