QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#62096 | #4496. Shinobu Loves Segment Tree | qinjianbin | AC ✓ | 44ms | 3720kb | C++ | 4.8kb | 2022-11-17 10:01:42 | 2022-11-17 10:01:43 |
Judging History
answer
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<algorithm>
#include<cctype>
#include<ctime>
#include<queue>
#include<stack>
#include<deque>
#include<map>
#include<unordered_map>
#include<set>
#include<unordered_set>
#include<bitset>
#include<functional>
using namespace std;
//STL库常用(vector, map, set, pair)
#define pii pair<int,int>
#define pdd pair<double,double>
#define F first
#define S second
//常量
#define PI (acos(-1.0))
#define INF 0x3f3f3f3f
//必加
#ifdef TanJI
#include<cassert>
#define dbg(...) do {cerr << #__VA_ARGS__ << " -> "; err(__VA_ARGS__); } while(0)
void err() {cerr << endl;}
template<template<typename...> class T, typename t, typename... A> void err(T<t> a, A... x) {for (auto v: a) cerr << v << ' '; cerr << ", "; err(x...);}
template<typename T, typename... A> void err(T a, A... x) {cerr << a << ' '; err(x...);}
template<typename T> void err(T *a, int len) {for (int i = 0; i < len; i++) cerr << a[i] << ' '; err();}
#else
#define dbg(...)
#define assert(...)
#endif
typedef unsigned long long ull;
typedef long long ll;
typedef double db;
// 快读快输
template<typename T> inline T read() {T x=0; bool f=0; char c=getchar();while(!isdigit(c)){if(c =='-')f= 1; c=getchar();}while(isdigit(c)){x=(x<<3)+(x<<1)+(c^48);c=getchar();}return f?~x+1:x;}
template<typename T> inline void print(T k){ int num = 0,ch[20]; if(k == 0){ putchar('0'); return ; } (k<0)&&(putchar('-'),k = -k); while(k>0) ch[++num] = k%10, k /= 10; while(num) putchar(ch[num--]+48); }
//图论
const int GRAPHN = 1, GRAPHM = 1;
int h[GRAPHN], e[GRAPHM], ne[GRAPHM], wei[GRAPHM], idx;
void AddEdge(int a, int b) {e[idx] = b, ne[idx] = h[a], h[a] = idx++;}
void AddEdge(int a, int b, int c) {e[idx] = b, ne[idx] = h[a], wei[idx] = c, h[a] = idx++;}
void AddEdge(int h[], int a, int b) {e[idx] = b, ne[idx] = h[a], h[a] = idx++;}
void AddEdge(int h[], int a, int b, int c) {e[idx] = b, ne[idx] = h[a], wei[idx] = c, h[a] = idx++;}
// 数学公式
template<typename T> inline T gcd(T a, T b){ return b==0 ? a : gcd(b,a%b); }
template<typename T> inline T lowbit(T x){ return x&(-x); }
template<typename T> inline bool mishu(T x){ return x>0?(x&(x-1))==0:false; }
template<typename T1,typename T2, typename T3> inline ll q_mul(T1 a,T2 b,T3 p){ ll w = 0; while(b){ if(b&1) w = (w+a)%p; b>>=1; a = (a+a)%p; } return w; }
template<typename T,typename T2> inline ll f_mul(T a,T b,T2 p){ return (a*b - (ll)((long double)a/p*b)*p+p)%p; }
template<typename T1,typename T2, typename T3> inline ll q_pow(T1 a,T2 b,T3 p){ ll w = 1; while(b){ if(b&1) w = (w*a)%p; b>>=1; a = (a*a)%p;} return w; }
template<typename T1,typename T2, typename T3> inline ll s_pow(T1 a,T2 b,T3 p){ ll w = 1; while(b){ if(b&1) w = q_mul(w,a,p); b>>=1; a = q_mul(a,a,p);} return w; }
template<typename T> inline ll ex_gcd(T a, T b, T& x, T& y){ if(b == 0){ x = 1, y = 0; return (ll)a; } ll r = ex_gcd(b,a%b,y,x); y -= a/b*x; return r;/*gcd*/ }
template<typename T1,typename T2> inline ll com(T1 m, T2 n) { int k = 1;ll ans = 1; while(k <= n){ ans=((m-k+1)*ans)/k;k++;} return ans; }
template<typename T> inline bool isprime(T n){ if(n <= 3) return n>1; if(n%6 != 1 && n%6 != 5) return 0; T n_s = floor(sqrt((db)(n))); for(int i = 5; i <= n_s; i += 6){ if(n%i == 0 || n%(i+2) == 0) return 0; } return 1; }
/* ----------------------------------------------------------------------------------------------------------------------------------------------------------------- */
const int MAXN = 1e5 + 10;
int T;
ll n, x;
ll solve() {
scanf("%lld%lld", &n, &x);
ll lim = 1;
ll cnt = 0;
if (x == 1) {
lim = 1;
}
else {
lim = 2;
ll xx = x >> 1;
cnt++;
while (xx != 1) {
if (xx & 1) lim = lim * 2;
else lim = lim * 2 - 1;
xx >>= 1;
cnt++;
}
}
cnt = 1 << cnt;
ll siz = n - lim + 1;
if (siz <= 0) return 0;
ll ans = 0, ned1 = 0;
if (x & 1)
ned1 = cnt;
else ned1 = cnt >> 1;
dbg(siz, ned1);
if (siz < ned1) return siz;
else {
ans = ned1;
siz -= ned1;
ll num = siz / cnt;
ans += (num + 3) * num * cnt / 2;
siz = siz % cnt;
dbg(num, cnt, siz, ans);
ans += siz * (num + 2);
return ans;
}
}
int main() {
#ifdef TanJI
clock_t c1 = clock();
freopen("D:\\Cpp\\1.in", "r", stdin);
freopen("D:\\Cpp\\1.out", "w", stdout);
#endif
//--------------------------------------------
scanf("%d", &T);
while (T--) {
printf("%lld\n", solve());
}
//--------------------------------------------
#ifdef TanJI
cerr << "Time Used:" << clock() - c1 << "ms" << endl;
#endif
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 44ms
memory: 3720kb
input:
100000 249 707 360 1429 151 380 118 103 221 711 88 79 471 1668 222 377 481 676 483 921 326 558 347 1151 104 220 91 97 258 250 446 122 368 1335 242 335 395 470 180 669 99 222 342 979 345 431 119 97 283 781 325 643 488 1413 285 868 205 723 118 115 397 526 432 1557 197 761 145 287 304 270 331 243 98 36...
output:
0 0 0 61 0 28 0 64 151 176 0 0 11 58 230 1585 0 0 192 0 0 0 100 108 0 0 0 0 0 70 0 0 0 0 64 328 0 808 390 0 0 0 35 0 63 128 405 0 0 52 0 0 146 0 48 662 0 0 0 0 72 6757 0 15 63 150 30 6 66 0 0 236 0 459 100 0 63 0 0 105 0 81 34 0 0 208 0 0 2484 0 63 71 198 89 172 83 19 160 0 237 0 0 0 28 423 32 0 220...
result:
ok 100000 lines