QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#735447 | #7744. Elevator | acb437 | TL | 1ms | 3972kb | C++14 | 912b | 2024-11-11 20:03:09 | 2024-11-11 20:03:09 |
Judging History
answer
#include <algorithm>
#include <cstdio>
#include <iostream>
using namespace std;
typedef long long ll;
const int N = 1e5 + 5;
int t, n;ll k, ans;
struct pkg{int c, w, f;}p[N];
int main()
{
scanf("%d", &t);
while(t--)
{
ans = 0;
scanf("%d%lld", &n, &k);
for(int i = 1;i <= n;i++)scanf("%d%d%d", &p[i].c, &p[i].w, &p[i].f);
sort(p + 1, p + n + 1, [](pkg a, pkg b){return a.f == b.f ? a.w > b.w : a.f > b.f;});
ll tmp = k;int hig = p[1].f;
for(int i = 1;i <= n;i++)
while(p[i].c)
if(p[i].c * p[i].w <= tmp)tmp -= p[i].c * p[i].w, p[i].c = 0;
else
{
p[i].c -= tmp / p[i].w, tmp %= p[i].w;
ans += hig, hig = p[i].f, tmp = k;
}
if(!p[n].c)ans += hig;
printf("%lld\n", ans);
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 1ms
memory: 3972kb
input:
2 4 6 1 1 8 7 2 5 1 1 7 3 2 6 8 1200000 100000 1 100000 100000 1 12345 100000 2 100000 100000 2 12345 100000 1 100000 100000 1 12345 100000 2 100000 100000 2 12345
output:
24 100000
result:
ok 2 lines
Test #2:
score: -100
Time Limit Exceeded
input:
5501 8 104 5 2 3 6 2 4 5 2 3 6 2 9 8 2 4 2 1 3 7 2 4 8 2 8 1 290 3 1 1 12 12 6 1 2 1 2 2 1 1 2 1 2 4 6 1 1 1 2 5 6 1 4 4 1 4 6 2 4 6 2 5 4 2 5 4 1 4 5 334 1 1 4 1 2 3 4 2 1 5 1 1 2 1 2 13 218 5 2 3 5 1 4 1 2 1 1 2 5 3 2 2 1 1 3 4 2 2 1 2 5 2 2 1 2 1 5 3 2 1 5 2 1 1 1 4 10 260 7 2 1 5 1 1 5 2 4 6 1 6...
output:
9 1 23 4 5 7 1 3 9 6 1 10 4 9 17 6 4 1 8 5 5 7 1 3 23 6 3 3 2 2 2 3 8 1 5 6 9 11 150 7 10 2 7 7 8 6 5 5 1 7 3 5 10 7 7 10 8 1 4 2 3 9 1 5 2 9 1 6 7 7 6 10 18 8 10 4 10 9 2 8 3 5 9 3 6 5 3 2 6 1 3 2 2 1 6 9 6 3 4 8 9 9 2 6 1 2 6 7 5 2 5 21 8 1 2 3 4 9 3 4 6 5 9 6 1 7 3 7 3 2 2 8 7 3 5 9 7 10 7 3 2 4 ...