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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#695710 | #7738. Equivalent Rewriting | Always# | WA | 1ms | 4052kb | C++23 | 1.9kb | 2024-10-31 20:38:36 | 2024-10-31 20:38:43 |
Judging History
answer
#include<iostream>
#include<queue>
#include<cstdio>
using namespace std;
priority_queue<int> q;
struct node {
int to, nxt;
} e[40000006];
int cnt, head[100005];
void add(int x, int y) {
e[++cnt].to = y;
e[cnt].nxt = head[x];
head[x] = cnt;
}
int bu[100005], rd[100005], vis[100005];
int main() {
int T;
cin >> T;
while (T--) {
int n, m;
cin >> n >> m;
for (int i = 1; i <= n; i++) {
int p;
cin >> p;
for (int j = 1; j <= p; j++) {
int l;
cin >> l;
if (bu[l] == 0) {
bu[l] = i;
} else if (vis[bu[l]] == 0 && bu[l] != 0) {
add(bu[l], i);
rd[i]++;
vis[bu[l]] = 1;
bu[l] = i;
}
}
for (int j = 1; j <= p; j++)
vis[j] = 0; // 清零 vis
}
int pd = 0;
for (int i = 1; i <= n; i++) {
if (rd[i] == 0) q.push(i);
}
int ans[100005], tot = 0;
while (!q.empty()) {
int x = q.top();
q.pop();
ans[++tot] = x;
if (tot != x) pd = 1;
for (int i = head[x]; i != 0; i = e[i].nxt) {
int y = e[i].to;
rd[y]--;
if (rd[y] == 0) q.push(y);
}
}
if (pd == 0) {
cout << "No" << endl;
} else {
cout << "Yes" << endl;
for (int i = 1; i < tot; i++)
cout << ans[i] << " ";
cout << ans[tot] << endl; // 确保最后一项不带多余空格
}
for (int i = 1; i <= n; i++)
bu[i] = rd[i] = head[i] = 0;
cnt = 0;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3980kb
input:
3 3 6 3 3 1 5 2 5 3 2 2 6 2 3 3 1 3 2 2 3 1 1 3 2 2 1
output:
Yes 3 1 2 No No
result:
ok OK. (3 test cases)
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 4052kb
input:
1 10 5 2 2 4 4 1 3 4 2 1 2 3 2 1 4 4 5 2 4 3 3 2 5 4 3 5 4 2 3 1 3 2 5 1 4 2 3 5 1 4
output:
Yes 1 3 2 4 5 10 6 7 8 9
result:
wrong answer two transactions are not equivalent. (test case 1)