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#603017#9242. An Easy Geometry Problemxi_xiWA 2ms9776kbC++144.3kb2024-10-01 14:11:242024-10-01 14:11:25

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你现在查看的是最新测评结果

  • [2024-10-01 14:11:25]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:9776kb
  • [2024-10-01 14:11:24]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
#define ull unsigned long long
#define int long long
using namespace std;

const int maxn = 2e5 + 5;
const int base = 131313131;
const int mod = 998244353;
int n, q, k, b, a[maxn];
int pw[maxn], sum[maxn], ans[maxn];
struct node{
	struct nd{
		int l, r, laz;
		int sum;
	}tree[maxn << 2];
	void pushup(int p){
		tree[p].sum = (tree[p << 1].sum + tree[p << 1 | 1].sum) % mod; 
	}
	void build(int p, int l, int r){
		tree[p].l = l;tree[p].r = r;
		if(l == r){
			tree[p].sum = (a[l] * pw[l - 1]) % mod;
			return;
		}
		int mid = l + r >> 1;
		build(p << 1, l, mid);
		build(p << 1 | 1, mid + 1, r);
		pushup(p);
	}
	int len(int p){return tree[p].r - tree[p].l + 1;}
	void add(int p, int x){
		tree[p].laz += x;
		tree[p].sum += sum[len(p)] * pw[tree[p].l - 1] % mod * x % mod;
	}
	void pushdown(int p){
		int laz = tree[p].laz;
		if(laz){
			add(p << 1, laz);
			add(p << 1 | 1, laz);
			tree[p].laz = 0;
		}
	}
	void update(int p, int l, int r, int x){
		if(l <= tree[p].l && tree[p].r <= r){
			add(p, x);
			return;
		}
		pushdown(p);
		int mid = tree[p].l + tree[p].r >> 1;
		if(l <= mid) update(p << 1, l, r, x);
		if(mid < r) update(p << 1 | 1, l, r, x);
		pushup(p);
	}
	int query(int p, int l, int r){
		if(l <= tree[p].l && tree[p].r <= r) return tree[p].sum;
		int mid = tree[p].l + tree[p].r >> 1;
		int sum = 0;
		if(l <= mid) (sum += query(p << 1, l, r)) %= mod;
		if(mid < r) (sum += query(p << 1 | 1, l, r)) %= mod;
		return sum; 
	}
}T1;

struct node1{
	struct nd{
		int l, r, laz;
		int sum;
	}tree[maxn << 2];
	void pushup(int p){
		tree[p].sum = (tree[p << 1].sum + tree[p << 1 | 1].sum) % mod; 
	}
	void build(int p, int l, int r){
		tree[p].l = l;tree[p].r = r;
		if(l == r){
			tree[p].sum = a[l] * pw[n - l] % mod;
			return;
		}
		int mid = l + r >> 1;
		build(p << 1, l, mid);
		build(p << 1 | 1, mid + 1, r);
		pushup(p);
	}
	int len(int p){return tree[p].r - tree[p].l + 1;}
	void add(int p, int x){
		tree[p].laz += x;
		tree[p].sum += sum[len(p)] * pw[n - tree[p].r] % mod * x % mod;
	}
	void pushdown(int p){
		int laz = tree[p].laz;
		if(laz){
			add(p << 1, laz);
			add(p << 1 | 1, laz);
			tree[p].laz = 0;
		}
	}
	void update(int p, int l, int r, int x){
		if(l <= tree[p].l && tree[p].r <= r){
			add(p, x);
			return;
		}
		pushdown(p);
		int mid = tree[p].l + tree[p].r >> 1;
		if(l <= mid) update(p << 1, l, r, x);
		if(mid < r) update(p << 1 | 1, l, r, x);
		pushup(p);
	}
	int query(int p, int l, int r){
		if(l <= tree[p].l && tree[p].r <= r) return tree[p].sum;
		int mid = tree[p].l + tree[p].r >> 1;
		int sum = 0;
		if(l <= mid) (sum += query(p << 1, l, r)) %= mod;
		if(mid < r) (sum += query(p << 1 | 1, l, r)) %= mod;
		return sum; 
	}
}T2;

bool check(int i, int mid){
	int l = i - mid, r = i + mid;
	int x = T1.query(1, i + 1, r) * pw[n - i] % mod;
	int y = T2.query(1, l, i - 1) * pw[i] % mod;
//	cout << T1.query(1, i + 1, r) << " " << T2.query(1, l, i - 1) << " ";
//	cout << x - y << '\n';
//	cout << ans[mid] * pw[i] * pw[n - i + 1] << " ";
	return (x - y + mod) % mod == (ans[mid] % mod + mod) % mod * pw[i] % mod * pw[n - i] % mod;
}

signed main(){
    ios::sync_with_stdio(false);
    cout.tie(0);
    cin.tie(0);
	
	cin >> n >> q >> k >> b;
	for(int i = 1; i <= n; i++) cin >> a[i], a[i] = (a[i] % mod + mod) % mod;
	pw[0] = 1;for(int i = 1; i <= n; i++) pw[i] = pw[i - 1] * base % mod;
	for(int i = 1; i <= n; i++) sum[i] = (sum[i - 1] + pw[i - 1]) % mod;
	T1.build(1, 1, n);T2.build(1, 1, n);
	for(int i = 1; i <= n; i++) ans[i] = (ans[i - 1] + pw[i - 1] * ((k * i + b) % mod + mod) % mod) % mod;
	while(q--){
		int op;cin >> op;
		if(op == 1){
			int l, r, v;cin >> l >> r >> v;
			v = v % mod + mod;
			v %= mod;
			T1.update(1, l, r, v);
			T2.update(1, l, r, v);
		}else{
			int i;cin >> i;
			int l = 0, r = min(n - i, i - 1), ans = 0;
			while(l <= r){
				int mid = l + r >> 1;
				if(check(i, mid)) ans = mid, l = mid + 1;
				else r = mid - 1;
			}
			cout << ans << '\n';
		}
	}
//	for(int i = 1; i <= n; i++) cout << T1.query(1, i, i) << " ";cout << '\n';
	
    return 0;
}
/*
6 2 6 2
1 5 9 13 15 18
2 3

6 6 6 2
1 5 9 10 15 18
2 2
1 3 3 -3
2 2
1 3 4 3
2 3
2 4
*/

详细

Test #1:

score: 0
Wrong Answer
time: 2ms
memory: 9776kb

input:

6 6 6 2
1 5 9 10 15 18
2 2
1 3 3 -3
2 2
1 3 4 3
2 3
2 4

output:

0
0
0
0

result:

wrong answer 1st numbers differ - expected: '1', found: '0'