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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#661465#9250. Max GCDlllei#TL 4ms9808kbC++203.1kb2024-10-20 16:21:502024-10-20 16:21:51

Judging History

你现在查看的是最新测评结果

  • [2024-10-20 16:21:51]
  • 评测
  • 测评结果:TL
  • 用时:4ms
  • 内存:9808kb
  • [2024-10-20 16:21:50]
  • 提交

answer

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#pragma GCC optimize("Ofast,unroll-loops")
#pragma GCC target("avx2,tune=native,popcnt,lzcnt,abm,bmi,bmi2,fma")
using namespace __gnu_pbds;
using namespace std;
using LL = long long;


struct MyHash {
    LL operator()(pair<int, int> x) const {
        return ((1LL * x.first) << 31)  + x.second;
    }
};

const int N = 1e6 + 5;
int n, q;
int a[N];
vector<int> P[N];
struct qr {
    int x, y, v, type;
} node[N * 36], tmp[N * 36];
int ans[N];
void cdq(int l, int r) {
    if (l == r)
        return;
    int mid = l + r >> 1;
    cdq(l, mid);
    cdq(mid + 1, r);
    int p = l, q = mid + 1;
    int mx = 0, t = 0;
    while (p <= mid && q <= r) {
        if (node[p].x >= node[q].x) {
            if (node[p].type == 0)
                mx = max(mx, node[p].v);
            tmp[++t] = node[p];
            p++;
        } else if (node[p].x < node[q].x) {
            if (node[q].type == 1)
                ans[node[q].v] = max(ans[node[q].v], mx);
            tmp[++t] = node[q];
            q++;
        }
    }
    while (p <= mid) {
        if (node[p].type == 0)
            mx = max(mx, node[p].v);
        tmp[++t] = node[p];
        p++;
    }
    while (q <= r) {
        if (node[q].type == 1)
            ans[node[q].v] = max(ans[node[q].v], mx);
        tmp[++t] = node[q];
        q++;
    }
    for (int i = l; i <= r; i++)
        node[i] = tmp[i - l + 1];
}
int m;
int query(const vector<int> &v, int p) {
    int l = 0, r = (int)(v.size()) - 1, ans = -1;
    while (l <= r) {
        int mid = l + r >> 1;
        if (v[mid] >= p)
            ans = mid, r = mid - 1;
        else
            l = mid + 1;
    }
    return ans;
}
int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    cin >> n >> q;
    for (int i = 1; i <= n; i++)
        cin >> a[i];
    for (int i = 1; i <= n; i++) {
        int lim = sqrt(a[i]);
        for (int j = 1; j <= lim; j++) {
            if (a[i] % j == 0) {
                P[j].push_back(i);
                if (j * j != a[i])
                    P[a[i] / j].push_back(i);
            }
        }
    }
    gp_hash_table<pair<int, int>, int, MyHash> table;

    for (int i = 1; i <= 1000000; i++) {
        int lim = P[i].size();
        for (int j = 0; j < lim - 1; j++) {
            int t = P[i][j + 1] * 2 - P[i][j];
            int r = query(P[i], t);
            if (r != -1) {
                table[{P[i][j], P[i][r]}] = max(table[{P[i][j], P[i][r]}], i);
                // cout<<P[i][j]<<' '<<P[i][j+1]<<' '<<i<<' '<<P[i][r]<<'\n';
                // node[++m] = {P[i][j], P[i][r], i, 0};
            }
        }
    }
    for (const auto [x, y] : table) {
        node[++m] = {x.first, x.second, y, 0};
    }
    for (int i = 1; i <= q; i++) {
        int l, r;
        cin >> l >> r;
        node[++m] = {l, r, i, 1};
    }
    sort(node + 1, node + m + 1, [](const qr &a, const qr &b) { return a.y == b.y ? (a.x == b.x ? a.type < b.type : a.x > b.x) : a.y < b.y; });
    cdq(1, m);
    for (int i = 1; i <= q; i++)
        cout << ans[i] << '\n';
}

詳細信息

Test #1:

score: 100
Accepted
time: 4ms
memory: 9808kb

input:

8 8
8 24 4 6 6 7 3 3
1 5
2 6
3 7
5 8
4 8
1 3
2 5
3 8

output:

4
2
3
1
3
4
2
3

result:

ok 8 tokens

Test #2:

score: -100
Time Limit Exceeded

input:

150000 100000
982800 554400 665280 982800 997920 720720 786240 831600 997920 982800 786240 982800 942480 831600 887040 665280 831600 960960 786240 982800 786240 942480 665280 831600 942480 665280 982800 960960 960960 997920 720720 960960 960960 665280 982800 665280 982800 942480 786240 997920 554400...

output:


result: