QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#672613 | #6434. Paimon Sorting | etherealUnicorn | AC ✓ | 113ms | 4044kb | C++14 | 1.1kb | 2024-10-24 17:46:57 | 2024-10-24 17:46:58 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
int BIT[N];
void add(int n, int x, int inc)
{
for (; x <= n; x += x & -x)
BIT[x] += inc;
}
int ask(int x)
{
int ret = 0;
for (; x; x -= x & -x)
ret += BIT[x];
return ret;
}
int main()
{
ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);
int t, n, a, maxa, pre;
long long ans;
cin >> t;
while (t--)
{
cin >> n;
for (int i = 1; i <= n; i++)
BIT[i] = 0;
maxa = 0, ans = -2, pre = N;
for (int i = 1; i <= n; i++)
{
cin >> a;
if (ask(a) - ask(a - 1) == 0)
add(n, a, 1);
if (a > maxa)
{
maxa = a;
ans += 2 + max(0, i - pre);
pre = N;
}
else if (a == maxa)
pre = min(pre, i);
else
ans += ask(n) - ask(a);
cout << ans << (i == n ? "" : " ");
}
cout << endl;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3584kb
input:
3 5 2 3 2 1 5 3 1 2 3 1 1
output:
0 2 3 5 7 0 2 4 0
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 113ms
memory: 4044kb
input:
6107 19 10 13 8 8 11 18 12 9 15 19 6 13 11 11 17 9 14 2 18 12 1 8 10 2 10 2 6 1 5 9 5 7 16 14 4 2 15 12 14 10 3 2 9 15 4 12 9 5 15 10 3 2 5 6 7 8 6 1 6 4 18 6 5 12 12 11 2 10 10 5 10 13 15 13 10 17 7 11 2 1 1 2 1 1 3 2 1 2 17 11 15 3 10 7 15 15 10 5 17 3 3 14 13 11 11 2 3 2 2 3 7 6 1 7 5 3 5 1 7 2 1...
output:
0 2 4 6 7 9 11 16 17 19 28 31 36 41 43 51 55 67 68 0 2 4 6 6 8 10 14 17 18 22 25 0 1 3 5 7 8 11 16 22 26 26 31 33 37 42 42 0 1 3 5 7 9 11 17 19 23 0 1 3 3 4 8 10 12 16 18 27 29 30 34 36 42 46 55 0 0 0 0 1 1 0 2 4 6 9 9 9 11 15 21 27 33 35 38 42 46 55 0 0 3 0 1 3 5 8 10 14 0 1 3 4 6 9 9 0 1 1 3 7 11 ...
result:
ok 6107 lines