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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#63930#2831. Game Theorypty6666RE 3ms3412kbC++143.6kb2022-11-23 18:28:232022-11-23 18:28:25

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-11-23 18:28:25]
  • 评测
  • 测评结果:RE
  • 用时:3ms
  • 内存:3412kb
  • [2022-11-23 18:28:23]
  • 提交

answer

#include <cstdio>
#include <cstring>
#include <queue>
#include <algorithm>
#include <iostream>
#include <cmath>
#include <random>
#include <ctime>
#include <string>
#define lson ( p << 1 )
#define rson ( p << 1 | 1 )
using namespace std;
typedef long long ll;
const int maxn = 2e6 + 10;
struct Tree{
	ll val[2][2];
	int lazy;
	int cnt[2];
}tree[maxn << 2];
int n,q;
string s;

Tree combine(Tree x,Tree y)
{
	Tree ret{};
	for(int i = 0;i<=1;i++){
		for(int j = 0;j<=1;j++){
			ret.val[i][j] = x.val[i][j] + y.val[i][j];
		}
		ret.cnt[i] = x.cnt[i] + y.cnt[i];
	}
	return ret;
}

void pushdown(int p)
{
	swap(tree[lson].val[0][0],tree[lson].val[1][0]);
	swap(tree[lson].val[0][1],tree[lson].val[1][1]);
	swap(tree[rson].val[0][0],tree[rson].val[1][0]);
	swap(tree[rson].val[0][1],tree[rson].val[1][1]);
	swap(tree[lson].cnt[0],tree[lson].cnt[1]);
	swap(tree[rson].cnt[0],tree[rson].cnt[1]);
	tree[lson].lazy ^= 1;
	tree[rson].lazy ^= 1;
	tree[p].lazy = 0;
}

void build(int l = 1,int r = n,int p = 1)
{
	tree[p].lazy = 0;
	if(l == r){
		for(int i =0;i<=1;i++){
			for(int j = 0;j<=1;j++){
				tree[p].val[i][j] = 0;
			}
			tree[p].cnt[i] = 0;
		}
		if(s[l] == '0'){
			tree[p].val[0][0] = l;
			tree[p].val[0][1] = n - l + 1;
			tree[p].cnt[0] = 1;
		}
		else {
			tree[p].val[1][0] = l;
			tree[p].val[1][1] = n - l + 1;
			tree[p].cnt[1] = 1;
		}
		return;
	}
	int mid = (l + r) >> 1;
	build(l,mid,lson);
	build(mid + 1,r,rson);
	for(int i = 0;i<=1;i++){
		for(int j = 0;j<=1;j++){
			tree[p].val[i][j] = tree[lson].val[i][j] + tree[rson].val[i][j];
		}
		tree[p].cnt[i] = tree[lson].cnt[i] + tree[rson].cnt[i];
	}
}

void update(int s,int t,int l = 1,int r = n,int p = 1)
{
	if(s <= l && r <= t){
		tree[p].lazy ^= 1;
		swap(tree[p].val[0][0],tree[p].val[1][0]);
		swap(tree[p].val[0][1],tree[p].val[1][1]);
		swap(tree[p].cnt[0],tree[p].cnt[1]);
		return;
	}
	int mid = (l +r ) >> 1;
	if(tree[p].lazy)
		pushdown(p);
	if(s <= mid)
		update(s,t,l,mid,lson);
	if(t > mid)
		update(s,t,mid + 1,r,rson);
	for(int i = 0;i<=1;i++){
		for(int j = 0;j<=1;j++){
			tree[p].val[i][j] = tree[lson].val[i][j] + tree[rson].val[i][j];
		}
		tree[p].cnt[i] = tree[lson].cnt[i] + tree[rson].cnt[i];
	}
}

Tree query(int s,int t,int l = 1,int r = n,int p = 1)
{
	if(s <= l && r <= t){
		return tree[p];
	}
	if(tree[p].lazy)
		pushdown(p);
	int mid = ( l + r) >> 1;
	if(s <= mid && t > mid)
		return combine(query(s,t,l,mid,lson), query(s,t,mid + 1,r,rson));
	else if(s <= mid)
		return query(s,t,l,mid,lson);
	else return query(s,t,mid + 1,r,rson);
}

int main() {
	ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	while(cin >> n >> q){
		cin >> s;
		s = " " + s;
		build();
		for(int i = 1;i<=q;i++){
			int l,r;
			cin >> l >> r;
			update(l,r);
			Tree temp = query(1,n);
			int k = temp.cnt[1];
			if(k == 0){
				cout << 0 << "\n";
			}
			Tree tt = query(k,k);
			ll ans = 0;
			if(tt.cnt[1] == 1) {
				Tree temp1 {};
				if ( k - 1 >= 1 )
					temp1 = query( 1, k - 1 );
				Tree temp2 = query(k,n);
				ans += temp2.val[1][0] - temp1.val[0][0];
				temp2 = {};
				if(k + 1 <= n)
					temp2 = query(k + 1,n);
				ans += temp1.val[0][1] - temp2.val[1][1];
				cout << ans << "\n";
			}
			else {
				Tree temp1 = query( 1, k );
				Tree temp2{};
				if(k + 1 <= n){
					temp2 = query(k + 1,n);
				}
				ans += temp1.val[0][1] - temp2.val[1][1];
				temp1 = {};
				if(k - 1 >= 1)
					temp1 = query(1,k - 1);
				ans += temp2.val[1][0] - temp1.val[0][0];
				cout << ans << "\n";
			}
		}
	}
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 3ms
memory: 3412kb

input:

3 2
010
1 2
2 3
5 1
00000
1 5

output:

1
3
5

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 3324kb

input:

1 1
0
1 1

output:

1

result:

ok single line: '1'

Test #3:

score: -100
Runtime Error

input:

2 2
01
2 2
2 2
2 2
01
1 2
1 2
1 2
1
1 1
1 1
1 2
1
1 1
1 1
2 2
00
1 2
1 2
2 2
11
1 2
1 2
2 2
01
2 2
1 1
2 2
10
2 2
1 2
2 2
01
1 2
1 2
1 2
0
1 1
1 1
2 2
01
1 2
2 2
1 2
0
1 1
1 1
1 2
1
1 1
1 1
2 2
10
1 2
1 1
1 2
0
1 1
1 1
2 2
01
1 2
1 2
2 2
10
1 2
1 1
1 2
0
1 1
1 1
1 2
0
1 1
1 1
1 2
1
1 1
1 1
2 2
10
1 ...

output:


result: