QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#676948 | #3259. Substring Characters | fazlavarx | AC ✓ | 1ms | 3588kb | C++14 | 2.4kb | 2024-10-26 04:36:29 | 2024-10-26 04:36:29 |
Judging History
answer
#include <iostream>
#include <set>
#include <unordered_map>
using namespace std;
int main()
{
string input = "";
while (cin >> input)
{
int l = 0, r = 0;
set<char> Char(input.begin(), input.end()); // set for size
unordered_map<char, int> occ; // hashmap check how many times char occurs
unordered_map<string, int> Appeared; // hashmap to keep track of repeating substrings
int s = Char.size(); // value to compare to
int curr = 0; // how many unique chars are within window
int occurance = 0; // return value
while (l <= r)
{
// if we reached end, break
if (r == input.length())
break;
// if we haven't seen char yet, increment unique curr within sliding window
if (occ[input[r]] == 0)
curr++;
occ[input[r]]++; // increment occurence within occ hashmap
if (curr == s)
{
// check left pointer
// if char already exists within window, increment l
while (occ[input[l]] > 1)
{
occ[input[l]]--;
l++;
}
// put the substring within Appeared hashmap to keep track of substrings
string sub = "";
for (int i = l; i <= r; i++)
{
sub += input[i];
}
// cout << sub << endl;
Appeared[sub]++;
// if it appears more then once, dont increment occurances
if (Appeared[sub] == 1)
{
if (input.length() != curr)
{
occurance++;
// we have optimal window
curr--;
occ[input[l]] = 0;
l++;
}
// we breakout if the valid substring is the size of string
else
break;
}
else
{
curr--;
occ[input[l]] = 0;
l++;
}
}
r++;
}
cout << occurance << endl;
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3508kb
input:
aabbabb abAB34aB3ba7 104001144 aaabcaaa a bb bd 1234567
output:
2 1 3 2 0 1 0 0
result:
ok 8 lines
Test #2:
score: 0
Accepted
time: 0ms
memory: 3588kb
input:
kejfASKDNF2342389fjsl2lsklsdflkjdKDFJKFD2342359829jdkjfkdklsjekfw234234234235123 11111111111111111111111111111111111111111111111111111111111111111111111111111111 12312343123123142312341234123412341234123423412312341234123232312341232341234123
output:
1 1 11
result:
ok 3 lines
Test #3:
score: 0
Accepted
time: 1ms
memory: 3512kb
input:
1234543212345432123454321234543212345432123454321234543212345432123454321 1234543212345432123454321234543212345432123454321234543212345432123454321Z a1234543212345432123454321234543212345432123454321234543212345432123454321 ABCDEFABCDEFABCDEFABCDEFABCDEFABCDEFABCDEFABCDEFABCDEFABCDEFABCDEFABCDEFABCD...
output:
2 1 1 6 1 1 25 2 1 1 1 0 0 1 1 4 5 2 1 1 1 1
result:
ok 22 lines
Test #4:
score: 0
Accepted
time: 1ms
memory: 3528kb
input:
0123456789ABCDEFEDCBA9876543210123456789ABCDEFEDCBA98765432123456789ABCDEFEDCBA abcdeadbedcacdebadecbdaecdbacebdcaebecadebacebdabecdcbeabedcebdadbcecbdaedbcacb 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZzyxwvutsrqponmlkjihgfedcbaqdKYJt2iHEL3vWFghr 99RBKQEBTBCA8WRSVNBSCGVZFLPTP7F29965694YAKW3B77CCFXCNEWRRL8...
output:
2 32 1 2 1 2 2 1 2 1 1 8 7 8 13 1 6 3 2 1 1 1
result:
ok 22 lines
Test #5:
score: 0
Accepted
time: 0ms
memory: 3512kb
input:
x dddddddgggggg dgdgdgdgdgdg ef1ef1e ef1ef1 abcbacbacab cabcbacbacabc kadksfkaddkdfakkjdfjdfasjdafhgdafsdasflalsdlkhdfhdasjklsadkjdafhklsajfghdasjkdg 1234567890 1234567890987654321 ssss aba ec26hb6a4l2wv3rm1ut7r9nxtejs5riidbxenodgipyjjuxtdwi3bykyhnauvv5gvws8r7fxdady7ek8 q3g12voqn3mewezr1jfoejpgh4vc4...
output:
0 1 2 3 3 5 5 6 0 2 1 2 1 1 1 1 1 1 1 7 4 1
result:
ok 22 lines