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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#735447#7744. Elevatoracb437TL 1ms3972kbC++14912b2024-11-11 20:03:092024-11-11 20:03:09

Judging History

你现在查看的是最新测评结果

  • [2024-11-11 20:03:09]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3972kb
  • [2024-11-11 20:03:09]
  • 提交

answer

#include <algorithm>
#include <cstdio>
#include <iostream>
using namespace std;
typedef long long ll;
const int N = 1e5 + 5;
int t, n;ll k, ans;
struct pkg{int c, w, f;}p[N];

int main()
{
    scanf("%d", &t);
    while(t--)
    {
        ans = 0;
        scanf("%d%lld", &n, &k);
        for(int i = 1;i <= n;i++)scanf("%d%d%d", &p[i].c, &p[i].w, &p[i].f);
        sort(p + 1, p + n + 1, [](pkg a, pkg b){return a.f == b.f ? a.w > b.w : a.f > b.f;});
        ll tmp = k;int hig = p[1].f;
        for(int i = 1;i <= n;i++)
            while(p[i].c)
                if(p[i].c * p[i].w <= tmp)tmp -= p[i].c * p[i].w, p[i].c = 0;
                else
                {
                    p[i].c -= tmp / p[i].w, tmp %= p[i].w;
                    ans += hig, hig = p[i].f, tmp = k;
                }
        if(!p[n].c)ans += hig;
        printf("%lld\n", ans);
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3972kb

input:

2
4 6
1 1 8
7 2 5
1 1 7
3 2 6
8 1200000
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345

output:

24
100000

result:

ok 2 lines

Test #2:

score: -100
Time Limit Exceeded

input:

5501
8 104
5 2 3
6 2 4
5 2 3
6 2 9
8 2 4
2 1 3
7 2 4
8 2 8
1 290
3 1 1
12 12
6 1 2
1 2 2
1 1 2
1 2 4
6 1 1
1 2 5
6 1 4
4 1 4
6 2 4
6 2 5
4 2 5
4 1 4
5 334
1 1 4
1 2 3
4 2 1
5 1 1
2 1 2
13 218
5 2 3
5 1 4
1 2 1
1 2 5
3 2 2
1 1 3
4 2 2
1 2 5
2 2 1
2 1 5
3 2 1
5 2 1
1 1 4
10 260
7 2 1
5 1 1
5 2 4
6 1 6...

output:

9
1
23
4
5
7
1
3
9
6
1
10
4
9
17
6
4
1
8
5
5
7
1
3
23
6
3
3
2
2
2
3
8
1
5
6
9
11
150
7
10
2
7
7
8
6
5
5
1
7
3
5
10
7
7
10
8
1
4
2
3
9
1
5
2
9
1
6
7
7
6
10
18
8
10
4
10
9
2
8
3
5
9
3
6
5
3
2
6
1
3
2
2
1
6
9
6
3
4
8
9
9
2
6
1
2
6
7
5
2
5
21
8
1
2
3
4
9
3
4
6
5
9
6
1
7
3
7
3
2
2
8
7
3
5
9
7
10
7
3
2
4
...

result: