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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#659328 | #5414. Stop, Yesterday Please No More | He_ng# | WA | 1ms | 3756kb | C++17 | 3.2kb | 2024-10-19 19:38:34 | 2024-10-19 19:38:35 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define pii pair<int, int>
const int N = 1e6;
const int M = 1e3 + 10;
void solve()
{
int n, m, k;
cin >> n >> m >> k;
vector<int> a(5, 0);
vector<int> b(5, 0);
vector<vector<int>> mp(n + 100, vector<int>(m + 100, 0));
vector<vector<int>> sum(n + 100, vector<int>(m + 100, 0));
string s;
cin >> s;
int l = s.size();
s = " " + s;
for (int i = 1; i <= l; i++)
{
if (s[i] == 'U')
{
if (b[2] == 0)
a[1]++;
else
{
b[2]--;
}
b[1]++;
}
else if (s[i] == 'D')
{
if (b[1] == 0)
a[2]++;
else
{
b[1]--;
}
b[2]++;
}
else if (s[i] == 'L')
{
if (b[4] == 0)
a[3]++;
else
{
b[4]--;
}
b[3]++;
}
else
{
if (b[3] == 0)
a[4]++;
else
{
b[3]--;
}
b[4]++;
}
}
int x1 = 0, x2 = 0, y1 = 0, y2 = 0;
x1 = a[1] + 1;
y1 = a[2] + 1;
x2 = n - a[3];
y2 = m - a[4];
if(x1>x2||y1>y2){
if (k > 0)
{
cout << 0 << endl;
return;
}
cout << n * m << endl;
return;
}
if (x1 > n || y1 > m || x2 < 1 || y2 < 1)
{
if (k > 0)
{
cout << 0 << endl;
return;
}
cout << n * m << endl;
return;
}
x1 = max(a[1] + 1, 1ll);
y1 = max(1ll, a[3] + 1);
x2 = min(n, n - a[3]);
y2 = max(m, m - a[4]);
for (int i = x1; i <= x2; ++i)
for (int j = y1; j <= y2; ++j)
mp[i][j] = 1;
for (int i = 1; i <= n; ++i)
for (int j = 1; j <= m; ++j)
sum[i][j] = mp[i][j] - mp[i - 1][j] - mp[i][j - 1] + mp[i - 1][j - 1];
int ss = (x2 - x1 + 1) * (y2 - y1 + 1);
if (k > ss)
{
cout << 0 << endl;
return;
}
for (int i = 1; i <= l; i++)
{
if (s[i] == 'U')
{
x1 -= 1;
x2 -= 1;
}
else if (s[i] == 'D')
{
x1 += 1;
x2 += 1;
}
else if (s[i] == 'L')
{
y1 -= 1;
y2 -= 1;
}
else
{
y1 += 1;
y2 += 1;
}
sum[x1][y1] += 1;
sum[x2 + 1][y2 + 1] += 1;
sum[x1][y2 + 1] -= 1;
sum[x2 + 1][y1] -= 1;
}
int ans = 0;
for (int i = 1; i <= n; ++i)
{
for (int j = 1; j <= m; ++j)
{
sum[i][j] = sum[i][j] + sum[i - 1][j] + sum[i][j - 1] - sum[i - 1][j - 1];
if (sum[i][j] == ss - k)
{
ans++;
}
}
cout << endl;
}
return;
}
signed main()
{
ios::sync_with_stdio(false);
cin.tie(0);
int t = 1;
cin >> t;
while (t--)
solve();
return 0;
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 1ms
memory: 3756kb
input:
3 4 5 3 ULDDRR 4 5 0 UUUUUUU 4 5 10 UUUUUUU
output:
20 0
result:
wrong answer 1st numbers differ - expected: '2', found: '20'