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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#707617 | #7901. Basic Substring Structure | IllusionaryDominance | RE | 3ms | 51160kb | C++20 | 3.9kb | 2024-11-03 16:47:19 | 2024-11-03 16:47:20 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int MAX_N = 400000 + 5;
int N, str[MAX_N], sa[MAX_N], rk[MAX_N], ht[MAX_N], lcp[MAX_N], st[20][MAX_N], a[MAX_N], c[MAX_N], lg[MAX_N];
unordered_map <int, ll> bonus[MAX_N];
ll b[MAX_N], d[MAX_N];
void build_sa(int *s, int n, int *sa, int *rk, int *ht) {
static int cnt[MAX_N], sb[MAX_N], rk_[MAX_N];
int i, j, k = n, m, *x = rk, *y = rk_;
for (i = 1; i <= n; i ++) cnt[s[i]] ++;
for (i = 1; i <= k; i ++) cnt[i] += cnt[i - 1];
for (i = n; i > 0; i --) sa[cnt[s[i]] --] = i;
memset(cnt, 0, sizeof(int) * (k + 1));
for (i = 1, k = 0; i <= n; i ++) rk[sa[i]] = k += s[sa[i]] != s[sa[i - 1]];
for (m = 1; m < n && k < n; m <<= 1) {
for (j = 1; j <= m; j ++) sb[j] = n - m + j;
for (i = 1; i <= n; i ++) if (sa[i] > m) sb[j ++] = sa[i] - m;
for (i = 1; i <= n; i ++) cnt[x[i]] ++;
for (i = 1; i <= k; i ++) cnt[i] += cnt[i - 1];
for (i = n; i > 0; i --) sa[cnt[x[sb[i]]] --] = sb[i];
memset(cnt, 0, sizeof(int) * (k + 1));
for (i = 1, k = 0; i <= n; i ++) y[sa[i]] = k += (x[sa[i]] != x[sa[i - 1]] || x[sa[i] + m] != x[sa[i - 1] + m]);
swap(x, y);
}
if (x != rk) memcpy(rk, rk_, sizeof(int) * (n + 1));
for (i = 1, k = 0; i <= n; i ++) {
k -= k > 0;
while (s[i + k] == s[sa[rk[i] - 1] + k]) k ++;
ht[rk[i]] = k;
}
for (i = 1; i <= n; i ++) st[0][i] = ht[i];
for (i = 1; i <= lg[n]; i ++) {
for (j = 1; j + (1 << i) - 1 <= n; j ++) {
st[i][j] = min(st[i - 1][j], st[i - 1][j + (1 << i - 1)]);
}
}
}
int query_lcp(int i, int j) {
if (i == j) return N - i + 1;
if (i > N || j > N) return 0;
int l = rk[i], r = rk[j];
if (r < l) swap(l, r);
int len = lg[r - l];
return min(st[len][l + 1], st[len][r - (1 << len) + 1]);
}
void solve() {
scanf("%d", &N);
for (int i = 1; i <= N; i ++) {
scanf("%d", str + i);
bonus[i].clear();
}
str[N + 1] = 0;
build_sa(str, N, sa, rk, ht);
for (int i = 2; i <= N; i ++) {
lcp[i] = query_lcp(1, i);
int p1 = lcp[i] + 1, p2 = i + lcp[i];
assert(p2 > N || str[p1] != str[p2]);
if (p2 <= N) {
int exlen1 = query_lcp(p1 + 1, p2 + 1) + 1, exlen2 = exlen1;
if (p1 + exlen1 == p2 && p2 + exlen1 <= N && str[p1] == str[p2 + exlen1]) {
exlen1 += query_lcp(p2 + 1, p2 + exlen1 + 1) + 1;
}else if (p1 + exlen1 > p2) {
exlen1 = p2 - p1;
}
bonus[p2][str[p1]] += exlen1;
if (p1 < i) {
bonus[p1][str[p2]] += exlen2;
}
}
}
memset(b, 0, sizeof(ll) * (N + 1));
memset(d, 0, sizeof(ll) * (N + 1));
memset(a, 0, sizeof(int) * (N + 1));
memset(c, 0, sizeof(int) * (N + 1));
int cnt1 = 0, cnt2 = 0;
long long sum = 0, ans = 0, pre = 0, suf = 0;
for (int i = 2; i <= N; i ++) {
sum += lcp[i];
if (lcp[i] > 0) {
cnt2 ++;
suf += lcp[i] + 1;
c[min(i - 1, lcp[i])] ++;
d[min(i - 1, lcp[i])] += lcp[i] + 1;
}
}
for (int i = 1; i <= N; i ++) {
cnt1 -= a[i];
pre -= b[i];
if (lcp[i] > 0) {
cnt1 ++;
pre += lcp[i] + i;
if (lcp[i] + i <= N) {
a[lcp[i] + i] ++;
b[lcp[i] + i] += lcp[i] + i;
}
}
ll res = sum - pre - suf + 1ll * (cnt1 + cnt2) * i, maxbonus = 0;
for (auto [ch, val] : bonus[i]) {
maxbonus = max(maxbonus, val);
}
ans += (res + maxbonus + N) ^ i;
cnt2 -= c[i];
suf -= d[i];
}
printf("%lld\n", ans);
}
int main() {
for (int i = 2; i < MAX_N; i ++) lg[i] = lg[i >> 1] + 1;
int T;
scanf("%d", &T);
while (T --) solve();
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 3ms
memory: 51160kb
input:
2 4 2 1 1 2 12 1 1 4 5 1 4 1 9 1 9 8 10
output:
15 217
result:
ok 2 lines
Test #2:
score: -100
Runtime Error
input:
10000 8 2 1 2 1 1 1 2 2 9 2 2 1 2 1 2 1 2 1 15 2 1 2 1 1 1 1 2 2 1 2 1 2 2 1 2 1 1 10 2 1 1 1 2 2 1 1 2 2 3 2 1 2 11 1 2 2 1 1 2 1 2 2 1 1 14 2 1 1 1 1 2 1 1 1 2 2 1 2 1 12 2 2 2 1 2 2 2 1 1 2 1 2 4 2 1 1 2 8 1 2 2 2 1 2 1 1 8 1 1 2 1 2 1 1 1 6 2 1 1 1 2 2 14 2 2 1 1 1 1 2 2 2 1 2 2 1 1 10 1 2 2 1 1...