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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#664694#2788. HorsesPioneer0 2ms9940kbC++203.5kb2024-10-21 21:47:582024-10-21 21:47:58

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你现在查看的是最新测评结果

  • [2024-10-21 21:47:58]
  • 评测
  • 测评结果:0
  • 用时:2ms
  • 内存:9940kb
  • [2024-10-21 21:47:58]
  • 提交

answer

#include "horses.h"
#include <bits/stdc++.h>

#define ll long long
using namespace std;

const ll inf=1e9;
const int mod=1e9+7;
const int MAX=5e5+10;

int x[MAX];
int y[MAX];

struct segtree{
	pair<int,bool> t[4*MAX];

	pair<int,bool> mrg(pair<int,bool> a,pair<int,bool> b){
		pair<int,bool> res={a.first*1ll*b.first%mod,(a.second|b.second)};
		if(a.first*1ll*b.first>=mod){
			res.second=1;
		}
		return res;
	}

	void build(int v,int tl,int tr){
		cerr<<v<<" "<<tl<<" "<<tr<<"\n";
		if(v==0)exit(0);
		if(tl==tr){
			t[v]={x[tl],0};
			return;
		}
		int tm=(tl+tr)/2;
		build(2*v,tl,tm);
		build(2*v+1,tm+1,tr);
		t[v]=mrg(t[2*v],t[2*v+1]);
	}

	void update(int v,int tl,int tr,int pos,int x){
		if(tl==tr){
			t[v]={x,0};
			return;
		}
		int tm=(tl+tr)/2;
		if(pos<=tm)update(2*v,tl,tm,pos,x);
		else update(2*v+1,tm+1,tr,pos,x);
		t[v]=mrg(t[2*v],t[2*v+1]);
	}


	pair<int,bool> get(int v,int tl,int tr,int l,int r){
		if(l>r||tl>r||l>tr)return {1,0};
		if(l<=tl&&tr<=r)return t[v];
		int tm=(tl+tr)/2;
		return mrg(get(2*v,tl,tm,l,r),get(2*v+1,tm+1,tr,l,r));
	}
}tx;


struct segtreeMx{
	pair<int,int> t[MAX];

	pair<int,int> mrg(pair<int,int> a,pair<int,int> b){
		if(a.first>=b.first)return a;
		else return b;
	}

	void build(int v,int tl,int tr){
		if(tl==tr){
			t[v]={y[tl],tl};
			return;
		}
		int tm=(tl+tr)/2;
		build(2*v,tl,tm);
		build(2*v+1,tm+1,tr);
		t[v]=mrg(t[2*v],t[2*v+1]);
	}

	void update(int v,int tl,int tr,int pos,int x){
		if(tl==tr){
			t[v]={x,tl};
			return;
		}
		int tm=(tl+tr)/2;
		if(pos<=tm)update(2*v,tl,tm,pos,x);
		else update(2*v+1,tm+1,tr,pos,x);
		t[v]=mrg(t[2*v],t[2*v+1]);
	}

	pair<int,int> get(int v,int tl,int tr,int l,int r){
		if(l>r||tl>r||l>tr)return {0,0};
		if(l<=tl&&tr<=r)return t[v];
		int tm=(tl+tr)/2;
		return mrg(get(2*v,tl,tm,l,r),get(2*v+1,tm+1,tr,l,r));
	}
}ty;

int n;
set<int> st;

int get(int pos){
	int ans=1;
	for(int i=1;i<=pos;i++)ans=ans*1ll*x[i]%mod;
	assert(ans==tx.get(1,1,n,1,pos).first);
	return ans*1ll*y[pos]%mod;
	return tx.get(1,1,n,1,pos).first*1ll*y[pos]%mod;
}

int get(){
	{
		int pos=n;
		int per=x[n]*1ll*y[n]%mod;
		bool bf=0;
		if(x[n]*1ll*y[n]>=mod)bf=1;
		for(int i=n-1;i>=max(1,n-1000);i--){
			if(!bf&&y[i]>=per){
				pos=i;
				per=y[i];
				bf=0;
			}
			if(per*1ll*x[i]>=mod){
				bf=1;
			}
			per=per*1ll*x[i]%mod;
		}
		return get(pos);
	}
	st.insert(1);
	vector<int> vec;
	int pos=ty.get(1,1,n,*st.rbegin(),n).second;
	vec.push_back(*st.rbegin());
	st.erase(--st.end());
	while(!st.empty()){
		int pos1=ty.get(1,1,n,*st.rbegin(),vec.back()-1).second;
		vec.push_back(*st.rbegin());
		st.erase(--st.end());
		pair<int,bool> bf=tx.get(1,1,n,pos1+1,pos);
		if(bf.second||bf.first*1ll*y[pos]>=mod)break;
		if(bf.first*y[pos]<=y[pos1])pos=pos1;
	}
	for(int x:vec)st.insert(x);
	return get(pos);
}

int init(int N, int X[], int Y[]) {
	cout<<N<<"\n";
	n=N;
	for(int i=0;i<N;i++){
		y[i+1]=Y[i];
		x[i+1]=X[i];
		if(X[i]!=1){
			st.insert(i+1);
		}
	}
	n=N;
	// cerr<<"! "<<N<<" "<<n<<"\n";
	tx.build(1,1,n);
	ty.build(1,1,n);
	// for(int i=1;i<=n;i++){
	// 	cout<<tx.get(1,1,n,2,i).first<<" "<<tx.get(1,1,n,1,i).second<<"\n";
	// }
	// cout<<"\n";
	return 0;
	// return get();
}

int updateX(int pos, int val) {	
	return 0;
	pos++;
	if(x[pos]!=1)st.erase(pos);
	x[pos]=val;
	tx.update(1,1,n,pos,val);
	if(x[pos]!=1)st.insert(pos);
	return get();
}

int updateY(int pos, int val) {
	return 0;
	pos++;
	y[pos]=val;
	ty.update(1,1,n,pos,val);
	return get();
}

详细

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 0
Wrong Answer
time: 2ms
memory: 9940kb

input:

1
2
3
0

output:

1
0

result:

wrong answer 1st lines differ - expected: '6', found: '1'

Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Time Limit Exceeded

Test #33:

score: 0
Time Limit Exceeded

input:

500000
2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2...

output:

500000

result:


Subtask #4:

score: 0
Skipped

Dependency #2:

0%

Subtask #5:

score: 0
Skipped

Dependency #1:

0%