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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#666336 | #7619. Make SYSU Great Again I | MiniLong | WA | 0ms | 5752kb | C++14 | 3.4kb | 2024-10-22 17:54:57 | 2024-10-22 17:54:57 |
Judging History
answer
#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
#ifdef ONLINE_JUDGE
char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
#define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
#else
#define get() getchar()
#endif
template<typename T> inline void read(T &t){
T x = 0, f = 1;
char c = getchar();
while(!isdigit(c)){
if(c == '-') f = -f;
c = getchar();
}
while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
t = x * f;
}
template<typename T, typename ... Args> inline void read(T &t, Args&... args){
read(t);
read(args...);
}
template<typename T> void write(T t){
if(t < 0) putchar('-'), t = -t;
if(t >= 10) write(t / 10);
putchar(t % 10 + '0');
}
template<typename T, typename ... Args> void write(T t, Args... args){
write(t), putchar(' '), write(args...);
}
template<typename T> void writeln(T t){
write(t);
puts("");
}
template<typename T> void writes(T t){
write(t), putchar(' ');
}
#undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
const ll mod = 998244353;
ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
void add(ll &x, ll y){x = (x + y) % mod;}
void mul(ll &x, ll y){x = x * y % mod;}
ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
const int N = 2e5 + 5, M = 1e6 + 5;
int n, k;
PII a[N];
map<PII, bool> vis;
int main(){
read(n, k);
if(n % 2 == 0){
_rep(i, 1, n / 2){
a[2 * i - 1] = {i, 2 * i - 1};
a[2 * i] = {i, 2 * i};
a[2 * i - 1 + n] = {i + n / 2, 2 * i};
a[2 * i + n] = {i + n / 2, 2 * i - 1};
}
}else{
if(n == 3){
a[1] = {1, 1}, a[2] = {1, 2}, a[3] = {2, 2}, a[4] = {2, 3}, a[5] = {3, 3}, a[6] = {3, 1};
}else{
_rep(i, 1, n / 2){
a[2 * i - 1] = {i, 2 * i - 1};
a[2 * i] = {i, 2 * i};
a[2 * i + n] = {i + n / 2 + 1, 2 * i};
a[2 * i + n + 1] = {i + n / 2 + 1, 2 * i + 1};
}
a[n] = {n / 2 + 1, n}, a[n + 1] = {n / 2 + 1, 1};
swap(a[2 * n], a[2 * n - 2]);
}
}
_rep(i, 1, 2 * n) vis[{a[i].fi, a[i].se}] = 1;
int cnt = 2 * n;
_rep(i, 1, n){
_rep(j, 1, n){
if(cnt > k) break;
if(vis[{i, j}]) continue;
a[++cnt] = {i, j};
}
if(cnt > k) break;
}
_rep(i, 1, k) write(a[i].fi, a[i].se), puts("");
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 5752kb
input:
3 6
output:
1 1 1 2 2 2 2 3 3 3 3 1
result:
ok The answer is correct.
Test #2:
score: 0
Accepted
time: 0ms
memory: 3520kb
input:
3 7
output:
1 1 1 2 2 2 2 3 3 3 3 1 1 3
result:
ok The answer is correct.
Test #3:
score: 0
Accepted
time: 0ms
memory: 3524kb
input:
2 4
output:
1 1 1 2 2 2 2 1
result:
ok The answer is correct.
Test #4:
score: 0
Accepted
time: 0ms
memory: 5752kb
input:
3 9
output:
1 1 1 2 2 2 2 3 3 3 3 1 1 3 2 1 3 2
result:
ok The answer is correct.
Test #5:
score: -100
Wrong Answer
time: 0ms
memory: 3708kb
input:
10 20
output:
1 1 1 2 2 3 2 4 3 5 3 6 4 7 4 8 5 9 5 10 6 2 6 1 7 4 7 3 8 6 8 5 9 8 9 7 10 10 10 9
result:
wrong answer The answer is wrong: The maximum common divisor of row 6 and column 483382400 is not the same.