QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#651778#3083. Bit Operationxyz123WA 232ms55948kbC++231.9kb2024-10-18 18:01:252024-10-18 18:01:26

Judging History

你现在查看的是最新测评结果

  • [2024-10-18 18:01:26]
  • 评测
  • 测评结果:WA
  • 用时:232ms
  • 内存:55948kb
  • [2024-10-18 18:01:25]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
const long long mod=1e9+7;
long long T,a,b,c,d[1000001],v[1000001],o,h[1000001],fa[1000001],q,w,e,an,cn,fac[1000001],inv[1000001],st[1000001],u[1000001];
long long dp[1000001],pw[1000001],fc[1000001];
char s[1000001];
struct p{long long q,w;}l[1000001];
long long pow_(long long qq,long long ww){long long ee=1;while(ww){if(ww&1) ee*=qq,ee%=mod;qq*=qq,qq%=mod,ww>>=1;}return ee%mod;}
inline int read(){int x=0,f=1;char c=getchar();while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}while(c>='0'&&c<='9'){x=(x<<3)+(x<<1)+c-'0';c=getchar();}return x*f;}
void add(long long qq,long long ww){l[++o].q=ww,l[o].w=h[qq],h[qq]=o;}
long long gcd(long long qq,long long ww){return !ww?qq:gcd(ww,qq%ww);}
long long find(long long qq){return qq==fa[qq]?qq:fa[qq]=find(fa[qq]);}
void merge(long long qq,long long ww){long long f1=find(qq),f2=find(ww);if(f1==f2) return;fa[f1]=f2;}
long long C(long long qq,long long ww){return fac[qq]*inv[ww]%mod*inv[qq-ww]%mod;}
int main()
{
//	freopen("1.in","r",stdin);
	srand((unsigned)(time(0)^(*new int)));
	fac[0]=1;for(int i=1;i<=1000000;i++) fac[i]=fac[i-1]*i%mod;
	inv[1000000]=pow_(fac[1000000],mod-2);for(int i=999999;i>=0;i--) inv[i]=inv[i+1]*(i+1)%mod;
	fc[0]=1;
	for(int i=1;i<=1000000;i++) fc[i]=fc[i-1]*pow_(2,mod-2)%mod*(2*i-1)%mod;
	pw[0]=1;
	for(int i=1;i<=1000000;i++) pw[i]=pw[i-1]*2%mod;
	scanf("%lld",&a);
	for(int i=1;i<=a;i++)
	{
		scanf("%lld",&d[i]);
	}
	for(int i=1;i<=a;i++)
	{
		dp[i]=fc[i-1]*fc[a-i]%mod*pow_(2,a-1)%mod*C(a-1,i-1)%mod;
	}
	for(int i=1;i<=a;i++)
	{
		if(d[i]) an=(an+dp[i])%mod;
	}
//	for(int i=2;i<=a;i++)
//	{
//		for(int j=1;j+i-1<=a;j++)
//		{
//			int r=j+i-1;
//			for(int k=j;k<r;k++)
//			{
//				dp[j][r]=(dp[j][r]+(dp[j][k]*pw[r-k-1]%mod+dp[k+1][r]*pw[k-j]%mod)*pow_(r-j,mod-2))%mod;
//			}
//		}
//	}
	printf("%lld",(an%mod+mod)%mod);
	return 0;
}

详细

Test #1:

score: 0
Wrong Answer
time: 232ms
memory: 55948kb

input:

999993
1 0 0 1 1 0 0 1 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 1 1 0 1 0 0 0 0 1 0 0 0 0 0 1 1 0 1 1 1 1 0 1 0 0 0 1 0 0 0 0 1 0 1 0 1 0 0 1 1 1 1 0 1 1 0 0 1 0 1 1 1 0 0 1 1 0 1 0 0 0 1 0 1 0 1 0 0 0 0 0 1 1 0 0 1 0 0 0 0 1 0 0 0 1 0 0 0 1 1 0 0 1 0 1 1 0 1 0 0 0 0 1 1 1 1 0 1 0 1 0 0 1 1 0 0 0 0 0 0 1 1...

output:

177804889

result:

wrong answer 1st lines differ - expected: '318158140', found: '177804889'