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#647034#9242. An Easy Geometry Problemicpc_zhzx034#RE 16ms41424kbC++144.4kb2024-10-17 11:10:532024-10-17 11:10:53

Judging History

你现在查看的是最新测评结果

  • [2024-10-17 11:10:53]
  • 评测
  • 测评结果:RE
  • 用时:16ms
  • 内存:41424kb
  • [2024-10-17 11:10:53]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair <ll,ll> P;
#define _for(x,y,z) for (int x(y),_(z); x<=_; ++x)
#define _rep(x,y,z) for (int x(y),_(z); x>=_; --x)
inline ll read(){ ll x; scanf("%lld",&x); return x; }
inline void _init(){
	#ifdef LOCAL
		assert(freopen("test.in", "r", stdin));
		assert(freopen("test.out", "w", stdout));
	#endif
	ios::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);
}

const int N = 2e5 + 5;

const ll base = 2131073233ll;
const ll mod = (ll)1e18 + 3;
ll pw[N], qz[N];
ll n, q, k, B, a[N], b[N], c[N];
struct Hsh{
	ll hsh, sz;
	Hsh(ll a=0, ll b=0){ hsh=a, sz=b; }
};
Hsh operator+ (Hsh A, Hsh B){
	return Hsh((A.hsh+(__int128)pw[A.sz]*B.hsh)%mod, A.sz+B.sz);
}

struct Seg1{
	Hsh t[4*N]; ll tag[4*N],len[4*N];
	void pushup(ll pos){
		t[pos]=t[pos<<1]+t[pos<<1|1];
	}
	void upd(ll pos,ll v){
		t[pos].hsh = (t[pos].hsh + (__int128)(v + mod) * qz[t[pos].sz-1]) % mod;
		tag[pos] = (tag[pos] + v) % mod;
	}
	void pushdown(ll pos){
		if(tag[pos]){
			upd(pos<<1, tag[pos]);
			upd(pos<<1|1, tag[pos]);
			tag[pos]=0;
		}
	}
	void build(ll l,ll r,ll pos){
		if(l==r){
			t[pos] = Hsh(b[l]<0?mod+b[l]:b[l], 1);
			// cout<<"at "<<l<<" is "<<(b[l]<0?mod+b[l]:b[l])<<endl;
			return;
		}
		ll mid=(l+r)>>1;
		if(l<=mid) build(l,mid,pos<<1);
		if(mid<r) build(mid+1,r,pos<<1|1);
		pushup(pos);
	}
	void update(ll l,ll r,ll ql,ll qr,ll v,ll pos){
		if(ql<=l && r<=qr){
			upd(pos, v);
			return;
		}
		ll mid=(l+r)>>1;
		pushdown(pos);
		if(ql<=mid) update(l,mid,ql,qr,v,pos<<1);
		if(mid<qr)  update(mid+1,r,ql,qr,v,pos<<1|1);
		pushup(pos);
	}
	Hsh ans;
	void query(ll l,ll r,ll ql,ll qr,ll pos){
		if(ql>qr) return;
		if(ql<=l && r<=qr) {
			ans = ans + t[pos];
			return;
		}
		ll mid=(l+r)>>1;
		pushdown(pos);
		if(ql<=mid) query(l,mid,ql,qr,pos<<1);
		if(mid<qr)  query(mid+1,r,ql,qr,pos<<1|1);
		pushup(pos);
	}
	ll hash(ll l,ll r,ll op=0){
		ans=Hsh(0,0);
		query(1,n,l,r,1);
		// if(op) cout<<"between "<<l<<" "<<r<<" hash = "<<ans.hsh<<endl;
		return ans.hsh;
	}
}S;


struct Seg2{
	Hsh t[4*N]; ll tag[4*N],len[4*N];
	void pushup(ll pos){
		t[pos]=t[pos<<1|1]+t[pos<<1];
	}
	void upd(ll pos,ll v){
		t[pos].hsh = (t[pos].hsh + (__int128)(v + mod) * qz[t[pos].sz-1]) % mod;
		tag[pos] = (tag[pos] + v) % mod;
	}
	void pushdown(ll pos){
		if(tag[pos]){
			upd(pos<<1, tag[pos]);
			upd(pos<<1|1, tag[pos]);
			tag[pos]=0;
		}
	}
	void build(ll l,ll r,ll pos){
		if(l==r){
			t[pos] = Hsh(b[l]<0?mod+b[l]:b[l], 1);
			// cout<<"at "<<l<<" is "<<(b[l]<0?mod+b[l]:b[l])<<endl;
			return;
		}
		ll mid=(l+r)>>1;
		if(l<=mid) build(l,mid,pos<<1);
		if(mid<r) build(mid+1,r,pos<<1|1);
		pushup(pos);
	}
	void update(ll l,ll r,ll ql,ll qr,ll v,ll pos){
		if(ql<=l && r<=qr){
			upd(pos, v);
			return;
		}
		ll mid=(l+r)>>1;
		pushdown(pos);
		if(ql<=mid) update(l,mid,ql,qr,v,pos<<1);
		if(mid<qr)  update(mid+1,r,ql,qr,v,pos<<1|1);
		pushup(pos);
	}
	Hsh ans;
	void query(ll l,ll r,ll ql,ll qr,ll pos){
		if(ql>qr) return;
		if(ql<=l && r<=qr) {
			ans = t[pos] + ans;
			return;
		}
		ll mid=(l+r)>>1;
		pushdown(pos);
		if(ql<=mid) query(l,mid,ql,qr,pos<<1);
		if(mid<qr)  query(mid+1,r,ql,qr,pos<<1|1);
		pushup(pos);
	}
	ll hash(ll l,ll r,ll op=0){
		ans=Hsh(0,0);
		query(1,n,l,r,1);
		// if(op) cout<<"between "<<l<<" "<<r<<" hash = "<<ans.hsh<<endl;
		return ans.hsh;
	}
}T;

void init() {
	pw[0] = qz[0] = 1;
	for(ll i=1;i<N;i++) pw[i]=(__int128)pw[i-1]*base%mod;
	for(ll i=1;i<N;i++) qz[i]=(qz[i-1]+pw[i])%mod;
}
void procedure() {
	n=read(), q=read(), k=read(), B=2*read();
	for(ll i=1;i<=n;i++){
		a[i]=read();
		b[i]=2*a[i]-i*k+1e9;
	}

	// for(ll i=1;i<=n;i++) cout<<b[i]<<" "; cout<<endl;
	S.build(1,n,1); T.build(1,n,1);
	while(q--){
		ll op=read();
		if(op==1){
			ll l=read(), r=read(), v=read()*2;
			S.update(1,n,l,r,v,1); T.update(1,n,l,r,v,1);
		}else{
			ll x=read();
			ll l=1, r=min(x-1, n-x), ans=0;
			S.update(1,n,1,x-1,B,1);
			while(l<=r){
				ll mid=(l+r)>>1;
				if(S.hash(x-mid,x-1,1) == T.hash(x+1,x+mid,1)){
					ans=mid; l=mid+1;
				}else r=mid-1;
			}
			S.update(1,n,1,x-1,-B,1);
			// cout<<ans<<endl;
			printf("%lld\n", ans);
		}

		// cout<<"now "; for(ll i=1;i<=n;i++) cout<<S.hash(i,i)<<" "; cout<<endl;
	}
}

int main() {
	_init(), init();
	int T=1;
	while(T--) procedure();
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 41168kb

input:

6 6 6 2
1 5 9 10 15 18
2 2
1 3 3 -3
2 2
1 3 4 3
2 3
2 4

output:

1
0
2
0

result:

ok 4 number(s): "1 0 2 0"

Test #2:

score: 0
Accepted
time: 16ms
memory: 41424kb

input:

5000 5000 2 0
-329 -328 -327 -326 -325 -324 -323 -322 -321 -320 -319 -318 -317 -316 -315 -314 -313 -312 -311 -310 -309 -308 -307 -306 -305 -304 -303 -302 -301 -300 -299 -298 -297 -296 -295 -294 -293 -292 -291 -290 -289 -288 -287 -286 -285 -284 -283 -282 -281 -280 -279 -278 -277 -276 -275 -274 -273 -...

output:

2
304
73
29
61
292
139
48
17
99
6
5
53
93
3
91
65
29
33
306
21
24
17
21
281
12
16
1
33
7
18
96
7
40
39
13
7
46
43
16
1
72
33
16
22
5
6
189
27
1
35
107
43
34
3
27
20
21
44
56
96
36
2
27
22
30
32
6
5
105
27
37
12
58
2
21
154
17
110
57
3
7
33
15
24
94
68
25
1
14
10
4
10
2
25
39
36
33
164
11
19
181
11
3...

result:

ok 3337 numbers

Test #3:

score: -100
Runtime Error

input:

5000 5000 2 0
793 794 795 796 797 798 799 800 801 802 803 804 805 806 807 808 809 810 811 812 813 814 815 816 817 818 819 820 821 822 823 824 825 826 827 828 829 830 831 832 833 834 835 836 837 838 839 840 841 842 843 844 845 846 847 848 849 850 851 852 853 854 855 856 857 858 859 860 861 862 863 86...

output:


result: