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#630453#8058. Binary vs TernaryRilllo#WA 2ms5872kbC++233.9kb2024-10-11 18:39:252024-10-11 18:39:25

Judging History

你现在查看的是最新测评结果

  • [2024-10-11 18:39:25]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:5872kb
  • [2024-10-11 18:39:25]
  • 提交

answer

#include<bits/stdc++.h>
#define int long long int
#define ull unsigned long long
#define pb push_back
#define pii pair<int,int>
#define fi first
#define se second
using namespace std;
const int maxn=1e6+5;
const int inf=1e18;
string a,b;
char sa[maxn],sb[maxn];
char tmp[maxn];
int lena,lenb;
void solve()
{
    cin>>a>>b;
    if(a==b)
    {
        cout<<0<<'\n';
        return;
    }
    bool f1=true,f2=true;
    for(auto j:a)
    {
        if(j=='1')
        {
            f1=false;
        }
    }
    for(auto j:b)
    {
        if(j=='1')
        {
            f2=false;
        }
    }
    if((f1!=f2)||(f1&&f2))
    {
        cout<<-1<<'\n';return;
    }
    lena=a.size();lenb=b.size();
    for(int i=1;i<=lena;i++)
        sa[i]=a[i-1];
    for(int i=1;i<=lenb;i++)
        sb[i]=b[i-1];
    vector<pii>ans;
    int pos=0;
    for(int i=1;i<=lenb;i++)
    {
        if(sb[i]=='1')
        {
            pos=i-1;break;
        }
    }
    if(pos>=lena)
    {
        cout<<-1<<'\n';return;
    }
    for(int i=1;i<=pos;i++)
    {
        if(sa[i]=='1')
        {
            cout<<-1<<'\n';return;
        }
    }
    int pos2=pos;
    for(int i=pos+1;i<=lena;i++)
    {
        if(sa[i]=='1')
        {
            pos2=i-1;break;
        }
    }
    if(pos2>=pos+1)
    {
        ans.pb({pos+1,pos2});
        int len=pos2-pos;
        for(int i=pos+1;i+len<=lena;i++)
        {
            sa[i]=sa[i+len];
        }
        lena-=len;
    }
    // for(int i=1;i<=lena;i++)
    // {
    //     cout<<sa[i];
    // }
    // cout<<'\n';
    // for(int i=1;i<=lenb;i++)
    // {
    //     cout<<sb[i];
    // }
    // cout<<'\n';
    // cout<<pos<<'\n';
    for(int i=pos+1;i<lena;i++)
    {
        if(sa[i]=='1'&&sa[i+1]=='0')
        {
            sa[i+1]='1';
            ans.pb({i,i+1});
        }
    }
    if(lena!=lenb&&lena-pos==1)
    {
        cout<<-1<<'\n';return;
    }
    while(lena<lenb)
    {
        ans.pb({lena-1,lena});
        ans.pb({lena-1,lena});lena++;
        ans.pb({lena-1,lena});sa[lena]='1';
    }
    vector<int>tmpa,tmpb;
    for(int i=pos+1;i<=lena;i++)
        tmpa.pb(sa[i]-'0');
    for(int i=pos+1;i<=lenb;i++)
        tmpb.pb(sb[i]-'0');
    // for(auto j:tmpa)cout<<j;
    // cout<<'\n';
    // for(auto j:tmpb)cout<<j;
    // cout<<'\n';
    while(!tmpb.empty())
    {
        if(tmpb.back()==tmpa.back())
        {
            tmpa.pop_back();tmpb.pop_back();continue;
        }
        else if(tmpa.size()<=1)
        {
            cout<<-1<<'\n';return;
        }
        if(tmpb.back()==0)
        {
            ans.pb({pos+(int)tmpa.size()-1,pos+(int)tmpa.size()});
            tmpa.pop_back();
            tmpa.pb(0);
            tmpb.pop_back();
        }
        else if(tmpb.back()==1)
        {
            ans.pb({pos+(int)tmpa.size()-1,pos+(int)tmpa.size()});
            tmpa.pop_back();
            tmpb.pop_back();
        }
    }
    while(!tmpa.empty())
    {
        if(tmpa.back()==0)
        {
            ans.pb({pos+(int)tmpa.size()-1,pos+(int)tmpa.size()});
            tmpa.pop_back();
            continue;
        }
        if(tmpa.size()>=2)
        {
            ans.pb({pos+(int)tmpa.size()-1,pos+(int)tmpa.size()});
            ans.pb({pos+(int)tmpa.size(),pos+(int)tmpa.size()+2});
            tmpa.pop_back();
        }
        else
        {
            ans.pb({pos+(int)tmpa.size(),pos+(int)tmpa.size()+1});
            ans.pb({pos+(int)tmpa.size()+1,pos+(int)tmpa.size()+3});
            tmpa.pop_back();
        }
    }
    cout<<ans.size()<<'\n';
    for(auto j:ans)
    {
        cout<<j.fi<<' '<<j.se<<'\n';
    }
}
signed main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr); cout.tie(nullptr);
    cout<<fixed<<setprecision(10);
    int T=1;
    cin>>T;
    for(int i=1;i<=T;i++)
    solve();
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3628kb

input:

3
1
111
110110
1101010
1111
111111

output:

-1
17
2 3
5 6
5 6
5 6
6 7
6 7
6 7
5 6
5 6
4 5
4 5
2 3
3 5
1 2
2 4
1 2
2 4
6
3 4
3 4
4 5
4 5
4 5
5 6

result:

ok Haitang Suki (3 test cases)

Test #2:

score: -100
Wrong Answer
time: 2ms
memory: 5872kb

input:

1000
11100
111
1
11110
10001
10
1011
1111
10
1110
1100
11
11010
11
110
11
1
10001
10110
10
10
11111
10000
1001
10
1
11
10111
11
10
1
100
11
10100
1
10
101
11
1100
110
11
1110
1
1001
1
11111
10
10010
10
11001
110
1010
10011
1110
10100
1001
1001
101
100
1
1001
11
101
11
101
1001
1
1
1011
1
10
10
1011
...

output:

6
3 4
4 5
1 2
2 4
1 2
2 4
-1
13
1 2
2 3
3 4
4 5
4 5
3 4
4 6
2 3
3 5
1 2
2 4
1 2
2 4
1
1 2
11
1 2
1 2
1 2
2 3
2 3
2 3
3 4
3 4
3 4
1 2
2 4
6
2 3
3 4
1 2
2 4
1 2
2 4
8
2 3
4 5
2 3
3 5
1 2
2 4
1 2
2 4
3
2 3
1 2
2 4
-1
12
1 2
4 5
4 5
4 5
3 4
4 6
2 3
3 5
1 2
2 4
1 2
2 4
10
1 2
1 2
1 2
2 3
2 3
2 3
3 4
3 4
...

result:

wrong answer (l,r) is invalid (test case 13)