QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#679609#5438. Half Mixedruoye123456WA 0ms3584kbC++202.1kb2024-10-26 17:58:432024-10-26 17:58:44

Judging History

你现在查看的是最新测评结果

  • [2024-10-26 17:58:44]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3584kb
  • [2024-10-26 17:58:43]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define x first
#define y second
typedef pair<int,int> PII;
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int uint;
typedef vector<string> VS;
typedef vector<int> VI;
typedef vector<vector<int>> VVI;
vector<int> vx;
inline void divide() {sort(vx.begin(),vx.end());vx.erase(unique(vx.begin(),vx.end()),vx.end());}
//inline int mp(int x) {return upper_bound(vx.begin(),vx.end(),x)-vx.begin();}
inline int log_2(int x) {return 31-__builtin_clz(x);}
inline int popcount(int x) {return __builtin_popcount(x);}
inline int lowbit(int x) {return x&-x;}
inline ll Lsqrt(ll x) { ll L = 1,R = 2e9;while(L + 1 < R){ll M = (L+R)/2;if(M*M <= x) L = M;else R = M;}return L;}
void solve()
{
    int n,m;
    cin>>n>>m;
    bool turn = true;
    if((ll)m*(m+1)%4) {cout<<"No\n";return ;}
    if(n < m) {swap(n,m);turn = false;}
    ll ans = m*m/2 - m/2;
    vector<int> final;
    auto dfs = [&](auto && dfs, int rest, ll res, vector<int> path)->void 
    {
        if(!rest)
        {
            if(res == ans) final = path;
            return ;
        } 
        for(int i=rest;i;--i)
        {
            if(res + (ll)i * i + rest - i > ans) continue;
            vector<int> tmp = path;
            tmp.push_back(i);
            dfs(dfs, rest - i, res + (ll)i*i, tmp);
        }
    };
    cout<<"Yes\n";
    vector<int> init;
    dfs(dfs, m, 0, init);
    //cout<<final.size()<<'\n';
    vector<vector<int>> g(n,vector<int> (m));
    int ok = 0;
    int cnt = 0;
    for(auto t : final)
    {
        for(int i=1;i<=t;++i) g[0][cnt++] = ok;
        ok ^= 1;
    } 
    for(int i=1;i<n;++i)
     for(int j=0;j<m;++j)
     g[i][j] = g[0][j];
    if(turn)
    {
        for(int i=0;i<n;++i)
            for(int j=0;j<m;++j)
            cout<<g[i][j]<<" \n"[j==m-1];
    }
    else
    {
        for(int i=0;i<m;++i)
            for(int j=0;j<n;++j)
            cout<<g[j][i]<<" \n"[j==n-1];
    }
    
}
int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	int T;
	cin>>T;
	while(T--)
	{
		solve();
	}
}

详细

Test #1:

score: 0
Wrong Answer
time: 0ms
memory: 3584kb

input:

2
2 3
1 1

output:

Yes
0 0 0
0 0 0
No

result:

wrong answer 0 Mixed Submatrices Found, but 9 Expected (test case 1)