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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#625323#7897. Largest DigitMiniLongAC ✓1ms3692kbC++202.6kb2024-10-09 18:39:412024-10-09 18:39:41

Judging History

你现在查看的是最新测评结果

  • [2024-10-09 18:39:41]
  • 评测
  • 测评结果:AC
  • 用时:1ms
  • 内存:3692kb
  • [2024-10-09 18:39:41]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
    #ifdef ONLINE_JUDGE
    char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
int l1, r1, l2, r2;
int main(){
    multitest(){
        read(l1, r1, l2, r2);
        if(r1 - l1 > 10 || r2 - l2 > 10){
            puts("9");
        }else{
            int ans = 0;
            _rep(i, l1, r1) _rep(j, l2, r2){
                int x = i + j;
                while(x) ans = max(ans, x % 10), x /= 10;
            }
            writeln(ans);
        }
    }
    return 0;
}

这程序好像有点Bug,我给组数据试试?

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3692kb

input:

2
178 182 83 85
2 5 3 6

output:

7
9

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 3656kb

input:

1000
158260522 877914575 24979445 602436426
1 5 1101111 1101112
2 5 33333 33335
1 5 10111 10111
138996221 797829355 353195922 501899080
212 215 10302 10302
101100 101101 1 2
111 114 1101000 1101001
265804420 569328197 234828607 807497925
1110110 1110112 11100 11103
323 327 23 27
1 1 1 5
316412581 80...

output:

9
7
9
6
9
7
3
5
9
5
9
6
9
9
9
9
9
9
9
9
9
5
9
6
9
9
7
8
9
9
9
9
9
9
3
8
9
7
7
9
9
6
7
9
9
8
9
6
9
9
9
5
9
4
9
5
9
7
8
8
9
9
9
6
9
8
9
5
9
7
9
7
9
9
6
5
9
2
3
6
9
9
8
6
9
9
6
4
9
9
9
9
9
9
8
2
9
4
5
9
9
9
8
6
9
5
7
9
9
9
9
5
9
7
8
5
9
9
9
7
9
9
3
3
9
9
5
7
9
9
6
6
9
7
7
9
9
8
9
9
9
5
9
6
9
7
9
4
9
5
...

result:

ok 1000 lines

Extra Test:

score: 0
Extra Test Passed