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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#704811 | #7733. Cool, It’s Yesterday Four Times More | SUNCHAOYI | WA | 1ms | 5844kb | C++14 | 2.3kb | 2024-11-02 21:06:02 | 2024-11-02 21:06:10 |
Judging History
answer
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <vector>
#define init(x) memset (x,0,sizeof (x))
#define ll long long
#define ull unsigned long long
#define INF 0x3f3f3f3f
using namespace std;
const int MAX = 1e3 + 5;
const int MOD = 1e9 + 7;
inline int read ();
vector <pair <int,int> > p,ex;
int t,n,m,tot,ans,dx[] = {0,0,1,-1},dy[] = {1,-1,0,0};
int dd[4],out[MAX][MAX],vis[MAX][MAX],num[MAX][MAX];
char s[MAX][MAX];
void dfs (int x,int y);
bool check (int x,int y);
int main ()
{
//freopen (".in","r",stdin);
//freopen (".out","w",stdout);
t = read ();
while (t--)
{
ans = 0;ex.clear ();
n = read ();m = read ();
for (int i = 1;i <= n;++i) scanf ("%s",s[i] + 1);
for (int i = 1;i <= n;++i)
for (int j = 1;j <= m;++j) vis[i][j] = 0;
for (int i = 1;i <= n;++i)
for (int j = 1;j <= m;++j)
if (s[i][j] == '.') ex.push_back ({i,j});
for (int i = 1;i <= n;++i)
{
for (int j = 1;j <= m;++j)
{
if (s[i][j] == 'O') continue;
for (int k = 1;k <= n;++k)
for (int l = 1;l <= m;++l) vis[k][l] = 0;
p.clear ();dfs (i,j);
for (int o = 0;o < p.size ();++o) p[o] = {p[o].first - i,p[o].second - j};//delta
int re = ex.size () - 1;
for (auto item : ex)
{
if (item.first == i && item.second == j) continue;
bool ok = 0;
for (auto v : p)
if (check (item.first + v.first,item.second + v.second)) {ok = 1;break;}
if (ok) --re;
}
if (!re) ++ans;
}
}
printf ("%d\n",ans);
}
return 0;
}
inline int read ()
{
int s = 0;int f = 1;
char ch = getchar ();
while ((ch < '0' || ch > '9') && ch != EOF)
{
if (ch == '-') f = -1;
ch = getchar ();
}
while (ch >= '0' && ch <= '9')
{
s = s * 10 + ch - '0';
ch = getchar ();
}
return s * f;
}
void dfs (int x,int y)
{
p.push_back ({x,y});vis[x][y] = 1;
for (int i = 0;i < 4;++i) dd[i] = i;
random_shuffle (dd,dd + 4);
for (int i = 0;i < 4;++i)
{
int xx = dx[dd[i]] + x,yy = dy[dd[i]] + y;
if (1 <= xx && xx <= n && 1 <= yy && yy <= m && s[xx][yy] != 'O' && !vis[xx][yy]) dfs (xx,yy);
}
}
bool check (int x,int y)
{
if (!(1 <= x && x <= n && 1 <= y && y <= m)) return 1;
return s[x][y] == 'O';
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 1ms
memory: 5844kb
input:
4 2 5 .OO.. O..O. 1 3 O.O 1 3 .O. 2 3 OOO OOO
output:
2 1 0 0
result:
wrong answer 1st lines differ - expected: '3', found: '2'