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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#721741 | #2517. Critical Structures | ucup-team5062# | AC ✓ | 60ms | 23416kb | C++17 | 2.0kb | 2024-11-07 16:44:10 | 2024-11-07 16:44:10 |
Judging History
answer
#include <set>
#include <vector>
#include <numeric>
#include <iostream>
#include <algorithm>
using namespace std;
struct edge {
int t, id;
};
vector<vector<int> > biconnected(int N, int M, const vector<vector<edge> >& G) {
vector<bool> vis(N, false);
vector<int> depth(N);
vector<edge> par(N, edge{-1, -1});
vector<int> low(N);
vector<vector<int> > ans;
vector<edge> st;
auto dfs = [&](auto& self, int x) -> void {
vis[x] = true;
low[x] = depth[x];
for (edge e : G[x]) {
if (!vis[e.t]) {
depth[e.t] = depth[x] + 1;
par[e.t] = edge{x, e.id};
st.push_back(e);
self(self, e.t);
low[x] = min(low[x], low[e.t]);
if (low[e.t] >= depth[x]) {
ans.push_back(vector<int>());
while (st.back().id != e.id) {
ans.back().push_back(st.back().id);
st.pop_back();
}
ans.back().push_back(e.id);
st.pop_back();
}
} else if (depth[e.t] < depth[x] && e.id != par[x].id) {
st.push_back(e);
low[x] = min(low[x], depth[e.t]);
}
}
};
dfs(dfs, 0);
return ans;
}
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
int T;
cin >> T;
for (int id = 1; id <= T; id++) {
int N, M;
cin >> N >> M;
vector<vector<edge> > G(N);
vector<int> A(M), B(M);
for (int i = 0; i < M; i++) {
cin >> A[i] >> B[i];
A[i]--; B[i]--;
G[A[i]].push_back(edge{B[i], i});
G[B[i]].push_back(edge{A[i], i});
}
vector<vector<int> > ans = biconnected(N, M, G);
vector<int> c(N);
for (int i = 0; i < ans.size(); i++) {
set<int> s;
for (int j : ans[i]) {
s.insert(A[j]);
s.insert(B[j]);
}
for (int j : s) {
c[j]++;
}
}
int ans1 = 0, ans2 = 0, ans3 = 0, ans4 = 0;
for (int i = 0; i < N; i++) {
ans1 += int(c[i] >= 2);
}
for (int i = 0; i < ans.size(); i++) {
ans2 += int(ans[i].size() == 1);
ans3 += 1;
ans4 = max(ans4, int(ans[i].size()));
}
cout << ans1 << ' ' << ans2 << ' ' << ans3 / gcd(ans3, ans4) << ' ' << ans4 / gcd(ans3, ans4) << endl;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3556kb
input:
1 6 6 1 2 2 3 3 4 4 5 5 6 6 1
output:
0 0 1 6
result:
ok single line: '0 0 1 6'
Test #2:
score: 0
Accepted
time: 0ms
memory: 3660kb
input:
1 6 7 1 2 2 3 3 1 4 5 5 6 6 4 1 4
output:
2 1 1 1
result:
ok single line: '2 1 1 1'
Test #3:
score: 0
Accepted
time: 60ms
memory: 23416kb
input:
10 6 6 1 2 2 3 3 4 4 5 5 6 6 1 5 4 1 2 2 3 3 4 4 5 5 7 1 2 1 3 3 4 4 5 5 3 1 4 1 5 13 16 1 2 1 6 1 3 1 7 3 7 4 6 4 5 5 6 5 7 7 8 8 9 7 10 10 11 12 13 10 12 10 13 10 11 1 2 2 3 2 4 3 5 4 5 4 6 6 7 7 8 6 8 8 9 8 10 3 3 1 2 2 3 3 1 44 66 1 5 1 12 1 33 2 27 2 31 2 32 2 35 2 37 2 40 3 6 3 30 3 44 4 20 4 ...
output:
0 0 1 6 3 4 4 1 1 1 1 3 4 5 7 8 4 4 3 2 0 0 1 3 8 9 10 57 0 0 1 499500 2 2 3 1777 108 112 113 1531
result:
ok 10 lines