QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#685185#6422. Evil Coordinateadivse#AC ✓14ms4028kbC++204.8kb2024-10-28 18:09:402024-10-28 18:09:41

Judging History

你现在查看的是最新测评结果

  • [2024-10-28 18:09:41]
  • 评测
  • 测评结果:AC
  • 用时:14ms
  • 内存:4028kb
  • [2024-10-28 18:09:40]
  • 提交

answer

#include <iostream>
#include <algorithm>
#include <cstring>
#include <cmath>
#include <vector>
#include <set>
#include <queue>
#include <map>
#include <iomanip>
#define endl '\n'
#define int long long
#define rep(i,a,b) for(int i=(a);i<=(b);i++)
#define rep2(i,a,b) for(int i=(a);i>=(b);i--)
using namespace std;
template<typename T>
void cc(vector<T> tem) { for (auto x : tem) cout << x << ' '; cout << endl; }
void cc(int a) { cout << a << endl; }
void cc(int a, int b) { cout << a << ' ' << b << endl; }
void cc(int a, int b, int c) { cout << a << ' ' << b << ' ' << c << endl; }
void kuaidu() { ios::sync_with_stdio(false), cin.tie(0), cout.tie(0); }
inline int max(int a, int b) { if (a < b) return b; return a; }
inline int min(int a, int b) { if (a < b) return a; return b; }
void cmax(int& a, const int b) { if (b > a) a = b; }
void cmin(int& a, const int b) { if (b < a) a = b; }
using PII = pair<int, int>;
using i128 = __int128;

//--------------------------------------------------------------------------------
const int N = 1e5 + 10;
const int M = 1e6 + 10;
const int mod = 1e9 + 7;
const int INF = 1e16;
int n, m, T;
int zx, zy;
int tx, ty;
int A[4];//0 shang 1 xia 2 zuo 3 you
//--------------------------------------------------------------------------------
void shang() {
    rep(i, 1, A[0]) cout << 'U';
    rep(i, 1, A[1]) cout << 'D';
}
void zuo() {
    rep(i, 1, A[2]) cout << 'L';
    rep(i, 1, A[3]) cout << 'R';
}
signed main() {
    kuaidu();
    T = 1;
    cin >> T;
    while (T--) {
        cin >> zx >> zy;
        string s; cin >> s;
        rep(i, 0, 3) A[i] = 0;
        tx = 0, ty = 0;
        rep(i, 0, s.size() - 1) {
            if (s[i] == 'U') A[0]++, ty += 1;
            if (s[i] == 'L') A[2]++, tx -= 1;
            if (s[i] == 'D') A[1]++, ty -= 1;
            if (s[i] == 'R') A[3]++, tx += 1;
        }

        if (zx == 0 and zy == 0) {
            cout << "Impossible" << endl;
            continue;
        }

        if (zx == tx and zy == ty) {
            cout << "Impossible" << endl;
            continue;
        }

        
        if (zx and zy) {

            if (ty == zy) {
                zuo(), shang();
                cout << endl;

                continue;
            }

            if (tx == zx) {
                shang(), zuo();
                cout << endl;

                continue;
            }
            shang(); zuo();
            cout << endl;

            continue;
        }

        if (tx and ty) {
            if (zx == 0) {
                zuo(), shang();
                cout << endl;

                continue;
            }
            if (zy == 0) {
                shang(); zuo();
                cout << endl;

                continue;
            }
            continue;
        }
        
        if (zx and ty or zy and tx) {
            if (zx and ty) {
                shang(), zuo();
                cout << endl;

                continue;
            }
            if (zy and tx) {
                zuo(), shang();
                cout << endl;

                continue;
            }
        }

        if (zx) {

            if (zx * tx > 0 and abs(zx) > abs(tx) || zx * tx <= 0) {
                if (zx < 0) {
                    shang();
                    rep(i, 1, A[3]) cout << 'R';
                    rep(i, 1, A[2]) cout << 'L';
                }
                if (zx > 0) {
                    shang();
                    rep(i, 1, A[2]) cout << 'L';
                    rep(i, 1, A[3]) cout << 'R';
                }
                cout << endl;

                continue;
            }

            if (!A[0]) {
                cout << "Impossible" << endl;
                continue;
            }
            //0 shang 1 xia 2 zuo 3 you
            cout << 'U';
            zuo();
            rep(i, 2, A[0]) cout << 'U';
            rep(i, 1, A[1]) cout << 'D';
            cout << endl;

            continue;
        }

        if (zy) {

            if (zy * ty > 0 and abs(zy) > abs(ty) or zy * ty <= 0) {
                if (zy < 0) {
                    zuo();
                    rep(i, 1, A[0]) cout << 'U';
                    rep(i, 1, A[1]) cout << 'D';
                }
                if (zy > 0) {
                    zuo();
                    rep(i, 1, A[1]) cout << 'D'; rep(i, 1, A[0]) cout << 'U';
                }
                cout << endl;

                continue;
            }
            if (!A[2]) {
                cout << "Impossible" << endl;
                continue;
            }
            cout << 'L';
            shang();
            rep(i, 2, A[2]) cout << 'L';
            rep(i, 1, A[3]) cout << 'R';
            cout << endl;
            continue;
        }


    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3616kb

input:

5
1 1
RURULLD
0 5
UUU
0 3
UUU
0 2
UUU
0 0
UUU

output:

LLRRUUD
UUU
Impossible
Impossible
Impossible

result:

ok 5 cases

Test #2:

score: 0
Accepted
time: 8ms
memory: 4028kb

input:

11109
6 0
RUDUDR
2 0
URU
0 0
UDRU
0 0
R
-1 1
LDUUDDRUUL
-1 5
RRUUUDUUU
-8 4
RRDRLDR
2 0
UD
0 0
UUDD
3 -2
LDDLLLRR
3 -2
LDRURLDD
1 0
RRL
-1 0
DUDDLLRDU
-4 0
LL
-1 -1
DLRLDLUDUR
1 4
URDULUR
0 0
DDUUDUDDDD
0 2
UU
1 0
RRULD
0 -2
LDLRLLDRRL
0 1
RLRLLRLUR
-3 0
RL
0 0
D
0 0
L
0 0
DDLRRUDRUD
0 0
DULU
2 0
RR...

output:

UUDDRR
UUR
Impossible
Impossible
Impossible
RRUUUUUUD
DDLRRRR
UD
Impossible
LLLLRRDD
LLRRUDDD
Impossible
UUDDDDLLR
LL
Impossible
UUUDLRR
Impossible
Impossible
Impossible
LLLLLRRRDD
Impossible
RL
Impossible
Impossible
Impossible
Impossible
Impossible
LLLRRRRRUU
UDLLL
Impossible
UUUDDDL
UUDDRR
Impossi...

result:

ok 11109 cases

Test #3:

score: 0
Accepted
time: 14ms
memory: 3900kb

input:

11107
1 0
LLRLRURLR
1 0
LLRR
0 1
R
1 0
LLLRLRRR
1 0
RUL
0 1
UD
1 0
RLRLU
0 1
DDDUUUDU
1 0
RURRLLRLL
1 0
LRLR
1 0
ULR
0 1
R
0 1
DDUUUDR
0 1
UUDDUDDU
0 1
DDUUDU
1 0
RRLRLLRLRL
1 0
RLRRLL
1 0
LUR
1 0
U
1 0
LRRRLLLR
0 1
DRUUDDUDU
0 1
DUUDDUR
1 0
LRLRLR
0 1
UUDDDUDU
0 1
R
0 1
UDUDDU
0 1
DUUDUD
1 0
RRLRRR...

output:

ULLLLRRRR
LLRR
R
LLLLRRRR
ULR
DU
ULLRR
DDDDUUUU
ULLLLRRRR
LLRR
ULR
R
RUUUDDD
DDDDUUUU
DDDUUU
LLLLLRRRRR
LLLRRR
ULR
U
LLLLRRRR
RUUUUDDDD
RUUUDDD
LLLRRR
DDDDUUUU
R
DDDUUU
DDDUUU
LLLLLRRRRR
DDDDUUUU
DDUU
ULLLLRRRR
DDUU
LLLRRR
ULR
ULR
U
ULR
LLLRRR
LLLLLRRRRR
U
DDDUUU
R
LLLRRR
RUUUUDDDD
RUUUUDDDD
LLLRRR
...

result:

ok 11107 cases