QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#631696#7900. Gifts from KnowledgePepinotWA 0ms3552kbC++202.1kb2024-10-12 09:43:522024-10-12 09:43:54

Judging History

你现在查看的是最新测评结果

  • [2024-10-12 09:43:54]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3552kb
  • [2024-10-12 09:43:52]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define pb push_back
#define fi first
#define se second
const int maxn = 1e6 + 5, inf = 1e18, maxm = 4e4 + 5, base = 37;
const int N = 1e6;
const int mod = 1e9 + 7;
int n, m;
int a[maxn];

// string s;

struct Node{
	int v, w;
};

struct DSU{
	vector<int> fa;
	DSU(int n) : fa(n) {
		for(int i = 0; i < n; i++){
			fa[i] = i;
		}
	} 
	int find(int x){
		if(x == fa[x]) return fa[x];
		fa[x] = find(fa[x]);
	}
	void merge(int x, int y){
		if(find(x) != find(y)){
			fa[find(x)] = find(y);
		}
	}
}; 

//long long ? maxn ? n? m?
void solve(){
	int res = 0;
	cin >> n >> m;
	vector<vector<int>> a(n + 5, vector<int>(m + 5));
	for(int i = 1; i <= n; i++){
		for(int j = 1; j <= m; j++){
			char ch;
			cin >> ch;
			a[i][j] = ch - '0';
		}
	}
	DSU d(2 * n + 5);
	for(int j = 1; j <= m / 2; j++){
		vector<int> vec[2];
		for(int i = 1; i <= n; i++){
			if(a[i][j]){
				vec[0].pb(i);
			}
			if(a[i][m - j + 1]){
				vec[1].pb(i);
			}
		}
		if(vec[0].size() + vec[1].size() >= 3){
			cout << 0 << '\n';
			return;
		}
		for(int x = 0; x < 2; x++){
			for(int y = 0; y < vec[x].size(); y++){
				for(int z = y + 1; z < vec[x].size(); z++){
					int u = vec[x][y], v = vec[x][z];
					d.merge(u + n, v);
					d.merge(u, v + n);
				}
			}
		}
		if(vec[0].size() && vec[1].size()){
			int u = vec[0][0], v = vec[1][0];
			d.merge(u, v);
			d.merge(u + n, v + n);
		}
	}
	if(m % 2 == 1){
		int j = (m + 1) / 2;
		vector<int> vec;
		for(int i = 1; i <= n; i++){
			if(a[i][j]){
				vec.pb(i);
			}
		}
		if(vec.size() >= 2){
			cout << 0 << '\n';
			return;
		}
	}
	for(int i = 1; i <= n; i++){
		if(d.find(i) == d.find(i + n)){
			cout << 0 << '\n';
			return;
		}
	}
	int cnt = 0;
	for(int i = 1; i <= 2 * n; i++){
		if(d.find(i) == i) cnt++;
	}
	cnt /= 2;
	res = 1;
	for(int i = 1; i <= cnt; i++){
		res = res * 2 % mod;
	}
	cout << res << '\n';
}   

signed main(){
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	cout << fixed << setprecision(9);
	int T = 1;
	cin >> T;
	while (T--)
		solve();
	return 0;
}

详细

Test #1:

score: 0
Wrong Answer
time: 0ms
memory: 3552kb

input:

3
3 5
01100
10001
00010
2 1
1
1
2 3
001
001

output:

1
0
1

result:

wrong answer 1st numbers differ - expected: '4', found: '1'