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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#672369#9172. Alternating Cycleucup-team1338WA 1ms5892kbC++146.8kb2024-10-24 16:37:212024-10-24 16:37:22

Judging History

你现在查看的是最新测评结果

  • [2024-10-24 16:37:22]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:5892kb
  • [2024-10-24 16:37:21]
  • 提交

answer

#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,sse4,popcnt,abm,mmx,avx,avx2") 
#include<bits/stdc++.h>
#define For(i,a,b) for(int i=(a);i<=(b);++i)
#define Rep(i,a,b) for(int i=(a);i>=(b);--i)
#define ll long long
#define int long long
#define ull unsigned long long

using namespace std;
inline int read()
{
    char c=getchar();int x=0;bool f=0;
    for(;!isdigit(c);c=getchar())f^=!(c^45);
    for(;isdigit(c);c=getchar())x=(x<<1)+(x<<3)+(c^48);
    if(f)x=-x;return x;
}

#define mod 998244353
struct modint{
  int x;
  modint(int o=0){x=o;}
  modint &operator = (int o){return x=o,*this;}
  modint &operator +=(modint o){return x=x+o.x>=mod?x+o.x-mod:x+o.x,*this;}
  modint &operator -=(modint o){return x=x-o.x<0?x-o.x+mod:x-o.x,*this;}
  modint &operator *=(modint o){return x=1ll*x*o.x%mod,*this;}
  modint &operator ^=(int b){
    modint a=*this,c=1;
    for(;b;b>>=1,a*=a)if(b&1)c*=a;
    return x=c.x,*this;
  }
  modint &operator /=(modint o){return *this *=o^=mod-2;}
  friend modint operator +(modint a,modint b){return a+=b;}
  friend modint operator -(modint a,modint b){return a-=b;}
  friend modint operator *(modint a,modint b){return a*=b;}
  friend modint operator /(modint a,modint b){return a/=b;}
  friend modint operator ^(modint a,int b){return a^=b;}
  friend bool operator ==(modint a,modint b){return a.x==b.x;}
  friend bool operator !=(modint a,modint b){return a.x!=b.x;}
  bool operator ! () {return !x;}
  modint operator - () {return x?mod-x:0;}
  bool operator <(const modint&b)const{return x<b.x;}
};
inline modint qpow(modint x,int y){return x^y;}

vector<modint> fac,ifac,iv;
inline void initC(int n)
{
  if(iv.empty())fac=ifac=iv=vector<modint>(2,1);
  int m=iv.size(); ++n;
  if(m>=n)return;
  iv.resize(n),fac.resize(n),ifac.resize(n);
  For(i,m,n-1){
    iv[i]=iv[mod%i]*(mod-mod/i);
    fac[i]=fac[i-1]*i,ifac[i]=ifac[i-1]*iv[i];
  }
}
inline modint C(int n,int m){
  if(m<0||n<m)return 0;
  return initC(n),fac[n]*ifac[m]*ifac[n-m];
}
inline modint sign(int n){return (n&1)?(mod-1):(1);}

#define fi first
#define se second
#define pb push_back
#define mkp make_pair
typedef pair<int,int>pii;
typedef vector<int>vi;

#define maxn 800005
#define inf 0x3f3f3f3f

struct P{
  int x,y,id;
  P(int x=0,int y=0):x(x),y(y){}
  P&operator +=(P o){return x+=o.x,y+=o.y,*this;}
  P&operator -=(P o){return x-=o.x,y-=o.y,*this;}
  P&operator *=(int o){return x*=o,y*=o,*this;}
  P&operator /=(int o){return x/=o,y/=o,*this;}
  friend P operator +(P a,P b){return a+=b;}
  friend P operator -(P a,P b){return a-=b;}
  friend P operator *(P a,int b){return a*=b;}
  friend P operator /(P a,int b){return a/=b;}
  friend bool operator <(P a,P b){return a.x==b.x?a.y<b.y:a.x<b.x;}
  friend int operator %(P a,P b){return a.x*b.x+a.y*b.y;} // dot
  friend int operator *(P a,P b){return a.x*b.y-a.y*b.x;} // cross
  
  inline double ang(){return atan2(y,x);}
  inline double l(){return sqrt((*this)*(*this));}
  
  void read(){cin>>x>>y;}
  void out(){cout<<"("<<x<<","<<y<<")"<<endl;}
};

int sgn(int x){
  return x<0?-1:(x>0);
}
int cross(P a,P b,P c){
  //(a->b) ---> (a->c)
  return (b-a)*(c-a);
}
int cmp3(P a,P b,P c){
  return sgn(cross(a,b,c));
}

int n,m;
vector<P>a,b,t;
bool vis[maxn];

vector<P>convex(vector<P>o){
  sort(o.begin(),o.end());
  int n=o.size();
  vector<P>p;
  For(i,0,n-1){
    while(p.size()>1&&(p.back()-p[p.size()-2])*(o[i]-p[p.size()-2])<=0) p.pop_back();
    p.pb(o[i]);
  }
  int m=p.size();
  Rep(i,n-2,0){
    while(p.size()>m&&(p.back()-p[p.size()-2])*(o[i]-p[p.size()-2])<=0) p.pop_back();
    if(i)p.pb(o[i]);
  }
  return p;
}

void check(vector<P>o){
//  cout<<"check\n";
  int n=o.size();
  vector<int>d(n);
  For(i,0,n-1) d[i]=cmp3(o[i],o[(i+1)%n],o[(i+2)%n]);
//  For(i,0,n-1) cout<<d[i]<<" "; cout<<"\n";
  For(i,0,n-1) if(d[i]!=-d[(i+1)%n]) return;
  cout<<o.size()<<"\n";
  for(auto it:o)cout<<it.x<<" "<<it.y<<"\n";
  exit(0);
}

bool in(P p,P a,P b,P c){
  return cmp3(a,b,p)>0 && cmp3(b,c,p)>0 && cmp3(c,a,p)>0;
}

bool vis1[13],vis2[13];
vector<P>ans;
void dfs(int u){
  if(u==6){
    check(ans);
    return;
  }
  if(u%2==0){
    For(i,0,n-1) if(!vis1[i]) {
      vis1[i]=1;
      ans[u]=b[i];
      dfs(u+1);
      vis1[i]=0;
    }
  }else{
    For(i,0,m-1) if(!vis2[i]){
      vis2[i]=1;
      ans[u]=t[i];
      dfs(u+1);
      vis2[i]=0;
    }
  }
}

void solve3(){
//  for(auto it:b)it.out();puts("---b---");
//  for(auto it:t)it.out();puts("---t---");
  while(b.size()>6){
    n=b.size();
    bool fd=0;
    Rep(i,n-1,0){
      P A=b[(i+n-1)%n],B=b[i],C=b[(i+1)%n];
      bool ok=1;
      for(auto p:t)
        if(in(p,A,B,C)) ok=0;
      if(ok){
        For(j,i,n-2) b[j]=b[j+1];
        b.pop_back();
        fd=1;
        break;
      }
    }
    assert(fd);
  }
//  for(auto it:b)it.out();puts("---b---");
//  for(auto it:t)it.out();puts("---t---");
  n=b.size();
  m=t.size();
  ans.resize(6);
  dfs(0);
  puts("-1"),exit(0);
  assert(0);
}

namespace S2{

  int op[maxn],n;
  P A,B;
  vector<P>p,q;
  bool solve2(vector<P>b,vector<P>t){
    n=b.size();
    A=t[0],B=t[1];
    int c1=0,c2=0;
    For(i,0,n-1) op[i]=cmp3(A,B,b[i]),c1+=(op[i]>0),c2+=(op[i]<0);
    if(c1<=1 || c2<=1) return 0;
    For(i,0,n-1) if(op[(i+n-1)%n]==-1 && op[i]==1){
      for(int j=i;op[j]==1;j=(j+1)%n) p.pb(b[j]);
      break;
    }
    For(i,0,n-1) if(op[(i+n-1)%n]==1 && op[i]==-1){
      for(int j=i;op[j]==-1;j=(j+1)%n) q.pb(b[j]);
      break;
    }
  //  assert(p.size()>=2 && q.size()>=2);
    P p1,p2,q1,q2;
    int np=p.size(),nq=q.size();
    int j=nq-1;
    bool ok=0;
    Rep(i,np-1,0){
      while(j>=0 && cmp3(p[i],B,q[j])>0) --j;
      if(j>=0 && cmp3(p[i],A,q[j])>0){
        p1=p[i],q1=q[j];
        ok=1;
        break;
      }
    }
    if(!ok) return 0;
    j=0;
    ok=0;
    For(i,0,nq-1){
      while(j<=np-1 && cmp3(q[i],B,p[j])<0) ++j;
      if(j<=np-1 && cmp3(q[i],A,p[j])<0){
        q2=q[i],p2=p[j];
        ok=1;
        break;
      }
    }
    if(!ok) return 0;
    vector<P>tmp={p1,A,q2,p2,B,q1};
    For(i,0,5)For(j,i+1,5)if(tmp[i].id==tmp[j].id) return 0;
    check(tmp);
    return 0;
  }
  
}

signed main()
{
//  freopen("data.in","r",stdin);
//  freopen("my.out","w",stdout);
  n=read();
  a.resize(n);
  For(i,0,n-1)a[i].x=read(),a[i].y=read(),a[i].id=i;
  b=convex(a);
  for(auto t:b) vis[t.id]=1;
  int cnt=0;
  For(i,0,n-1)cnt+=(!vis[i]);
  if(cnt<=1){
    puts("-1");
    exit(0);
  }
  vector<P>aa;
  for(auto t:a) if(!vis[t.id] && aa.size()<3) aa.pb(t);
  ::t=aa;
  if(cnt==2){
    //S2::solve2(b,t);
    puts("-1");
    exit(0);
  }
  //For(i,0,2) For(j,i+1,2) S2::solve2(b,vector<P>{t[i],t[j]});
  solve3();
  return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 5892kb

input:

6
10 15
20 15
15 23
0 31
15 0
30 30

output:

6
0 31
10 15
15 0
20 15
30 30
15 23

result:

ok Everything ok

Test #2:

score: 0
Accepted
time: 1ms
memory: 5668kb

input:

4
0 0
0 1
1 0
1 1

output:

-1

result:

ok Everything ok

Test #3:

score: 0
Accepted
time: 0ms
memory: 3844kb

input:

9
693150551 810053304
26684055 999173154
767007508 725151476
697948407 601311897
593914132 156628727
294286621 249587903
361249906 42266067
110658137 698550461
923704821 886066345

output:

6
26684055 999173154
693150551 810053304
923704821 886066345
767007508 725151476
593914132 156628727
697948407 601311897

result:

ok Everything ok

Test #4:

score: -100
Wrong Answer
time: 1ms
memory: 5672kb

input:

9
870407732 947373192
362190573 311657719
792350850 916217578
908809410 529664178
147184624 105531482
800863654 27569449
290489622 819212758
64484618 355712627
474856219 425123887

output:

-1

result:

wrong answer Jury has a better answer