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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#648629#7904. Rainbow SubarrayLyniaTL 1366ms6744kbC++234.3kb2024-10-17 19:43:212024-10-17 19:43:24

Judging History

你现在查看的是最新测评结果

  • [2024-10-17 19:43:24]
  • 评测
  • 测评结果:TL
  • 用时:1366ms
  • 内存:6744kb
  • [2024-10-17 19:43:21]
  • 提交

answer

///////////        
//                   //      //
//              ////////////////////
//                   //      //
//                 
///////////

//          
//          
//           //     //    ////////     /\     /////////
//           //     //   //      //          //       //
//            ////////   //      //    //    //       //
//                  //   //      //    //    //       //
//////////   ////////    //      //    //     /////////////

#pragma GCC optimize(2)
#include <iostream>
#include <iomanip>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <string>
#include <cstring>
#include <cmath>
#include <list>
#include <stack>
#include <array>
#include <unordered_map>
#include <unordered_set>
#include <bitset>
#include <random>
#include <numeric>
#include <functional>
//#include <Windows.h>

using namespace std;

#define fa(i,op,n) for (int i = op; i <= n; i++)
#define fb(j,op,n) for (int j = op; j >= n; j--)
#define pb push_back
#define HashMap unordered_map
#define HashSet unordered_set
#define var auto
#define all(i) i.begin(), i.end()
#define endl '\n'
#define px first
#define py second
#define DEBUG(a) cout<<a<<endl

using VI = vector<int>;
using VL = vector<long long>;
using ll = long long;
using ull = unsigned long long;
using db = double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;

template<class T1, class T2>
ostream& operator<<(ostream& out, const pair<T1, T2>& p) {
	out << '(' << p.first << ", " << p.second << ')';
	return out;
}

template<typename T>
ostream& operator<<(ostream& out, const vector<T>& ve) {
	for (T i : ve)
		out << i << ' ';
	return out;
}

template<class T1, class T2>
ostream& operator<<(ostream& out, const map<T1, T2>& mp) {
	for (auto i : mp)
		out << i << '\n';
	return out;
}

const int INF = 0x3f3f3f3f;
const ll LNF = 0x3f3f3f3f3f3f3f3f;
const int IINF = 0x7fffffff;
const int iinf = 0x80000000;
const ll LINF = 0x7FFFFFFFFFFFFFFF;
const ll linf = 0x8000000000000000;
int dx[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };
int dy[8] = { 0, 0, 1, -1, 1, -1, -1, 1 };

//#include "Lynia.h"

const int mod = 998244353;
const int N = 1e6 + 10;

void solve(int CASE)
{
	ll n, k; cin >> n >> k;
	var a = vector<ll>(n + 1, 0);
	fa(i, 1, n)cin >> a[i], a[i] -= i;

	var check = [&](ll mid)->bool {
		multiset<ll>r;
		multiset<ll, greater<ll>>l;
		ll l_sum = 0, r_sum = 0;

		var f = [&]()->void {
			ll tmp;
			while (l.size() and (*l.begin()) > (*r.begin())) {
				tmp = (*l.begin());
				r_sum += tmp, r.insert(tmp);
				l_sum -= tmp, l.erase(l.find(tmp));
			}
			if (mid & 1) {
				while (l.size() < r.size() + 1) {
					tmp = (*r.begin());
					l_sum += tmp, l.insert(tmp);
					r_sum -= tmp, r.erase(r.find(tmp));
				}
				while (l.size() > r.size() + 1) {
					tmp = (*l.begin());
					r_sum += tmp, r.insert(tmp);
					l_sum -= tmp, l.erase(l.find(tmp));
				}
			}
			else {
				while (l.size() < r.size()) {
					tmp = (*r.begin());
					l_sum += tmp, l.insert(tmp);
					r_sum -= tmp, r.erase(r.find(tmp));
				}
				while (l.size() > r.size()) {
					tmp = (*l.begin());
					r_sum += tmp, r.insert(tmp);
					l_sum -= tmp, l.erase(l.find(tmp));
				}
			}
			};

		fa(i, 1, mid) {
			if (l.size() == 0)l_sum += a[i], l.insert(a[i]);
			else {
				if (a[i] <= (*l.begin()))l_sum += a[i], l.insert(a[i]);
				else r_sum += a[i], r.insert(a[i]);
			}
		}

		f(); // 刷新双set
		ll mmid = (*l.begin()); // 中位数
		ll mn = (mmid * (ll)l.size() - l_sum) + (r_sum - mmid * (ll)r.size());

		fa(i, mid + 1, n) {
			if (l.count(a[i - mid])) l_sum -= a[i - mid], l.erase(l.find(a[i - mid]));
			else r_sum -= a[i - mid], r.erase(r.find(a[i - mid]));

			if (a[i] <= (*l.begin()))l_sum += a[i], l.insert(a[i]);
			else r_sum += a[i], r.insert(a[i]);

			f(); // 刷新双set
			mmid = (*l.begin()); // 中位数
			mn = min(mn, (mmid * (ll)l.size() - l_sum) + (r_sum - mmid * (ll)r.size()));
		}

		return mn <= k;
		};

	ll l = 1, r = n;
	while (l < r) {
		ll mid = l + r + 1 >> 1;
		if (check(mid))l = mid;
		else r = mid - 1;
	}
	cout << l << endl;
	return;
}

int main()
{
	//SetConsoleOutputCP(CP_UTF8);
	ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
	int _ = 1;
	cin >> _;
	fa(i, 1, _)solve(i);
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3584kb

input:

5
7 5
7 2 5 5 4 11 7
6 0
100 3 4 5 99 100
5 6
1 1 1 1 1
5 50
100 200 300 400 500
1 100
3

output:

4
3
5
1
1

result:

ok 5 lines

Test #2:

score: 0
Accepted
time: 1366ms
memory: 6744kb

input:

11102
2 167959139
336470888 134074578
5 642802746
273386884 79721198 396628655 3722503 471207868
6 202647942
268792718 46761498 443917727 16843338 125908043 191952768
2 717268783
150414369 193319712
6 519096230
356168102 262263554 174936674 407246545 274667941 279198849
9 527268921
421436316 3613460...

output:

1
4
3
2
6
5
7
2
4
1
4
1
1
3
2
2
7
8
7
7
1
7
6
2
4
3
1
6
7
7
3
4
3
9
3
8
6
6
3
1
6
3
1
2
4
6
4
6
4
1
4
7
1
6
3
5
6
6
1
7
5
3
1
6
4
5
3
2
2
6
2
3
10
1
4
3
2
4
5
1
7
5
5
5
8
5
3
6
3
5
5
8
5
4
5
2
1
5
2
3
3
4
8
1
3
1
2
2
8
3
1
6
8
1
8
4
5
6
6
8
4
8
3
2
8
4
5
6
2
6
2
4
1
5
4
5
3
2
4
1
2
1
4
5
8
3
7
3
3
3...

result:

ok 11102 lines

Test #3:

score: -100
Time Limit Exceeded

input:

1
500000 17244641009859
54748096 75475634 204928248 276927808 84875072 103158867 27937890 322595515 186026685 45468307 69240390 139887597 188586447 373764525 121365644 310156469 185188306 60350786 211308832 384695957 370562147 208427221 35937909 267590963 126478310 275357775 55361535 335993561 36696...

output:


result: