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#626519#7901. Basic Substring StructureMiniLongTL 0ms24024kbC++207.0kb2024-10-10 09:57:012024-10-10 09:57:01

Judging History

你现在查看的是最新测评结果

  • [2024-10-10 09:57:01]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:24024kb
  • [2024-10-10 09:57:01]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
    #ifdef ONLINE_JUDGE
    char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
const int N = 2e5 + 5;
int n, s[N];
namespace SA{
    int m, x[N], y[N], sa[N], rk[N], c[N], ht[N], f[N][25];
    void build(){
        m = n;
        _rep(i, 1, n) c[x[i] = s[i]]++;
        _rep(i, 1, m) c[i] += c[i - 1];
        _req(i, n, 1) sa[c[x[i]]--] = i;
        for(int k = 1; k <= n; k <<= 1){
            int p = 0;
            _rep(i, n - k + 1, n) y[++p] = i;
            _rep(i, 1, n) if(sa[i] > k) y[++p] = sa[i] - k;
            _rep(i, 1, m) c[i] = 0;
            _rep(i, 1, n) c[x[y[i]]]++;
            _rep(i, 1, m) c[i] += c[i - 1];
            _req(i, n, 1) sa[c[x[y[i]]]--] = y[i];
            p = y[sa[1]] = 1;
            _rep(i, 2, n) y[sa[i]] = (x[sa[i]] == x[sa[i - 1]] && x[sa[i] + k] == x[sa[i - 1] + k]) ? p : ++p;
            swap(x, y);
            if(p >= n) break;
            m = n;
        }
        _rep(i, 1, n) rk[sa[i]] = i;
        int k = 0; ht[1] = 0;
        _rep(i, 1, n){
            if(rk[i] == 1) continue;
            if(k) --k;
            while(s[i + k] == s[sa[rk[i] - 1] + k]) ++k;
            ht[rk[i]] = k;
        }
        _rep(i, 1, n) f[i][0] = ht[i];
        _rep(i, 1, 20) _rep(j, 1, n - (1 << i) + 1) f[j][i] = min(f[j][i - 1], f[j + (1 << i - 1)][i - 1]);
    }
    int lcp(int x, int y){
        if(x > n || y > n || x < 1 || y < 1) return 0;
        if(x == y) return n - x + 1;
        x = rk[x], y = rk[y]; if(x > y) swap(x, y); x++;
        int k = __lg(y - x + 1);
        return min(f[x][k], f[y - (1 << k) + 1][k]);
    }
    void clr(){
        _rep(i, 0, n + 1) x[i] = y[i] = sa[i] = rk[i] = c[i] = ht[i] = 0, mst(f[i], 0);
        m = 0;
    }
}
using SA::lcp;
ll ans, z[N], r[N], f[N], g[N], nxt[N], res[N];
vector<int> h[N];
int lcp(int x, int y, int p, int c){
    int lst = s[p]; s[p] = c;
    int cur = min(lcp(x, y), p - x);
    if(cur < p - x || s[y + cur] != s[x + cur]) return s[p] = lst, cur;
    cur += lcp(x + cur + 1, y + cur + 1) + 1;
    return s[p] = lst, cur;
}
// int calc(int p, int c){
//     int lst = s[p]; s[p] = c;
//     int tot = 0;
//     _rep(i, 1, n){
//         int cur = 0;
//         _rep(j, 1, n - i + 1){
//             if(s[i + j - 1] != s[j]) break;
//             cur++;
//         }
//         tot += cur;
//     }
//     s[p] = lst;
//     return tot;
// }
ll pre[N], suf[N];
vector<PII> v[N];
void clr(){
    ans = 0;
    _rep(i, 0, n + 1){
        z[i] = r[i] = f[i] = g[i] = nxt[i] = res[i] = s[i] = 0;
        h[i].clear(), pre[i] = suf[i] = 0, v[i].clear();
    }
    SA::clr();
}
int main(){
    multitest(){
        read(n);
        _rep(i, 1, n) read(s[i]);
        SA::build();
        _rep(i, 1, n){
            z[i] = lcp(i, 1), ans += z[i], r[i] = i + z[i] - 1;
            if(z[i] < n - i + 1){
                nxt[i] = s[z[i] + 1];
                f[i] = lcp(z[i] + 2, i + z[i] + 1, r[i] + 1, nxt[i]) + 1;
                if(z[i] < i - 1) g[i] = lcp(z[i] + 2, i + z[i] + 1) + 1;
            }
        }
        /*work 1*/
        vector<int> p;
        _rep(i, 2, n) p.pb(i);
        sort(p.begin(), p.end(), [](int x, int y){return s[x] < s[y];});
        res[1] = n;
        _rep(i, 0, n - 2){
            int j = i; ll tot = lcp(p[i] + 1, 2) + 1;
            while(j < n - 2 && s[p[j + 1]] == s[p[i]]) j++, tot += lcp(p[j] + 1, 2) + 1;
            tot += n;
            if(s[p[i]] != s[1])
                res[1] = max(res[1], tot);
        }
        /*work 2~n*/
        ll sum = 0, cnt = 0;
        _rep(i, 2, n){
            if(r[i] >= i) sum += r[i], cnt++, h[r[i]].pb(i);
            pre[i] = sum - cnt * (i - 1);
            for(auto &j : h[i]) sum -= i, cnt--;
        }
        _rep(i, 1, n) h[i].clear();
        sum = cnt = 0;
        _req(i, n, 2){
            for(auto &j : h[i]) sum += i, cnt++;
            suf[i] = sum - cnt * (i - 1);
            if(z[i] < i) h[z[i]].pb(i);
            if(z[i] >= i) sum += z[i], cnt++;
        }
        _rep(i, 1, n) h[i].clear();
        _rep(i, 2, n){
            v[r[i]].pb({nxt[i], f[i]});
        }
        _req(i, n, 2){
            ll cur = ans;
            cur -= pre[i];
            cur -= suf[i];
            sort(v[i - 1].begin(), v[i - 1].end());
            int len = v[i - 1].size();
            res[i] = max(res[i], cur);
            _rep(j, 0, len - 1){
                int k = j; ll tot = v[i - 1][j].se;
                while(k < len - 1 && v[i - 1][k + 1].fi == v[i - 1][j].fi) k++, tot += v[i - 1][k].se;
                if(v[i - 1][j].fi != s[i])
                    res[i] = max(res[i], cur + tot);
                j = k;
            }
            if(z[i] < i - 1 && i + z[i] <= n) v[z[i]].pb({s[i + z[i]], g[i]});
        }
        ll t = 0;
        _rep(i, 1, n){
            t += (res[i] ^ i);
        }
        writeln(t);
        clr();
    }    
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 24024kb

input:

2
4
2 1 1 2
12
1 1 4 5 1 4 1 9 1 9 8 10

output:

15
217

result:

ok 2 lines

Test #2:

score: -100
Time Limit Exceeded

input:

10000
8
2 1 2 1 1 1 2 2
9
2 2 1 2 1 2 1 2 1
15
2 1 2 1 1 1 1 2 2 1 2 1 2 2 1
2
1 1
10
2 1 1 1 2 2 1 1 2 2
3
2 1 2
11
1 2 2 1 1 2 1 2 2 1 1
14
2 1 1 1 1 2 1 1 1 2 2 1 2 1
12
2 2 2 1 2 2 2 1 1 2 1 2
4
2 1 1 2
8
1 2 2 2 1 2 1 1
8
1 1 2 1 2 1 1 1
6
2 1 1 1 2 2
14
2 2 1 1 1 1 2 2 2 1 2 2 1 1
10
1 2 2 1 1...

output:

94
128
347
3
211
9
265
363
278
15
95
114
58
348
225
3
335
364
377
316
3
19
122
66
15
83
36
258
11
63
28
90
85
103
252
191
21
48
303
63
102
20
24
68
316
362
266
309
355
281
326
281
231
312
3
330
54
328
3
69
32
147
322
39
338
90
242
3
165
346
245
20
155
3
404
393
392
81
269
360
20
54
21
279
3
17
351
3...

result: